You see, some teachers know what they’re doing. My teacher sent our class to this video instead of actually teaching us... Still learned more than usual
I know this video was posted very long ago but I still want to express how grateful I am for this video’s existence. I have a test tomorrow on this concept and I went from not understanding any of this to understanding almost completely! this is a lot more straightforward than how my teacher explained it, so thank you so much for taking time out of your day to explain this! it helped a lot!!!
Thank you so much, my teacher showed me how to do and gave me homework and i had no idea but after this video I know how to do it thanks for this video.
sciencepost what my teacher took 2 weeks to explain, you just did in 14:14 minutes and i completely understand it. Thanks for the help because I got my chemistry final tomorrow.
I missed this day in class! Thanks for the help!! However, I was wondering what happens if your temp and your amount of water don't line up? We are using the same graph you were toward the end of this vid. My chem teacher gave the problem: ...determine how many grams of KClO3 needs to dissilve in 50 grams of water in order to have a saturated solution at 80 degrees C.
KCIO3 needs 10 more grams to have a saturated solution at 80 degrees C. I got this by lining up the compound on the x-axis and y-axis. At 80 degrees C. and 40 grams of solute they meet. However, the question is asking at 50 degrees C. so to get from 40 -> 50 you would set up the equation: 40 + x = 50 Your end result would be x = 10, thus you need 10 more grams of solute.
@sciencepost Is it ok if you explain how in a prac you would test how much of the solid dissolves in the given temperature until the saturation point has been reached. I understand the picture and the graph show a correlation (to make it easier to understand), but they don't directly refer to each other which what makes me confused on how they gathered the data for the graph. And also, that method of seeing how much dissolves in the pictures is a bit dodgy (eg.parralax error.etc)
Okay can someone tell me how you would figure those same problems but only if you didn’t have 100 grams of whatever is being dissolved. I’m my case it’s 79 grams of KNO3 and I have to know of it would be saturated, super saturated, or unsaturated.
Btw, im not sure how legit the graphs are, but is it saying when water is 0 degrees Celsius (frozen into ice), it can still dissolve 175 grams of sugar???
this was a great video. He taught me more in 14 minutes than my teacher does in an hour
NO FRRR
I was so confused at first, but this video made it crystal clear. Like if you agree. Thanks for putting this video up for struggling students
Chrystal clear, is that because crystals are left over🤣
100000000 subscribers without making a video STOP
You see, some teachers know what they’re doing. My teacher sent our class to this video instead of actually teaching us... Still learned more than usual
I know this video was posted very long ago but I still want to express how grateful I am for this video’s existence. I have a test tomorrow on this concept and I went from not understanding any of this to understanding almost completely! this is a lot more straightforward than how my teacher explained it, so thank you so much for taking time out of your day to explain this! it helped a lot!!!
You are my hero. My Chemistry teacher said I should just 'google it' because apparently I'm too 'daft' to understand. So thanks for helping.
Your teacher actually said that 😮
Shocking
I was so stressed because I didn't know how to determine solubility curve but when I watched this video I finally understand the solubility curves.
thannnnkkkk youuuuu i have had sooo much trouble understanding these. this help me 1000000%
YOU PEOPLE SAVE MY LIFE (well academic life)
This video is nice and clear. My chemistry teacher does not teach us anything so I appreciate the video.
Thank you so much! i hope you have a great day and a great life
Thanks a lot! I was finding a bit difficult understanding this, but I get it now because of you! Thanks a lot again, you really helped me! =D
Wow you are an amazing teacher! Thanks!!
you saved my life
Thank you so much, my teacher showed me how to do and gave me homework and i had no idea but after this video I know how to do it thanks for this video.
Vas, thanks for the feedback. Sooooo stoked they are helping you.
This was so helpful (as a teacher!)
THANK YOU!
Glad to help. Tune back in when needed :)
Wow! You just saved me I take my Final today in chemistry and physics! I love your teaching, you are amazing!
I was really struggling with this, but this video really made it click. Thank you!
Thanks, a lot. This video gives a clear understanding of the solubility curve.
eternally grateful for this video.
Very helpful. Thank you for posting this video. I now understand my homework better
this was very helpfull you are able to "dumb down" something that i was unable to get thank you
Thank you. Feel much better for my solutions test tomorrow.
Go big on the test!
Can you please replace my braindead chemistry teacher, PLEASE?!?!?!?!?!?!?!?!?!?
Lol. Von, this is not easy to teach. It may be easier on video, less distractions :) Be awesome!
sciencepost what my teacher took 2 weeks to explain, you just did in 14:14 minutes and i completely understand it. Thanks for the help because I got my chemistry final tomorrow.
Hey bro, go BIG. That means STUDY. I can't stress that enough. Put the time into this Final and you will not regret it. Be awesome! Go Big!
sciencepost Thanks, that just me want you as my chem teacher even more. Wish my teacher said stuff like that.
Lol. Keep rocking the vids bro, and perhaps you'll be the chem teacher one day too. Be awesome bro! I look forward to hearing from you again.
Thank you so much .
You save my GCCEs
My chemistry teacher gave HW on solubility which she hasn't even taught so thanks for saving my chem grade
Very helpful!! You made everything so simple.
