Can you do this crazy integral?

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  • Опубликовано: 19 ноя 2024

Комментарии • 83

  • @two697
    @two697 2 года назад +34

    I've noticed myself getting better at integrals just by watching Michael Penn videos. I was able to solve this one is under 5 minutes

  • @kkanden
    @kkanden 2 года назад +54

    such a fun integral! loved how it combined with the 1/x^2 factor! great video michael keep it up :D

  • @Monkieteam
    @Monkieteam 2 года назад +23

    I used what we proved about α and β as inspiration to solve the integral in a pretty nice way :
    * Take x = sqrt(1+θ²) + θ
    Then similarly to the case with α and β, we have that x - 1/x = 2θ.
    * Under this change of variable, α and β clearly become -π/6 and π/6 respectively.
    * dx becomes (θ/sqrt(1+θ²) + 1)dθ, however since cos(2θ)*θ/sqrt(1+θ²) is odd, that part vanishes in the integral (the bounds are opposite)
    * we are left with integral of cos(2θ)dθ from -π/6 to π/6, which gives sin(π/3).
    Nice video as always!

  • @alexrozenbom3430
    @alexrozenbom3430 2 года назад +23

    I would have majored in Math if I had seen Michael Penn's videos growing up in the 80s and 90s.

    • @nikitakipriyanov7260
      @nikitakipriyanov7260 2 года назад +1

      I think he himself would have been happy to see those videos these years when he was growing up too :)

  • @HershO.
    @HershO. 2 года назад +17

    Very creative! At first I tried doing this through u-sub but soon realised that it was going to be an extraneously long solution, problem being absence of 1 + 1/x^2 term. Although I think this is the best method, if one were to go through the efforts of doing the u-sub completely, then I suppose IBP would've eventually yielded the solution. Just as a back up brute force plan.

    • @leif1075
      @leif1075 Год назад

      But he did ubsib in tbr video..was yours different

  • @paulconway5693
    @paulconway5693 2 года назад +1

    I absolutely love the way you present your videos!

  • @manucitomx
    @manucitomx 2 года назад +6

    Wow, wow, wow.
    Great, if contrived, problem.
    Thank you, professor.

  • @Pengochan
    @Pengochan 2 года назад +11

    Reminded me of this one: ruclips.net/video/pOCisqitZbk/видео.html
    Note that until the very last step only the evenness of cos() and properties of the bounds of integration are used here, so that would apply to any integral over f(x+1/x) from a to b with ab=1 and f even.

  • @AntonioRadici
    @AntonioRadici 2 года назад

    great video as usual. I'm already a patreon supporter and I'm super happy that we are getting closer to the 1k/mo goal!

  • @ChristianRosenhagen
    @ChristianRosenhagen Год назад

    It's a joy to watch!

  • @Mystery_Biscuits
    @Mystery_Biscuits 2 года назад +1

    I wasn't really sure where he was going with this but then at 7:49, it all clicked, and it's a very slick solution I might add!

  • @ВикторПоплевко-е2т
    @ВикторПоплевко-е2т 3 месяца назад

    I love this integral

  • @nightowl9512
    @nightowl9512 2 года назад

    Well that was a treat

  • @MichaelGrantPhD
    @MichaelGrantPhD 2 года назад

    ok that took a twist I wasn't expecting. fun!

  • @jaredvv86
    @jaredvv86 2 года назад +3

    This reminds me of calc II test in college. It was the ridiculously ugly integral, just really painful. After all the work and effort it simplified out to be just 1+1 =2. Pretty sure the professor was just having a laugh at our expense.

  • @bitanic
    @bitanic 2 года назад

    Brilliant!
    Beautiful!

  • @CaradhrasAiguo49
    @CaradhrasAiguo49 2 года назад

    I did this with a x = e^t substitution since the (x - 1/x) argument to cos reminded of e^t - e^{-t} which is 2sinh(t), then added and subtracted integral on the same log-transformed bounds of the integral of e^{-t} * cos(e^t - e^{-t}) dt. Then I briefly got stuck but the hint came in helpful with the "extra" definite integration of the e^{-t} * cos(e^t - e^{-t}) dt term which is just a negative copy of the original integral, leaving 2 * I(t) = integral from -ln(beta) to ln(beta) of (e^t + e^{-t}) * cos(e^t - e^{-t}) dt, which is an easy u-sub.

    • @leif1075
      @leif1075 Год назад

      Why not just start with cosine difference formula isn't that simpler and more obvious?

