You see, some teachers know what they’re doing. My teacher sent our class to this video instead of actually teaching us... Still learned more than usual
I know this video was posted very long ago but I still want to express how grateful I am for this video’s existence. I have a test tomorrow on this concept and I went from not understanding any of this to understanding almost completely! this is a lot more straightforward than how my teacher explained it, so thank you so much for taking time out of your day to explain this! it helped a lot!!!
sciencepost what my teacher took 2 weeks to explain, you just did in 14:14 minutes and i completely understand it. Thanks for the help because I got my chemistry final tomorrow.
Thank you so much, my teacher showed me how to do and gave me homework and i had no idea but after this video I know how to do it thanks for this video.
@sciencepost Is it ok if you explain how in a prac you would test how much of the solid dissolves in the given temperature until the saturation point has been reached. I understand the picture and the graph show a correlation (to make it easier to understand), but they don't directly refer to each other which what makes me confused on how they gathered the data for the graph. And also, that method of seeing how much dissolves in the pictures is a bit dodgy (eg.parralax error.etc)
I missed this day in class! Thanks for the help!! However, I was wondering what happens if your temp and your amount of water don't line up? We are using the same graph you were toward the end of this vid. My chem teacher gave the problem: ...determine how many grams of KClO3 needs to dissilve in 50 grams of water in order to have a saturated solution at 80 degrees C.
KCIO3 needs 10 more grams to have a saturated solution at 80 degrees C. I got this by lining up the compound on the x-axis and y-axis. At 80 degrees C. and 40 grams of solute they meet. However, the question is asking at 50 degrees C. so to get from 40 -> 50 you would set up the equation: 40 + x = 50 Your end result would be x = 10, thus you need 10 more grams of solute.
Okay can someone tell me how you would figure those same problems but only if you didn’t have 100 grams of whatever is being dissolved. I’m my case it’s 79 grams of KNO3 and I have to know of it would be saturated, super saturated, or unsaturated.
this was a great video. He taught me more in 14 minutes than my teacher does in an hour
NO FRRR
I was so confused at first, but this video made it crystal clear. Like if you agree. Thanks for putting this video up for struggling students
Chrystal clear, is that because crystals are left over🤣
100000000 subscribers without making a video STOP
You see, some teachers know what they’re doing. My teacher sent our class to this video instead of actually teaching us... Still learned more than usual
I know this video was posted very long ago but I still want to express how grateful I am for this video’s existence. I have a test tomorrow on this concept and I went from not understanding any of this to understanding almost completely! this is a lot more straightforward than how my teacher explained it, so thank you so much for taking time out of your day to explain this! it helped a lot!!!
You are my hero. My Chemistry teacher said I should just 'google it' because apparently I'm too 'daft' to understand. So thanks for helping.
Your teacher actually said that 😮
Shocking
I was so stressed because I didn't know how to determine solubility curve but when I watched this video I finally understand the solubility curves.
YOU PEOPLE SAVE MY LIFE (well academic life)
Can you please replace my braindead chemistry teacher, PLEASE?!?!?!?!?!?!?!?!?!?
Lol. Von, this is not easy to teach. It may be easier on video, less distractions :) Be awesome!
sciencepost what my teacher took 2 weeks to explain, you just did in 14:14 minutes and i completely understand it. Thanks for the help because I got my chemistry final tomorrow.
Hey bro, go BIG. That means STUDY. I can't stress that enough. Put the time into this Final and you will not regret it. Be awesome! Go Big!
sciencepost Thanks, that just me want you as my chem teacher even more. Wish my teacher said stuff like that.
Lol. Keep rocking the vids bro, and perhaps you'll be the chem teacher one day too. Be awesome bro! I look forward to hearing from you again.
thannnnkkkk youuuuu i have had sooo much trouble understanding these. this help me 1000000%
you saved my life
Thank you so much, my teacher showed me how to do and gave me homework and i had no idea but after this video I know how to do it thanks for this video.
This video is nice and clear. My chemistry teacher does not teach us anything so I appreciate the video.
Kym, thanks for tuning in. So happy it helped you. Keep up the the studies.
Vas, thanks for the feedback. Sooooo stoked they are helping you.
Thank soooo you. You have made me understand things my teacher never could 👏🏾👍🏾
Wow you are an amazing teacher! Thanks!!
this was very helpfull you are able to "dumb down" something that i was unable to get thank you
Thanks a lot! I was finding a bit difficult understanding this, but I get it now because of you! Thanks a lot again, you really helped me! =D
Thank you so much! i hope you have a great day and a great life
Wow! You just saved me I take my Final today in chemistry and physics! I love your teaching, you are amazing!
My chemistry teacher gave HW on solubility which she hasn't even taught so thanks for saving my chem grade
I am not going to fail my Chem test today!!!! :D
This was so helpful (as a teacher!)
THANK YOU!
Glad to help. Tune back in when needed :)
THANKS SO MUCH MY CHEMISTRY TEACHERS A THICK HEAD AND IM ALWAYS ASKING QUESTIONS THXS :)
eternally grateful for this video.
