One of THE craziest & most beautiful integrals in existence

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  • Опубликовано: 28 июл 2023
  • WOW!
    WHAT A WILD INTEGRATION!
    Solution development using a bunch of my favourite tools and the integrals involved along with the final solution were indeed epic.
    Reflection formula for the gamma function (part of solution development of another cool integral):
    • My take on @MichaelPen...
    The gamma-zeta integral:
    • A quantum integral con...

Комментарии • 46

  • @maths_505
    @maths_505  Год назад +29

    Note: at the 6:50 mark it would've been better if I applied l'hopital's rule for the limit x->0. One differentiation of the numerator and denominator shows that the limit is indeed zero.

    • @JO06
      @JO06 Год назад +3

      Was thinking about that lol

    • @tueur2squall973
      @tueur2squall973 Год назад +1

      I think we all thought about that. I came to the comment section to say just that 😂

    • @maths_505
      @maths_505  Год назад +5

      @@tueur2squall973 so used to dealing with those kind of structures I feel like just crossing them out to zero without any explanation at all😂

  • @NittyLittyNiturzion
    @NittyLittyNiturzion Год назад +34

    I've been watching this channel for a bit now (since about 22k subscribers), and the problems have gotten more and more interesting, and has really made me cracked at integration

    • @maths_505
      @maths_505  Год назад +10

      And it's only gonna get better mate😎

    • @fhffhff
      @fhffhff Год назад

      π²$(0;∞)(1-ix²)²/sin²(πix²)dx=π(-x³/2-ix+0,5x-¹)(e^(πx²)+e^(-πx²))/(e^(π x²)-e^(-πx²))+$0,5πix-²ctg(πix²)dx-π (x+2$dx/(e^(2πx²)-1)dx)-0,75xln|co s(πix²)|+$0,75ln|(e^(2πx²)+1)/(e^(2 πx²)-1)|dx(0;∞)=-∞+∞i

    • @BridgeBum
      @BridgeBum Год назад

      Dr. Penn has a different focus, he's generally more interested in proofs than solving complex integrals. I enjoy both channels for different reasons.

  • @mihaipuiu6231
    @mihaipuiu6231 Год назад +1

    Nice demonstration! GOOD FOR YOU TEACHER 505!

  • @MrWael1970
    @MrWael1970 Год назад

    Awesome solution. It is very interesting integral. Thank you.

  • @vibaked
    @vibaked Год назад +9

    I feel like you don’t get the opportunity to write the numeral 8 in your videos much, so I’m excited to see it make an appearance here

    • @maths_505
      @maths_505  Год назад +16

      I barely get the chance to use any numerals in my videos so I in fact get nervous whenever I have to....
      "Okay Kamaal.....its just the number 8....you just need 2 circles one slightly bigger than the other....gotta draw em tangent to each other.....but what if they aren't tangent?????...oh wait yeah no big deal.....but what if they're so off tangent that it looks weird!!!"

    • @jkid1134
      @jkid1134 Год назад

      ​@@maths_505I write something like an S and connect the ends, highly recommend it

  • @user-os6zy8ik3y
    @user-os6zy8ik3y Год назад +4

    I enjoyed watching your video. Utterly wonderful. I’m just curious about where you learned those divergent mathematical concepts! Thank you

    • @maths_505
      @maths_505  Год назад +2

      I'm self taught so I just search up the internet for pdfs and videos. Alot of these integrals are homemade including this one.

  • @balasubramanianravikumar5233
    @balasubramanianravikumar5233 Год назад +2

    Presently reading the book In pursuit of Zeta-3 by Paul Nahin. It is just watching a series of Maths 505 video clips.

  • @nicogehren6566
    @nicogehren6566 Год назад +1

    Awesome!!!

  • @onionbroisbestwaifu5067
    @onionbroisbestwaifu5067 Год назад +3

    Ive always wanted to know what the squared norm of Gamma squared of (1+ix^2) on [0,infinity) was.

