Thanks for this amazing stuff. Never was very good at math in my young years, but since I started to figure out and use slide rules, math became much more ‘logical’ and interesting!
Just got my Pickett N4-ES in the mail yesterday. Gave it a good (mild) cleaning and lubricated it with dry teflon . SMOOTH! I haven't had a slide rule in my hands for 50 years. This will be fun learning again. When I was in college, I'm afraid I only learned the minimum in order to make it through my chemistry and physics courses. Looking forward to some self-learning of pre-calculus and trig. Keep up the great work!
Thanks for reminding me of the good times with my slide rule in engineering school. Use of the slide rule engaged you in the problem solution more so than use of computers, something we've lost along the way. And, it's nice to hear from a real science guy instead of that fraud with a similar name.
@@sliderulesandmathematics9232 None at this time. I just wished more people took interest in one. My father showed me how to use the basics of one years ago and I truly believe it made me better at math. I try and use it all the time since I am fascinated with it. Keep the videos coming so I can learn even more.
Thank you for another great video with a practical application for slide rules! You’re right, vector calculations are much easier and faster with a slide rule than a digital calculator! I have one question: What type of fountain pen do you use in your videos?
May I remind a trick I already mentioned here, allowing to calculate the norm (or length) of a vector, which is the square root of the sum of the squares of its coordinates. Here in the 2D space, that would be the square root of x^2 + y^2. - Align the value of y^2 on the mobile B scale under the fixed 10 of scale A - Read the value m on fixed A scale, in front of x^2 on mobile B scale. - Mentally compute 10 + m, and align the cursor on fixed A scale at the result position. - On that alignment, you can read the sum x^2+y^2 on scale B and its square root on scale C.
I first thought it was a clever approximation, but it is not, it is just maths : Given a setup of the mobile scale, all the readings have the same ratio. Once you align 2 and 1, you have all the results you want 2x2 or 2x3 or 2x1.5. So here we have a 10/y^2 = m/x^2, and if the maths are correct it should also be equal to (10 + m)/(x^2 + y^2). And it is easy to demonstrate it. We find m = 10 x^2/y^2, so 10 + m = 10 + 10 x^2/y^2 = 10/y^2 * (x^2 + y^2) , let's divide both sides by the sum of squares... (10 + m)/(x^2 + y^2) = 10/y^2 QED
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Thanks for this amazing stuff. Never was very good at math in my young years, but since I started to figure out and use slide rules, math became much more ‘logical’ and interesting!
Great to hear!
Tue
Thanks for another awesome slide rule video.
Just got my Pickett N4-ES in the mail yesterday. Gave it a good (mild) cleaning and lubricated it with dry teflon . SMOOTH! I haven't had a slide rule in my hands for 50 years. This will be fun learning again. When I was in college, I'm afraid I only learned the minimum in order to make it through my chemistry and physics courses. Looking forward to some self-learning of pre-calculus and trig. Keep up the great work!
I have enjoyed it. I have an n4 but prefer the n3 or the aristo studio 0968
yeeaaaa thanks for this videos!! Time to grab my sliderule!!!
Enjoy!
Thanks!
Looking forward to the next practical problem 😁
do you have a request?
@@sliderulesandmathematics9232 Maybe an example for working with complex numbers?
Such as?
Thanks for reminding me of the good times with my slide rule in engineering school. Use of the slide rule engaged you in the problem solution more so than use of computers, something we've lost along the way.
And, it's nice to hear from a real science guy instead of that fraud with a similar name.
Do you have any suggestions for future episodes of ‘practical slide rule’. Any kinds of problems you found well suited to the slip stick?
@Bob --- Love this channel !!!! Been following along with my trusty K&E 4081- 3 Decitrig. Keep the videos coming.
Have any topic requests ?
@@sliderulesandmathematics9232 None at this time. I just wished more people took interest in one. My father showed me how to use the basics of one years ago and I truly believe it made me better at math. I try and use it all the time since I am fascinated with it.
Keep the videos coming so I can learn even more.
I think I’ll look at exponential growth and decay/interest
Thank you for another great video with a practical application for slide rules! You’re right, vector calculations are much easier and faster with a slide rule than a digital calculator!
I have one question: What type of fountain pen do you use in your videos?
Glad it was helpful! That is an Aurora fountain pen
i just want you to know that we're all counting on you - for a good video.
(surely you will, with a title like that.)
it was an awesome title
Have you done your slide rule presentation to the math club students?
yes, it went over very well, but I was very disappointed in the turn out.
How many people attended?
@@charmersify two and the advisor. It wasn't announced until late in the afternoon of the day of the meeting.
May I remind a trick I already mentioned here, allowing to calculate the norm (or length) of a vector, which is the square root of the sum of the squares of its coordinates. Here in the 2D space, that would be the square root of x^2 + y^2.
- Align the value of y^2 on the mobile B scale under the fixed 10 of scale A
- Read the value m on fixed A scale, in front of x^2 on mobile B scale.
- Mentally compute 10 + m, and align the cursor on fixed A scale at the result position.
- On that alignment, you can read the sum x^2+y^2 on scale B and its square root on scale C.
I'll have a look at that in detail.
I first thought it was a clever approximation, but it is not, it is just maths : Given a setup of the mobile scale, all the readings have the same ratio. Once you align 2 and 1, you have all the results you want 2x2 or 2x3 or 2x1.5. So here we have a 10/y^2 = m/x^2, and if the maths are correct it should also be equal to (10 + m)/(x^2 + y^2). And it is easy to demonstrate it.
We find m = 10 x^2/y^2, so 10 + m = 10 + 10 x^2/y^2 = 10/y^2 * (x^2 + y^2) , let's divide both sides by the sum of squares...
(10 + m)/(x^2 + y^2) = 10/y^2 QED
Try double x,x angle,then double y,y angle, sin-1(C/B),cos-1(A/B),cos-1(C/B). Y ,cos-1(A/B),cos-1(C/B),sin-1(C/B). Double angles. John.
Son-1(C/B)+90) john.
roger, Roger!
Do you have the clearance, Clarence
@@sliderulesandmathematics9232 LOL!
.25 a b/c1=1/4 base of one try other bases,4,8,16,32,64 have fun.,