Very nice video, great explanation and a nice speed! But I do have a question though, will the the current always remain constant throughout a circuit? Or will it possibly change, and therefore affect the ratio of each Ohm's effect on the voltage drop?
The only time amperage can change on a circuit is when it splits into a parallel circuit, and even then, the parallel branches all add up to the same amount you would see where the branches are all joined together again.
In a series wired cct amperage is constant throughout and volt drops at every load . In a parallel cct voltage is constant throughout and amperage changes with every load. Most cct’s are wired in parallel but vehicles might be different I don’t know .
I have shared your video on an electronics testing site. The link anyhow. It may help students clear up questions the video produced for the site left for students.
I have a question After all the votls are used up is there 0 volts left on the rest of the circuit And if we connect the volt metre after the last resistor and just before the negative end of the battery will it read 0 volts
On paper/in theory, yes. In practice, there is usually a little bit of measured voltage because of the slight resistance in the wire across a long enough distance. That amount should be quite small, though.
Ok, my question is this. According to what I know about electricity, it would always return to it's source. How can it do this if it has zero volts on the last leg of this circuit?
What is the voltage drop between your two resistors. In other words place your first lead after the first resistor and your second lead before the second resistor. If you measure 12 Volts, your lesson is incomplete and you have left your students with more questions then answers. You need to update this video.
![Voltage Drop Testing With A Test Light? [Part 2]](/img/1.gif)
What electrical concept would you like to see covered next?
How a parasitic draw affects a circuit
understanding how to recognize DC series and parallel circuits applied to auto circuits
I just stumbled across your videos, and now subscribe. Thanks for doing them.
Thanks, I appreciate it!
Well done, so I just subscribed!
Nice job. Very helpful.
Thanks!
Dr Science, thanks again!
Thanks!
Cool video. Maybe cover why different gauge wire matters in a car and how much.
Good idea, and thanks!
Very nice video, great explanation and a nice speed!
But I do have a question though, will the the current always remain constant throughout a circuit? Or will it possibly change, and therefore affect the ratio of each Ohm's effect on the voltage drop?
The only time amperage can change on a circuit is when it splits into a parallel circuit, and even then, the parallel branches all add up to the same amount you would see where the branches are all joined together again.
In a series wired cct amperage is constant throughout and volt drops at every load .
In a parallel cct voltage is constant throughout and amperage changes with every load.
Most cct’s are wired in parallel but vehicles might be different I don’t know .
I have shared your video on an electronics testing site. The link anyhow. It may help students clear up questions the video produced for the site left for students.
I still dont understand all I see is numbers with not rhyme or reason WHY IS THE VOLT DROP 6 TELL ME WHY
6ohm × 1amp = 6v
clear as mud!
I have a question
After all the votls are used up is there 0 volts left on the rest of the circuit
And if we connect the volt metre after the last resistor and just before the negative end of the battery will it read 0 volts
On paper/in theory, yes. In practice, there is usually a little bit of measured voltage because of the slight resistance in the wire across a long enough distance. That amount should be quite small, though.
I thought that in order for voltage drop to occur, there needed to be a load applied to the circuit, not just resistance.?
Ok, my question is this. According to what I know about electricity, it would always return to it's source. How can it do this if it has zero volts on the last leg of this circuit?
how is it 0V instead of 1V? 6/6 is 1 not 0
The voltage meets 2 ohms and goes to 0. Why not 2 volts as before it went from 12 to 8?
What is the voltage drop between your two resistors. In other words place your first lead after the first resistor and your second lead before the second resistor. If you measure 12 Volts, your lesson is incomplete and you have left your students with more questions then answers. You need to update this video.
It same potential so it 0v? Why 12v?
Where is the earth connection
WHY IS THE RESITACE TWO AMPS
12v / (4ohm + 2ohm) = 2amp
Ohm's Law is equation so it can flip left or right side to get the unknown value