Understanding Voltage Drop: Calculating Dropped Volts With Easy Math/Numbers ⚡ Cars Simplified
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- Опубликовано: 11 июн 2024
- Voltage drop is an important concept to understand when you start to diagnose automotive electrical issues. A lot of what you'll be working with will have one load per circuit, so one component tends to have about 99% voltage drop, but if there is damage to the wiring causing resistance elsewhere, what would that look like? This video covers the math of voltage drop using easy-to-work-with numbers so that the concepts will be focused on.
In upcoming lessons, we will move away from the whiteboard and do some real world voltage drop testing.
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What electrical concept would you like to see covered next?
How a parasitic draw affects a circuit
understanding how to recognize DC series and parallel circuits applied to auto circuits
Well done, so I just subscribed!
I just stumbled across your videos, and now subscribe. Thanks for doing them.
Thanks, I appreciate it!
Nice job. Very helpful.
Thanks!
Dr Science, thanks again!
Thanks!
Cool video. Maybe cover why different gauge wire matters in a car and how much.
Good idea, and thanks!
I have shared your video on an electronics testing site. The link anyhow. It may help students clear up questions the video produced for the site left for students.
Very nice video, great explanation and a nice speed!
But I do have a question though, will the the current always remain constant throughout a circuit? Or will it possibly change, and therefore affect the ratio of each Ohm's effect on the voltage drop?
The only time amperage can change on a circuit is when it splits into a parallel circuit, and even then, the parallel branches all add up to the same amount you would see where the branches are all joined together again.
In a series wired cct amperage is constant throughout and volt drops at every load .
In a parallel cct voltage is constant throughout and amperage changes with every load.
Most cct’s are wired in parallel but vehicles might be different I don’t know .
I thought that in order for voltage drop to occur, there needed to be a load applied to the circuit, not just resistance.?
Ok, my question is this. According to what I know about electricity, it would always return to it's source. How can it do this if it has zero volts on the last leg of this circuit?
I have a question
After all the votls are used up is there 0 volts left on the rest of the circuit
And if we connect the volt metre after the last resistor and just before the negative end of the battery will it read 0 volts
On paper/in theory, yes. In practice, there is usually a little bit of measured voltage because of the slight resistance in the wire across a long enough distance. That amount should be quite small, though.
how is it 0V instead of 1V? 6/6 is 1 not 0
The voltage meets 2 ohms and goes to 0. Why not 2 volts as before it went from 12 to 8?
I still dont understand all I see is numbers with not rhyme or reason WHY IS THE VOLT DROP 6 TELL ME WHY
clear as mud!
WHY IS THE RESITACE TWO AMPS