Problem 5: Analysis of T -frame by moment distribution method

[@ashwinkumar8965]

Thank you for this amazing session.This is very usefull to gaining my knowledge.

[@ameenask9710]

Very nice teaching madam and your pitch also

[@manjunathrkn]

Nice presentation....very clear explanation...

[@shashank_d_a]

Thank you for this amazing teaching mam 😊

[@rosidahrazak4531]

teacher you teaching is so clear, Thank you so much

[@cattleyalater1605]

Since you are considering the modification of stiffness factor, simple support should not carry any moment. FEM OF CB must be zero

[@mehulgadhvi942]

To start calculation first assume it as fixed and at the end final moment comes zero, see 17:40

[@leaderleads3884]

👍

[@thewinger1665]

Thank you I have Question through calculated distribution factor about JOINT BA why we use 4I/L But WE HAVE FIXED USED I/L I NEED EXPLAIN THANK YOU.

[@swasthik4139]

Yep we use I/L for fixed support

[@filipszymanski6266]

Summed up moments at joint B should equal to zero? Why does this examples not end up equaling zero?

[@er.deependrashrestha1058]

FEM of CB should be released to make zero at the moment distribution table before the balancing process.

[@DevendraDulal-kl8kg]

It"s 0.4 not 1.4

[@Ram..866]

Thank you mam ❤

[@nasserabdouramane2534]

thanks

[@srinurao3327]

in moment distribution ...for final moments of member BD is -19.38+2.55=(-)16.83 please confirm

[@gurumantraacademy9843]

Also bmd change by this region

[@hruthikroshanlalji6439]

Tq madam