Thank you!!!!
Very USEFULL THANK YOU SO MUCH!
Thanks! I have my exams tomorrow and you explained this very clearly.
Thank you so much .
You save my GCCEs
Thank you. Feel much better for my solutions test tomorrow.
Go big on the test!
Thanks, a lot. This video gives a clear understanding of the solubility curve.
"So, if you're a fish, and you're swimming around that lake.." Oh wow😂😂
Very Helpful
Thanks for watching Oneday04. I'm stoked you learned it. Tune back in again if you need help in other areas of chem. Peace..
Thank you so much! This helped a lot!
You are welcome!
Very helpful!! You made everything so simple.
That's great to hear. Now it's time to ace your test. Be awesome!
If only all teachers were like this..
I was really struggling with this, but this video really made it click. Thank you!
Very helpful. Thank you for posting this video. I now understand my homework better
this is SOOOOOOOOOOOOOO easy THANK YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!
thanks a lot this video has really benefited me :)
Great video for chemistry students.
this was actually so good
You're awesome. Thank you!
it all makes sense now. THANK YOU.
Thank yu sir! Now I can do my homework :D
thanks for diss video it help mi a lot
Thanks you're a lifesaver!!!
U r a life saver
You seem like such a cool guy that's great at chemistry. Thanks for the video :) much appreciated and needed
THANKS MAN!!!!!!!!! You, sir, are AWSOME
Wow, I thought you were Awesomeness! Keep up the sweet effort. Do your best! Be Awesome!
thank you so much! i can pass my test now :D
@Celeste Pineda 4years later.. did u pass it
Thanks very much it's was very helpful
This video helped me so much. Thank you!!!
Excellent video. Super helpful bro. Subscribed
Dude i have a quiz on this tmrw and you literally just cleared my brain if you wanna be my chemistry teacher let me know
i like how at 4:44 the amounts of solution are different. one is 33ml and one is 35ml.
your videos are really helpful, and I love how your voice is so chill!
you sound like a total bro
Thanks for the sweet feedback amigo. Not sure if I'm that chill, because I get pretty amped up to teach. Best wishes learning. Keep being awesome!
Thank you so much for this video. It is so helpful.
Thank you! That helped!
@sciencepost Is it ok if you explain how in a prac you would test how much of the solid dissolves in the given temperature until the saturation point has been reached. I understand the picture and the graph show a correlation (to make it easier to understand), but they don't directly refer to each other which what makes me confused on how they gathered the data for the graph. And also, that method of seeing how much dissolves in the pictures is a bit dodgy (eg.parralax error.etc)
You are welcome dude. Please share it if it helped. Peace out.
I missed this day in class! Thanks for the help!! However, I was wondering what happens if your temp and your amount of water don't line up? We are using the same graph you were toward the end of this vid. My chem teacher gave the problem:
...determine how many grams of KClO3 needs to dissilve in 50 grams of water in order to have a saturated solution at 80 degrees C.
KCIO3 needs 10 more grams to have a saturated solution at 80 degrees C. I got this by lining up the compound on the x-axis and y-axis. At 80 degrees C. and 40 grams of solute they meet. However, the question is asking at 50 degrees C. so to get from 40 -> 50 you would set up the equation:
40 + x = 50
Your end result would be x = 10, thus you need 10 more grams of solute.
does a solubility curve of anhydrous solid always necessarily be continuous ?
thanks a lot you have helped me a lot
I have a test on monday
Sarah aljamal samee
Exam
I have a test in 2 minutes 😂😂
So stoked it worked for you! Tune back again.
thank you so much. I finally understand 😊
Thank you now I will share with my students!
Eduardo Miranda Thanks bro. I hope that it helps them. Best wishes.
Thanks for you're help.
thank you so much
Thanks! so helpful
Thank you it was very helpful.
clear an simple, thanks!
Yeah! So cool to hear that the video worked for you. Be Awesome!
Subtitles would be awesome if you could start putting them on your videos.
so helpful!! thank you!
thanks helped alot
thank you
Thank you so much!!!
Thank's this really helped
thanks for help
Okay can someone tell me how you would figure those same problems but only if you didn’t have 100 grams of whatever is being dissolved. I’m my case it’s 79 grams of KNO3 and I have to know of it would be saturated, super saturated, or unsaturated.
What if you were asked to a solution which is the least saturated at 20 degrees celsius with 20g of solute dissolved in 100g of water
Thanks helped on Hw
great vid!!
i love your vids
why he sound like Patton Sanders-
(not in a bad way of course your voice is great)
bro saving my life i get it now😭
@11:01 Cerium Sulfate, not Cesium Sulfate.
Thanks this helped a lot! :)))
So cool to hear. Thanks!
amazing video thanks alot
Well did
Great Video!! =]
Thanks for tuning in and leaving feedback! Keep up the good work!
My teachers teach for 5 weeks it doesn't make sense but when I watched 5-15 minute videos it does make sense. Something wrong here?
lets go ms.Nathan
you're awesome
ty
can u put in the file u are using thx
Get me out of chemistry omg
Science* for me