patrick i have been watching ur videos from limits to here. I pretty much learned calculus from your video rather then the text book and prof. Don't like to admitted but i skip my math class all the time cuz your video are much better then my prof's lecture. Your video has been a huge asset in my life! i would like to take this chance to wholeheartedly thank you for everything you have done for us. Please keep what your doing best and hope all your life problems will be solved (if any)!
thank you so much, I've watched nearly 20 of your videos just today to study for my AP calculus test, you explain everything very clearly, you are saving my grade!
@@huizylove We know both series converge because in both cases we have -1 < r < 1. And we split in two series, so we consider the total summation (the value the first one converges to plus the value the second one converges to).
thank you so much. i know you hear it all the time but you are truly one of the easiest people to learn from. you're awesome -sincerley, everyone who's ever taken calculus
I have struggled with learning calculus at UCLA until finding your videos. You teach these concepts very simply and show every step along the way. I wish more of my teachers taught like you. Thank you!!!
TOO AWESOME THANKS! I'm that way too, I can't compute simple math on demand, but I can grasp challenging concepts quickly. Interestingly enough, the series concepts aren't easy when being self-taught.
Even though I got a 37 on my exam before my final because my professor is a pompous prick with a 50% pass rate, watching your videos helped me ace the final and pull out with an A in my calc 1 class, thanks so much!
Patrick, I don't know if someone has mentioned this, but is (1/3)/(2/3)= .5, and it would diverge to 1.5... Unless I made a stupid mistake somewhere, which is 100% possible. Thank you so much for the videos though. I use your videos more than my lecture. Calc 2 midterm t-minus 16 hours.
How do I tell the difference between a P series and a Geometric series? My professor also said something about alternating series, but she mumbles and uses markers almost out of ink, so my notes are pretty much useless.
I just wanted to check if the series converges or diverges....so I applies limit tends to infinity to the function. I just got log (6^6^n)/log(6^6^n) = 1 which is not equal to 0. So the series diverges.... But actually the series converges.... Can somebody help me on this....
ugh.. why didn't I watch these videos earlier in the semester.. !! If I did, I would not be stressing so much about the final and I would definitely end up with an A in my Calc II class
+Kristen Henderson You can only use 'that' (which is the sum of a given geometric series). If r is a number which is less than one (regardless of positive or negative sign). Example, 2/3, 4/5. All are less than one. So, we evaluate one of these numbers from a given limit, hoping to get a fraction which is less than one. So we use that as our r and find a by plugging in the inital value of n which they specified to start with (like n=1). If we don't get a number which is less than one, then the series is divergent and a sum for that series, does not exist.
On your previous video 'what is series' you said that the formula (a/(1-r)) works only if our common ratio is raised to 'n-1'... Here on your last example you used the formula even if the common ratio was raised to 'n'.. Did i understand something wrong or you just forgot it?... thanks by the way you helped me a lot ! :)
this is wrong guys, you can't use this theorem if the series start from n=1, you have to change the series to start from n=0 and then use 1/(1-x). the answer for this question should be 1.5
It's perfectly fine to do what he did, he simply did his arithmetic at the end wrong. he said (1/3)/(2/3) is equal to two instead of .5. Either way you do it, the answer is 1.5
patrick i have been watching ur videos from limits to here. I pretty much learned calculus from your video rather then the text book and prof. Don't like to admitted but i skip my math class all the time cuz your video are much better then my prof's lecture. Your video has been a huge asset in my life! i would like to take this chance to wholeheartedly thank you for everything you have done for us. Please keep what your doing best and hope all your life problems will be solved (if any)!
thank you so much, I've watched nearly 20 of your videos just today to study for my AP calculus test, you explain everything very clearly, you are saving my grade!
for the answer, the first part converges to 1, but the second part converges to 1/2 not 2. so the final answer is 3/2 or 1.5 not 3
but does it converge? because the summation is 1.5? or the converges are tested one by one and then we have the total summation?