That's great to hear. Now it's time to ace your test. Be awesome!
Thank soooo you. You have made me understand things my teacher never could 👏🏾👍🏾
this is SOOOOOOOOOOOOOO easy THANK YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Kym, thanks for tuning in. So happy it helped you. Keep up the the studies.
Very USEFULL THANK YOU SO MUCH!
Thank you so much! This helped a lot!
"So, if you're a fish, and you're swimming around that lake.." Oh wow😂😂
THANKS SO MUCH MY CHEMISTRY TEACHERS A THICK HEAD AND IM ALWAYS ASKING QUESTIONS THXS :)
thanks a lot this video has really benefited me :)
You're awesome. Thank you!
Excellent video. Super helpful bro. Subscribed
your videos are really helpful, and I love how your voice is so chill!
you sound like a total bro
Thanks for the sweet feedback amigo. Not sure if I'm that chill, because I get pretty amped up to teach. Best wishes learning. Keep being awesome!
THANKS MAN!!!!!!!!! You, sir, are AWSOME
Wow, I thought you were Awesomeness! Keep up the sweet effort. Do your best! Be Awesome!
Thanks! I have my exams tomorrow and you explained this very clearly.
Thanks for watching Oneday04. I'm stoked you learned it. Tune back in again if you need help in other areas of chem. Peace..
it all makes sense now. THANK YOU.
this was actually so good
I am not going to fail my Chem test today!!!! :D
Thanks you're a lifesaver!!!
Great video for chemistry students.
If only all teachers were like this..
This video helped me so much. Thank you!!!
Thank you so much for this video. It is so helpful.
thank you so much! i can pass my test now :D
@Celeste Pineda 4years later.. did u pass it
Thank yu sir! Now I can do my homework :D
I missed this day in class! Thanks for the help!! However, I was wondering what happens if your temp and your amount of water don't line up? We are using the same graph you were toward the end of this vid. My chem teacher gave the problem:
...determine how many grams of KClO3 needs to dissilve in 50 grams of water in order to have a saturated solution at 80 degrees C.
KCIO3 needs 10 more grams to have a saturated solution at 80 degrees C. I got this by lining up the compound on the x-axis and y-axis. At 80 degrees C. and 40 grams of solute they meet. However, the question is asking at 50 degrees C. so to get from 40 -> 50 you would set up the equation:
40 + x = 50
Your end result would be x = 10, thus you need 10 more grams of solute.
You seem like such a cool guy that's great at chemistry. Thanks for the video :) much appreciated and needed
Thanks very much it's was very helpful
Very Helpful
thanks for diss video it help mi a lot
Thank you!!!!
thank you so much. I finally understand 😊
U r a life saver
You are welcome dude. Please share it if it helped. Peace out.
thanks a lot you have helped me a lot
Thank you it was very helpful.
Dude i have a quiz on this tmrw and you literally just cleared my brain if you wanna be my chemistry teacher let me know
Thank you now I will share with my students!
Eduardo Miranda Thanks bro. I hope that it helps them. Best wishes.
You are welcome!
i love your vids
Thank you! That helped!
i like how at 4:44 the amounts of solution are different. one is 33ml and one is 35ml.
clear an simple, thanks!
Yeah! So cool to hear that the video worked for you. Be Awesome!
@sciencepost Is it ok if you explain how in a prac you would test how much of the solid dissolves in the given temperature until the saturation point has been reached. I understand the picture and the graph show a correlation (to make it easier to understand), but they don't directly refer to each other which what makes me confused on how they gathered the data for the graph. And also, that method of seeing how much dissolves in the pictures is a bit dodgy (eg.parralax error.etc)
so helpful!! thank you!
So stoked it worked for you! Tune back again.
Thanks! so helpful
Thanks for you're help.
Thank's this really helped
Subtitles would be awesome if you could start putting them on your videos.
Thanks this helped a lot! :)))
So cool to hear. Thanks!
thanks helped alot
I have a test on monday
Sarah aljamal samee
Exam
I have a test in 2 minutes 😂😂
Thank you so much!!!
thank you so much
great vid!!
does a solubility curve of anhydrous solid always necessarily be continuous ?
amazing video thanks alot
why he sound like Patton Sanders-
(not in a bad way of course your voice is great)
Great Video!! =]
Thanks for tuning in and leaving feedback! Keep up the good work!
thanks for help
thank you
Thanks helped on Hw
bro saving my life i get it now😭
lets go ms.Nathan
Okay can someone tell me how you would figure those same problems but only if you didn’t have 100 grams of whatever is being dissolved. I’m my case it’s 79 grams of KNO3 and I have to know of it would be saturated, super saturated, or unsaturated.
Btw, im not sure how legit the graphs are, but is it saying when water is 0 degrees Celsius (frozen into ice), it can still dissolve 175 grams of sugar???
you're awesome
What if you were asked to a solution which is the least saturated at 20 degrees celsius with 20g of solute dissolved in 100g of water
My teachers teach for 5 weeks it doesn't make sense but when I watched 5-15 minute videos it does make sense. Something wrong here?
@11:01 Cerium Sulfate, not Cesium Sulfate.
You didn't do any of the question my grade 11 teacher needs, but i understand a little better now
Well did
Goat
Bruh