You just opened my eyes to another way to see and calculate the Surface Integral, thank you so much, keep doing videos like that, and if you could explain some difficult exercise would be great 👌🏾🔥
We don't calculate the length of the cross product. We calculate sqrt[det(D^T D)], where D is the derivative of the parametrisation. Looks like equivalent
Ahh I missed this video for some reason loll. Btw I like to think of the surface intgral like the mass of a really thin sheet thats molded to fit some mold where f is the density. It doesn't really make much sense bc the sheet would have to be "infinitely thin" but I guess you could think about the limit of the masses of a bunch of finite sheets as the thickness goes to 0 or something like that
here is a problem mr peyam. Find a linear operator such that: O(y¨)=O(y) for all functions with second derivative, and the other restriction is O(y^2)=(O(y))^2???????
This was too much, "then you do magic here, that I don't explain". Why is dS just the length of the cross product? Why do I replace y with the parametrization? At least for me, this video doesn't answer the question "What is a Surface Integral". Sorry, normaly I really like your videos, but on this I think I am missing too much knowledge on this topic.
would like to take a minute to say that your such a good tutor doc, soft spoken and detailed explanations. Hope you do more of these types of videos.
Thank you so much!!!
The recent surfaces video of yours made me look into differential geometry, thanks for the motivation haha
So clear! I love how i learn so easily with your videos, they are perfect
I have not looked at surface integrals in way too long. THANK YOU DR. PEYAM!!!
Why fear, Dr Peyam is there!!
I was just starting this, thanks for wonderful explanation Dr Peyam!!
You just opened my eyes to another way to see and calculate the Surface Integral, thank you so much, keep doing videos like that, and if you could explain some difficult exercise would be great 👌🏾🔥
finallly Dr. Peyam.....
You are great pal, one of the best. Hi from Spain
We don't calculate the length of the cross product. We calculate sqrt[det(D^T D)], where D is the derivative of the parametrisation. Looks like equivalent
Thank you for the great example!
Ahh I missed this video for some reason loll. Btw I like to think of the surface intgral like the mass of a really thin sheet thats molded to fit some mold where f is the density. It doesn't really make much sense bc the sheet would have to be "infinitely thin" but I guess you could think about the limit of the masses of a bunch of finite sheets as the thickness goes to 0 or something like that
here is a problem mr peyam. Find a linear operator such that: O(y¨)=O(y) for all functions with second derivative, and the other restriction is O(y^2)=(O(y))^2???????
Maybe differentiate both sides of Oy^2 = (Oy)^2?
@@a_llama mmm I already tried that and I couldnt get anything...try something else
What is O?
@@drpeyam O as an Operator (linear in this case)
Any operator?
Thank you
What is the SI unit for surface integral
dose?
Can r be a function of 3 variables ??
ايلافيوه اب دكتور بيان (:
Why is r a function of 2 variables u and v ??
I'm your fan Dr peyam! c:
Thank you!!!
I shall be the envy of my friends when they find out I crossed two vectors!
Are you interested in primality testing for very large numbers?
Not really, I don’t like number theory
@@drpeyam :o finite fields are the future!
Nah, real numbers it is for me
❤️
master :))
Doctor ;)
You got to tell the viewer WHY you do some of the steps !
?
This was too much, "then you do magic here, that I don't explain".
Why is dS just the length of the cross product?
Why do I replace y with the parametrization?
At least for me, this video doesn't answer the question "What is a Surface Integral". Sorry, normaly I really like your videos, but on this I think I am missing too much knowledge on this topic.
You should check out my playlist, it covers the basics. Also, I give some intuition at the end of this video
@@drpeyam i will do. Thank you.