@@huizylove We know both series converge because in both cases we have -1 < r < 1. And we split in two series, so we consider the total summation (the value the first one converges to plus the value the second one converges to).
thank you so much. i know you hear it all the time but you are truly one of the easiest people to learn from. you're awesome
-sincerley, everyone who's ever taken calculus
@jhh1822 ops yes, my mistake!
You are a fantastic teacher! Many professors are doctors, etc, but they're not meant to teach! You make things a lot simpler and make math fun!
I have struggled with learning calculus at UCLA until finding your videos. You teach these concepts very simply and show every step along the way. I wish more of my teachers taught like you. Thank you!!!
have you graduated ucla
you are a much better teacher than my current calc II teacher. you make series seem so easy. so thank you so much. you're a life saver :D
@DashofDosh ha - now i feel pressured to make good videos!
The forms you put your equations in were spot on with the summations I needed to figure out. Thank you!
2:00 1/3 over 2/3 is 1/2 not 2
@mosum91 you are welcome
thank you patrick! I treat calculus class as a free period but learn at night when I watch your videos.
TOO AWESOME THANKS! I'm that way too, I can't compute simple math on demand, but I can grasp challenging concepts quickly.
Interestingly enough, the series concepts aren't easy when being self-taught.
MVP MVP MVP
Even though I got a 37 on my exam before my final because my professor is a pompous prick with a 50% pass rate, watching your videos helped me ace the final and pull out with an A in my calc 1 class, thanks so much!
Thanks Patrick, your videos are great help for me to understand calculus.
@DonChedda opppps! i am just making sure you all are paying attention
Thank you for you very informative videos. You break the concepts down so well that it is very easy to understand the concepts.
@The1ntern well, math videos seem like a good place to advertise math videos : )
Dude you are awesome..i've got this cal teacher who doesn't know how to teach -.- my final is tomorrow, u just helped me regain my confidence.. (:
Patrick, I don't know if someone has mentioned this, but is (1/3)/(2/3)= .5, and it would diverge to 1.5... Unless I made a stupid mistake somewhere, which is 100% possible. Thank you so much for the videos though. I use your videos more than my lecture. Calc 2 midterm t-minus 16 hours.
Haven't been to class all year and this basically summed up a 2 week unit into 5 minutes
glad you like them! thanks a bunch for spreading the word!!
I have midterm tomorrow. your videos really help me. thanks a lot
You're The best Patrick!!! really saving my life right now!!!
I have a question! Since the geometric series state that the formula should be in this form.... ar^(n-1).... wouldn't you need to change it?
You save my life. I had difficult times with this topic. I got the basic concept now. :-)
How do I tell the difference between a P series and a Geometric series? My professor also said something about alternating series, but she mumbles and uses markers almost out of ink, so my notes are pretty much useless.
@Tweak2727 a big 'your welcome' to all the unlv students!
freakin awesome dude. I just learned this thing today and you make it so much easier.
Also I got a 100 on my 2nd test on integration!
Thank you
Bright booy
good job im proud of you
I learn more in one of your 5min vids than i do in my 2hr lectures
what is exactly should be reconsidered? 1/3 divided by 2/3 equal 1/2 and 1+1/2=3/2 ???!!!!!!!!!
you saved me. you have no idea. thank you. so much. soso much.
which one is the very first vdo to learn convergence and divergence of an infinite series?
Link to the first part please? :-D
Your math videos help a lot you are a boss.
how does that answer the question?
I just wanted to check if the series converges or diverges....so I applies limit tends to infinity to the function. I just got log (6^6^n)/log(6^6^n) = 1 which is not equal to 0. So the series diverges.... But actually the series converges.... Can somebody help me on this....
using the test for divergence , (1/2)^n for n->oo is equal to 1 , which is not equal to 0 ! so why does (1/2)^n converge and not diverge?
I thought geometric series had to be in the n-1 format and the only way to do the ^n way, the sigma below has to equal 0?
the second series was 1/2, not 2.
you are the man who saved my life!!!!!!!!!!!!!!!!!!
ugh.. why didn't I watch these videos earlier in the semester.. !!
If I did, I would not be stressing so much about the final and I would definitely end up with an A in my Calc II class
I thought you can only do the (a/(1-r) if (n-1)? I'm confused.
