Good explanation, if only my prof explained it and not just left us with the formula. Also, if anyone is confused about the negative sign: for chemistry we use Q-W= Ek + Ep + H but in physics we use Q+W= Ek + Ep + H
7:25 According to my textbook: The mechanical work done on the system is defined as w = - PV, where P is the pressure and V is the volume change and is equal to V2 - V whats goin on?
A gas has initial volume 0.2 cubic metre and temperature 290 K and pressure 1 atm. If its temperature is changed to 253 K and pressure is changed to 1.2159 atm the final volume attained is 0.1453 cubic metre . So what will be work done in expansion or PdV work? should we take P=1atm(initial)or P= 1.2159atm(final) to calculate PdV work. Please help ben. Is my question wrong?
sir, you discussed about workdone on compression and which W=-P∆V. But You have given a example of workdone on expansion.So, how can this possible that W=-P∆V. I think it will be W=P∆V and not the '-' sign attached to it
why 3.6 atm pressure... during expansion the pressure is going to change continuously... so is it that we have to always take the initial pressure for PdV work during expansion???
Thanks Ben!!! Still watching your videos OLD BUT GOLD indeed
You're very welcome! Thank you for your kind words, and thanks for watching! 😀
Wow, sir, your 10 minutes video has answered my far-fetched doubt for the entire time, thank you so much sir
You're very welcome! Thank you for your kind words, and thanks for watching! 😀
Thanks you, this help me understand pressure-volume work better because you use the example of the car engine.
thank you so much you dont understand how happy you made me when you brought out a real life example
You're very welcome! Thank you very much for watching 😃
Thank you much! A good, straightforward guide!
Ben...Dude...Awesome!! u just made Thermodynamics fun!!!...Keep up Buddy!
You're a great teacher! Thank you very much. This was pretty helpful.
You're very welcome! Thank you for your kind words!
Good explanation, if only my prof explained it and not just left us with the formula. Also, if anyone is confused about the negative sign: for chemistry we use Q-W= Ek + Ep + H but in physics we use Q+W= Ek + Ep + H
Which grade u in?
i know im late but youre way of teaching is very awesome . THANK YOU VERY MUCH.
You're very welcome! Thank you so much for your kind words, and thanks for watching 😀
Finally!!! I am so fucking happy that I found this one.
YOU LITERALLY SAVED MY LIFE
Best video I found on this topic. Thank you.
You're very welcome! Glad you found it helpful!
Great video. Not really what I was looking for but still very helpful
thanks man for dis video...it was well explained n beter understood..! good job!!
So So SO So PERFECT !!! Really thank you
Thank you very much Mr Ben now I know where the pressure-volume equation comes from!
You're very welcome. Many thanks for watching! 😃
This video made my day today thanku sir
You're very welcome 😀
I learned so much from this video. Thank you sir!
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thank you so much .................i understood everything!
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Thank you soooo much brother 👍🏻👍🏻👍🏻😊😊😊. Got this in one shot. Thanks a lottttttt💜💜
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was confused about the sign. thank you.
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Sir to good explanation. Keep it up sir👍👍👍👍.
Thanks so much! 😃
thanks man, found my answer
Glad I could help! 😃
Thank You! You explained this so well. :)
Yaa boy keep it up
Wow that was clear and interesting. Thanks a lot.
Thank you 👍🙂
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Wowww. you. know. how .to. explain 😮😮😮😮😊😊😊
Very helpful. Thanks.
thank you man
You're very welcome! Thanks for watching 😀
Very useful explanation, thank you
You're very welcome! Thanks for watching 😀
Well done!!
One lying crook complimenting another lying crook!!!
Thanks man 💯 💯 blessings on blessings
7:25
According to my textbook:
The mechanical work done on the system is defined
as w = - PV, where P is the pressure and V is the volume change and is equal to
V2 - V
whats goin on?
can you share any links or make a video to understand physically and equation wise about NON PV WORK?
Thankyouu bro👍🏻
You're very welcome 😃
Thanks!
very nice and helpful video. thanks alot
fantastic ! such an in-depth and helpful explanation. thanks for your hard work!
You're very welcome! Thank you for your kind words, and thanks for watching 😀
Many thanks
very good
Thanks for your kind words, and thanks for watching!
very helpful thank you very much
A gas has initial volume 0.2 cubic metre and temperature 290 K and pressure 1 atm. If its temperature is changed to 253 K and pressure is changed to 1.2159 atm the final volume attained is 0.1453 cubic metre . So what will be work done in expansion or PdV work? should we take P=1atm(initial)or P= 1.2159atm(final) to calculate PdV work. Please help ben.
Is my question wrong?
thanks for the Lxatm conversion, I always get stuck on that
What if i used -V delta P instead, it does not make sense for me at all.
Please findout work done by an aneroid barometer in joules ?
Thank you for guidance thank you so much thank you
Thanku sir very Helpful😊👍
THANKS
You're very welcome! Many thanks for watching 😀
Thanks BeN
very much helpful video
Did you make these new videos for quality? Just curious.
sir, you discussed about workdone on compression and which W=-P∆V.
But You have given a example of workdone on expansion.So, how can this possible that W=-P∆V.
I think it will be W=P∆V and not the '-' sign attached to it
In expansion work is negative
What is workdone by aneroid barometer in joules ???per year ?? So irs done lots of work but gonna waste ?use this power in making electricity ?
Great 👏👏
why 3.6 atm pressure... during expansion the pressure is going to change continuously...
so is it that we have to always take the initial pressure for PdV work during expansion???
Perfect, thank you so much!
Champion!
what if my pressure went up when I decreased the volume? what do i plug in for the -P then?
Oscar Castaneda Munoz fuck off
thanks for your teaching
4:45
Thats what you are looking for
how to solve the work if the initial and final volume is given and no atm given
superb
Tysm :)
Perfecto
The pressure has to be in kPa. That way you don't convert the energy. 1J = kPa L = kPa dm^3
Why is the pressure constant
لحضة إدراك الفيديو تم تنزيله وأنا بالثاني ابتدائي وحالياً أشاهده وأنا بالخامس إعدادي 👤💔
Why pressure is constant
Class 11 😒😒😒
I can not intrested your video pleas speak hindi