Limit State Design of Wall Footing | Design of RC Element | Lec - 25 | Civil Tutor

[@mohamednadheem1044]

Distribution bar Ast=0.12×A×D
ast=π÷4×10*2 formula use panuna spacing 109 provide 110 yedukalam neega distribution bar video sollalae last ahh reinforcement detailing lae provide solli poturukinga epdi du sollunga brww

[@santhosh703]

Eagerly waiting for next video.
Upload next videos before newyear sir pls.....

[@civiltutor7220]

Ok pa.., I will try.. thanks for your support..

[@divyashreeselvan9842]

Step 3 la a=0.4 epdi na vanthuchu

[@dharanisri4340]

a=thickness of the masonry wall
400mm=0.4m

[@sasikumar6497]

Good understanding siva. Keep it up

[@civiltutor7220]

Thank you sasi...💟

[@ceVasanthanSK]

b value is 2m which means 2000mm. why you are providing 1000mm in depth of footing

[@c.v.sharmah5409]

Bro, b represent width of footing not depth ,1st understand difference b/w L =1m,b=2m,d=250,D=250+50(cover) =300mm

[@nandhunandhini6047]

Length 1 sotringa athaye poii b la potringa onume புரியல

[@velusiva8698]

Sir DRC exam on Jan 22
Please upload staircase and footing video sir please...🙏🙏🙏🙏🙏
After watching your video i have completed DRC protion ....

[@civiltutor7220]

Sure pa.. I will upload soon.. thanks for your support

[@c.v.sharmah5409]

Equilibrial explanation ❣️,onega DRC NOTES pdf KEDAIKUMA...!🙌