Can't believe a video on Ancient Greek Geometry has 4400 views. Maybe the human race will be okay after all LOL... Well atleast a few thousand will be okay LOL
Hi. Can I prove this proposition in this way? On c1, draw a line equal to c2. Let's say it's c3. Since c1 is larger than c3, it is larger than c2. On b1, draw a line equal to b2. Let's say it is b3. Since b1 is larger than b3, it is larger than b2. So, c1 + b1 is larger than c2 + b2. BTW, I am a big fan of yours!
Thank you for watching. I'm glad you enjoy the videos. Do you by chance have a picture of your proof? I'm not quite sure what you're referencing when you say c1, c2, b1, or b2.
@@EulersAcademy Thank you so much for your reply. Sorry, I don’t know how to insert a picture. Here is what I meant: On AB, draw a line equal to BD. On AC, draw a line equal to DC. Since the line drawn on AB is smaller than AB and the line drawn on AC is smaller than AC, the sum of AB and AC is larger than the sum of BD and DC.
@@charliesgi1473 I will have to think about this a bit more. I think this runs into problems since you're assuming that the line drawn to BD is shorter than AB which in some sense is part of what we're trying to prove. Based on the picture it makes sense, but the picture is only a guide. Even though it visually looks like BD is shorter and it makes intuitive sense that it's shorter, we can't assume anything based on the picture and we can only prove it is shorter by using the past theorems, the definitions, the axioms, and the common notions. Like I mentioned, though, I will give this more thought and get back to you if I realize a mistake in my reply.
@@EulersAcademy Hi Michael. Yes, you are right. Pictures can be misleading sometimes. I just realized that my assumption cannot be applied to a triangle having BD greater than AC or a triangle having DC greater than AC. Thank you so much for your insightful comments!
Stunning
Thanks. I'm doing euclid at my school and it's helpful to see it done for me.
Thank you so much. You helped me so much with geometry.
Can't believe a video on Ancient Greek Geometry has 4400 views. Maybe the human race will be okay after all LOL... Well atleast a few thousand will be okay LOL
Thanks for watching. I appreciate the support. You have some interesting videos on your channel that I'll have to check out.
Hi. Can I prove this proposition in this way? On c1, draw a line equal to c2. Let's say it's c3. Since c1 is larger than c3, it is larger than c2. On b1, draw a line equal to b2. Let's say it is b3. Since b1 is larger than b3, it is larger than b2. So, c1 + b1 is larger than c2 + b2. BTW, I am a big fan of yours!
Thank you for watching. I'm glad you enjoy the videos.
Do you by chance have a picture of your proof? I'm not quite sure what you're referencing when you say c1, c2, b1, or b2.
@@EulersAcademy Thank you so much for your reply. Sorry, I don’t know how to insert a picture. Here is what I meant: On AB, draw a line equal to BD. On AC, draw a line equal to DC. Since the line drawn on AB is smaller than AB and the line drawn on AC is smaller than AC, the sum of AB and AC is larger than the sum of BD and DC.
@@charliesgi1473 I will have to think about this a bit more. I think this runs into problems since you're assuming that the line drawn to BD is shorter than AB which in some sense is part of what we're trying to prove. Based on the picture it makes sense, but the picture is only a guide. Even though it visually looks like BD is shorter and it makes intuitive sense that it's shorter, we can't assume anything based on the picture and we can only prove it is shorter by using the past theorems, the definitions, the axioms, and the common notions.
Like I mentioned, though, I will give this more thought and get back to you if I realize a mistake in my reply.
@@EulersAcademy Hi Michael. Yes, you are right. Pictures can be misleading sometimes. I just realized that my assumption cannot be applied to a triangle having BD greater than AC or a triangle having DC greater than AC. Thank you so much for your insightful comments!
I'm glad my comment was helpful. Thanks again for watching.