I'm taking Calculus right now and my prof always says the biggest mistakes mathematicians make are not putting an answer as Absolute value, rather than just "X" after being X to the power of 2,4,6, all even numbers that would cancel the potential negative. THanks for teaching it properly !!!!!!
The reason he did this is because in order to cancel out b in the denominator, it has to be the cube root of b^3. If he had multiplied by just b, it would have been the cube root of b^2 which wouldn't have removed the radical from the denominator.
I was really struggling thanks to the fact that my teacher despite being a nice guy even trying couldn't teach worse he might be the worst teacher in the school system however this video helped me still pass my midterms and finals so thanks!
The problem you solve at 4:44 I understood everything up until you simplified at the end by using the cubed squared root of b squared? How did it go from the cubed root of b in the denominator to the cubed root of b squared? Why didn't it just stay the same? Why did it go from b to b squared?
4:29 doesn't the answer have x squared instead of x cubed? I actually tried to follow out each equation and, with each variable set as 2, the original equation gives 54.3, the simplified equation with x squared gives 54.3, and the simplified equation with x cubed gives 108.6. So unless I typed something into the calculator wrong, the answer for 4:29 should have x squared.
I’m assuming the 1 in “1/2” came from the top. So if you look within the radical, the letters don’t have numbers in front of them. Sure they got exponents but they don’t have a number in front. So they all account for 1. The “2” in “1/2” just comes from the bottom of the radical.
As for why he made it the 4th root of 1/2. Thats because we’re dealing with the 4th root. If our radical were cubed then it would be the cubed root of 1/2.
So the reason I think he multiplies it by b squared is because on the bottom where trying to get 'b' to be a regular variable not to the power of anything so we can add it to b^4. So this we have a cube root of 3 with b on the inside, by multiplying that by the cube root of b^2 we will get b^3 and the cube root of b^3 is just b so we can then add that to b^4 and get b^5.
4:39 this might be a dumb dumb question but why did you divide all the exponents on this one and on the other ones you took the exponents on the numerator and the exponents of the demonator seperately?
It depends on equation, as in 4:39 it’s a square root and the exponents are odds so dividing 9, 3, 11 by 2 (because of the square root) is not convenient. So he had to divide first, find pair exponent and then eliminate the square root easier
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I'm taking Calculus right now and my prof always says the biggest mistakes mathematicians make are not putting an answer as Absolute value, rather than just "X" after being X to the power of 2,4,6, all even numbers that would cancel the potential negative. THanks for teaching it properly !!!!!!
"what!? still searching youtube for math help?" I really dislike this ad. it sounded more like an insult.
You got it too? Lol!
It is an insult lel
I am dead bro 😂😂😂😂
I wish I can make it stop appearing!!!!
Ad: “Are the math videos from 2006 really helping?”
More than you are, stop harassing me already 😭
Thank you so much for your help! I was having a hard time with dividing radicals but you came through!
In rationalizing step, 7:55
He multiplied by the cube root of b^(3) to the second power and he had in the denominator the cube root of b
The reason he did this is because in order to cancel out b in the denominator, it has to be the cube root of b^3. If he had multiplied by just b, it would have been the cube root of b^2 which wouldn't have removed the radical from the denominator.
where did he get the ³√b²
hey I know this is a year ago so you may not know anymore but is it that you can’t have a radical i the denominator? @@seltzer1505
I was really struggling thanks to the fact that my teacher despite being a nice guy even trying couldn't teach worse he might be the worst teacher in the school system however this video helped me still pass my midterms and finals so thanks!
So relaxing to follow
Its very helpful! but the variables are confusing sometimes but if you rewatch it you can get it alot better
The problem you solve at 4:44 I understood everything up until you simplified at the end by using the cubed squared root of b squared? How did it go from the cubed root of b in the denominator to the cubed root of b squared? Why didn't it just stay the same? Why did it go from b to b squared?
