CONJUGATE BEAM METHOD FOR SLOPE & DEFLECTION - SIMPLY SUPPORTED BEAM WITH UDL & POINT LOADS

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  • Опубликовано: 22 дек 2024

Комментарии • 9

  • @pvt765
    @pvt765 Год назад +2

    In second triangle...???
    Why you take cg distance 1/3×2....it is 2/3×2 hoga....???

    • @KHENISIR
      @KHENISIR  Год назад +1

      Dear Friend.....
      As per rules the CG distance for traingle from apex is 2/3 and its 1/3 of distance from side......
      If you go through this, you will get 1/3 of distance for 2nd traingle...

  • @capone9905
    @capone9905 Год назад +1

    Can you explain 10:53 for me please?

    • @KHENISIR
      @KHENISIR  Год назад

      Sure...as per the definition of Shear Force, person can assume either left or right side of section for unbalanced Vertical Force....
      During calculation at 10:53, if left side is assumed than vertical upward reaction than downward trapezoidal as well as UVL is taken for account and calculation is time consuming
      So as per the definition, at that location, right side section is assumed so that only the vertical reaction at B as unbalanced force and acc to sign convention, right side upward force is assumed as Negative
      Hope so your query is now resolved

    • @capone9905
      @capone9905 Год назад +1

      Can you please break it down further

    • @KHENISIR
      @KHENISIR  Год назад

      Sure... It depends that either person have to consider the left side or right side as per definition
      If you calculate the left side unbalanced loads then you will get the same value as the right side
      .. just we have to take care about sign conventions

    • @goat8326
      @goat8326 Год назад

      udl Curve cg 3/Length * base

  • @Amityadav-wj1im
    @Amityadav-wj1im Год назад +1

    Thanks sir nice explanation. ❤