+Kristen Henderson You can only use 'that' (which is the sum of a given geometric series). If r is a number which is less than one (regardless of positive or negative sign). Example, 2/3, 4/5. All are less than one. So, we evaluate one of these numbers from a given limit, hoping to get a fraction which is less than one. So we use that as our r and find a by plugging in the inital value of n which they specified to start with (like n=1). If we don't get a number which is less than one, then the series is divergent and a sum for that series, does not exist.
@like9orphanz perfect : )
yay! it should be reconsidered pat, all due respect
Please make more sequences and SERIES videos!
@Billabong024 good job!
wait....(1/3)/(2/3)=(1/2) correct. so doesnt it converge to (3/2)
@linocutter same here my final is tomorow and this series driving me crazy
why Term 1/2 ? and 1/3
Bc it starts at n=1 so the first terms are 1/2 & 1/3
On your previous video 'what is series' you said that the formula (a/(1-r)) works only if our common ratio is raised to 'n-1'... Here on your last example you used the formula even if the common ratio was raised to 'n'.. Did i understand something wrong or you just forgot it?... thanks by the way you helped me a lot ! :)
yes this is confusing me and others as well....
OMG THANK YOUUUUUUUU... Brilliant videos!
thank you very much patrick
wait... i thought you can only us a/(1-r) if the series is to the (n-l)power....
how can you dislike a fucking good educational video? wtf
The series converges to 1.5
Please check if its correct :)
if I ever become successful, I'll be sure to be making a very generous donation to your website for helping put me through college math
I LOVE YOU
i made the exact same mistake evaluating it... its at this point that we as people forget arithmetic...
actually i was backing your idea, i said "pat" for patrick dude, sorry for confusion
@mamatela As you can see yourself, everybody makes mistakes !
THANKS A LOT
cool videos!
Thank you so much!!
you forgot to flip the fraction when you divide. I think u got it wrong the answer is thus 3 not 3/2 please check again.
To be honest i think your videos are easier to understand the khanacademy videos
Thank you so much.
It will converge to 3/2 not 3, because (1/3)/(2/3) = 1/2
YES!! I actually understand this shit now!
you did very well
only because 1 elevated to anything gives you 1... if not you couldn't do that.
Thanks Patrick! I love you so much! You're almost better than Khan!
+anna lydia almost? wow that mustve hurt him
Thanks but it converges to 3/2 not 3 otherwise nice video
thanks a lot sir.
why doesn't it converge to 0? you are raising a number between 0 and 1 to the power of infinity.
series = sum. the final term at infinity will be 0 but if u add all the terms up to the infinite term u will end with the sum
thank you!!
help, thy name is patrickJMT
Patrick for 2020
You are greattttttt
1/2^oo = 0 ,so is convergent
I love you!!!
is "bust up" a math term cause both you and my calc professor say it LOL
Why are the cool and intelligent people always the ones to be left handed?
yup
i got 1.5 as my answer
thx
ooooh okay, sorry I misunderstood I feel like a dumb ass right now loool
wow it was good
sometimes i think they should start a youtube university.
don't compare them, but i know what u mean :)
i hate "that tutor guy"
you're wrong...... ((1/3)/1-(2/3))= 3/2
mine are of ebay :D
haha, dont be:)
oh just kidding
first view, cool
this is wrong guys, you can't use this theorem if the series start from n=1, you have to change the series to start from n=0 and then use 1/(1-x).
the answer for this question should be 1.5
It's perfectly fine to do what he did, he simply did his arithmetic at the end wrong. he said (1/3)/(2/3) is equal to two instead of .5. Either way you do it, the answer is 1.5
If it is for higher level math, we should use Theorem instead of the way he did it. The answer maybe right, but it won't get full point for it.
Jiaqi Hu It was certainly accepted on my college Calc 2 final, though it is true that some professors may not accept it.
check here.. you are right www.wolframalpha.com/widgets/view.jsp?id=86ceba9f35c96ebae137e44a36c7261a
Link to the first part please? :-D