  • @shanmugasundaram9688
    @shanmugasundaram9688 Год назад +1

    Integration by parts method works well in solving this integral.Very interesting.

    • @maths_505
      @maths_505  Год назад

      Yeah. I thought about a series expansion but that gets clunky. IBP is quite elegant here.

  • @insouciantFox
    @insouciantFox Год назад +1

    Beautiful. Who needs real friends when you have Euler friends. They're much more complex and Γ be much more satistfying.

  • @Amoeba_Podre
    @Amoeba_Podre Год назад +1

    What is the value of zeta(3/2)

  • @johnporter7915
    @johnporter7915 Год назад +3

    This guy does this as casually as if I were explaining x value in x-1=5 to someone. 😂😂😂

    • @maths_505
      @maths_505  Год назад +2

      And I also made a small casual mistake😂😂....check out the pinned comment.

    • @johnporter7915
      @johnporter7915 Год назад +1

      @@maths_505 Haha. I meant this comment to be both funny and a compliment.

    • @maths_505
      @maths_505  Год назад +2

      @@johnporter7915 yeah I know I just wanted to point out that limit evaluation 😂

    • @maths_505
      @maths_505  Год назад +2

      @@johnporter7915 thanks mate

    • @BridgeBum
      @BridgeBum Год назад

      ​@@maths_505Was that really a mistake though? You can show that the "exponential wins" using L'H if you want, you just used that lemma as a shortcut.

  • @emanuellandeholm5657
    @emanuellandeholm5657 Год назад

    Cool!

  • @TheDarkness__
    @TheDarkness__ Год назад +1

    Hi! Is there anything where I can try to learn what the Gamma function is? Did you talk more deeply about it in a specific video?

    • @maths_505
      @maths_505  Год назад +1

      Brilliant.org is a good place to start. Then you can find detailed notes and articles on the gamma function on the internet.

    • @TheDarkness__
      @TheDarkness__ Год назад

      @@maths_505🫶

  • @ikarienator
    @ikarienator 11 месяцев назад

    6:19 I don't get the argument to only differentiate x^3. I think we need to differentiate x^3/(exp(2pi x^2)-1)^2 there.

    • @ikarienator
      @ikarienator 11 месяцев назад

      Oh, I see what's going on. The f'/f^2 = -d(1/f).

  • @sslelgamal5206
    @sslelgamal5206 Год назад +4

    I tried to solve it with Parseval-Plancherel's theorem for Fourier transform but unfortunately the Fourier of Gamma(ax^2) is not solvable! Same for Mellin and Laplace transform, also not usable, your method is the only one working 😅😅
    It as surprising though, cause it kinda looks like Meijer or Fox's H function types!

    • @maths_505
      @maths_505  Год назад +2

      The integral obtained after applying the reflection formula can be used to derive a melin transform for csch²(x²). All that's needed is integration by parts followed by calling on the gamma zeta integral.

    • @maths_505
      @maths_505  Год назад +1

      But yeah no transform will work from the word go because of the gamma functions....that's the way I designed this integral😂

    • @sslelgamal5206
      @sslelgamal5206 Год назад +3

      @@maths_505 Yeah, that's actually soo cool, I did not follow on the footsteps to arrive at the Csch step and wanted to go all out on Gamma's but this one works 👌👌👍👍

  • @jonsmith8579
    @jonsmith8579 Год назад

    wheres the gamma hook :(

  • @manstuckinabox3679
    @manstuckinabox3679 Год назад

    I think We can also use at 2:33 the inverse Mellin transform… you made a mistake and introduced me to this tranform now I refuse to shut up about it.

    • @maths_505
      @maths_505  Год назад

      A mistake I will never regret my brother

  • @giuseppemalaguti435
    @giuseppemalaguti435 Год назад

    In base ai miei calcoli... Doesnt converge... Boh???

    • @maths_505
      @maths_505  Год назад

      Definitely converges bro😂

  • @cycklist
    @cycklist Год назад

    Clickbait title much?