Because we need it to rationalize to equal b cubed so we make it b² and multiply it to b and then divide b³ by ³ it would equal b outside the radical
There lots of subscribers but there are only few who liked his videos
He does more chemistry than math
@@demosthenes995 I like your pfp lol
Thanks for making my lesson a TLDR, u made a 1 hour lesson to a 12 minutes video, thanks :DD
Thanks bro you really helped me out!!!
4:29 doesn't the answer have x squared instead of x cubed? I actually tried to follow out each equation and, with each variable set as 2, the original equation gives 54.3, the simplified equation with x squared gives 54.3, and the simplified equation with x cubed gives 108.6.
So unless I typed something into the calculator wrong, the answer for 4:29 should have x squared.
7:55 when rationalizing the denominator, why was cube root b^2 and not cube root b.
it should be actually so that you can be able to cancel it its b^1 + b ^2 is b^3 so it becomes 3/b^3 so you can cancel it now and b remains😢😅i luv her
Great lesson.
10:55, how exactly did you get the fourth root of 1/2? Was it from the remainder of the fourth root of 2^5?
I’m assuming the 1 in “1/2” came from the top. So if you look within the radical, the letters don’t have numbers in front of them. Sure they got exponents but they don’t have a number in front. So they all account for 1. The “2” in “1/2” just comes from the bottom of the radical.
As for why he made it the 4th root of 1/2. Thats because we’re dealing with the 4th root. If our radical were cubed then it would be the cubed root of 1/2.
You kinda lost me in the last problem lol
That’s was the 2 all the way to the left, from the part of the equation that was solved out already and was in the denominator.
The last was wrong????
@@ynaramzian8514 I think he means he wasn't able to understand anymore
samee
yea me too, my answer is 3x^2 y^5 z/2. I dont get it the last thing he did😅
Love you teacher. ❤😁
So the reason I think he multiplies it by b squared is because on the bottom where trying to get 'b' to be a regular variable not to the power of anything so we can add it to b^4. So this we have a cube root of 3 with b on the inside, by multiplying that by the cube root of b^2 we will get b^3 and the cube root of b^3 is just b so we can then add that to b^4 and get b^5.
thanks man really helped alot
Bro is clutching my math grade😂😂
In 8:02, why was it multiplied by √b*2?
Should've been just cubed root of b right?
Yeah i'm really confused
i guess it's because it is cubed? i am not sure tho
4:39 this might be a dumb dumb question but why did you divide all the exponents on this one and on the other ones you took the exponents on the numerator and the exponents of the demonator seperately?
They have different variables
YES YOUR RIGHT!
It depends on equation, as in 4:39 it’s a square root and the exponents are odds so dividing 9, 3, 11 by 2 (because of the square root) is not convenient. So he had to divide first, find pair exponent and then eliminate the square root easier
I enjoyed this
at 3:20 where did the absolute signs come from for y^5? I am confused...
Sorry this is really late but I think it was because 5 is an odd number and all odd exponents become absolute, so because y⁵ is odd it is |y⁵|
@@katelynnhenasie4608why was b^3 not in absolute value then? i'm confused now
Why did it get more complex to the point where i didnt even get what i needed outta dis 😭
thank you. you rock
you cant cancle the 25x and 2x because this number is in , inthe radicand sign
Thanks
Are you on the Sopranos?
Magquiz mi sa math unya
hahahha amaw gudlack
makapasar unta ka ampoan tika
A zillion thanks 😍
Nice explanation, but you can factor out 4 even further than that 4 factors out to 2...
mine is 3 radical 5 radical 5 over 3 radical 5 to the fifth
Thanks dude i litterally got nothing my mind went blank from the first word i heard
10:55 how did u get that?
i hate division bruh
Great!
for the last example why isn't x^2 within absolute value?
the index is even, and so is the x^2 (the exponent). That's why it isn't within the absolute value.
@@hanah2561 But isn't the rule that if n=even it will have multiple results and and if n=odd then one result?
"Are videos from 2006 really helping??" Yes. Yes they do.
b is positive 7
so 3√3x/5√3x = 3/5?
Yes
❤
Bro you’re not explaining how we getting the answers
sighs im here
E
AND
His voice is kinda...🤭