  • @egillandersson1780
    @egillandersson1780 2 года назад +1

    I had the "aha!" at 4:13 A very funny integral !

  • @preethamjee6022
    @preethamjee6022 2 года назад +1

    We can use glasser master theorem if the bounds are between -infinity to +infinity

  • @jensknudsen4222
    @jensknudsen4222 2 года назад +2

    What a lucky coincidence that all that crazyness boils down to such a neat result in the end ;-)

    • @chri-k
      @chri-k 2 года назад +5

      almost as if it was intentionally constructed to be se

    • @jesusandrade1378
      @jesusandrade1378 2 года назад +1

      @@chri-k It was intentionally constructed to be so

    • @BikeArea
      @BikeArea Год назад

      I second that.

  • @richardheiville937
    @richardheiville937 2 года назад

    the trick works fine too for computing integral of 1/(1+x^4) x=0,infinity

  • @mathhack8647
    @mathhack8647 2 года назад

    Waou!1 amazing strategy. Starting my breakfast with this Pb.

  • @bilalabbad7954
    @bilalabbad7954 2 года назад

    Fun integral

  • @stefanalecu9532
    @stefanalecu9532 2 года назад +28

    Michael or his editor should be more careful with the thumbnails, the problem in the video isn't the same as the problem in the thumbnail

    • @Hiltok
      @Hiltok 2 года назад

      Your engagement by commenting on that micro-error has boosted this channel in YT's algorithm. If you haven't noticed that it's not a bug, it's a feature to get extra engagement, then you haven't really caught on to what running a YT channel is all about. Put aside the annoyance of these 'mistakes' and just enjoy the channel for the great coverage of topics.

    • @winteringgoose
      @winteringgoose 2 года назад

      @@Hiltok Are you seriously suggesting the commenter should enjoy this channel but *not* boost it? That's plain silly. If everyone involved enjoys the content it makes no sense to discourage engagement. 🤔

    • @Hiltok
      @Hiltok 2 года назад

      @@winteringgoose I'd rather people engage with the maths than remaining upset by trivialities like whether the thumbnails exactly match the content. There have been multiple comments about it over time so if it was going to be 'fixed' that would have happened by now. It hasn't, so one can infer a choice has been made.
      [I used to pause the videos to write comments about transcription errors in Michael's work. Over time, I learned that he always corrects them later on, either in person on the video or by superimposing script over the offending bits. It happens often enough that it's 'just how he rolls'.]

    • @Hiltok
      @Hiltok 2 года назад

      @@angelmendez-rivera351 My comment was based on drawing an inference from observed behavior.
      What reason do you ascribe to Michael and his crew ignoring the issue of thumbnails not exactly matching the problem at hand, about which there have been multiple comments over time? If it is not seen as a triviality that leads to extra comments/engagement to feed the YT algorithm, then it suggests they lack responsiveness to their viewers wanting greater accuracy. I know I'd prefer to think of the people running this channel as smart enough to know how YT works and looking to improve outcomes for the channel. I don't think I would want to categorize them as uninterested in the concerns of their viewers and repeatedly slipshod in their productions.

  • @markothy8
    @markothy8 2 года назад

    So satisfying!

  • @jucom756
    @jucom756 2 года назад +2

    I'm new to integrals, why are you just allowed to substitute u with x to get the 1/x² integral? I can think of a quick proof for all the rest of the steps but i don't get that step, shouldn't it be replaced with 1/x, giving the original integral again?

    • @dalek1099
      @dalek1099 2 года назад +1

      Definite integrals that are the same except for the labelling of the variable are equal. You can suppose you have the antiderivative F(x)/F(u) and substitute the limits to prove this you will get F(beta)-F(alpha) in both cases.

  • @user-et1up1nk9k
    @user-et1up1nk9k 2 года назад +1

    Cool integral simplification tricks 🥵

  • @jantarantowicz1306
    @jantarantowicz1306 2 года назад

    okay, it was epic!

  • @user-pr6ed3ri2k
    @user-pr6ed3ri2k 2 года назад +1

    1/s ds /x

  • @SuperYoonHo
    @SuperYoonHo 2 года назад +1

    Woah!

  • @thomasbach-zy1kn
    @thomasbach-zy1kn Год назад

    If you go back to “x“, should it not be “x^2“ instead of the inverse?

  • @user-pr6ed3ri2k
    @user-pr6ed3ri2k 2 года назад +1

    arithmic propertiEas

  • @charleyhoward4594
    @charleyhoward4594 2 года назад

    wolfram gives some crazy results when ∫ (1+1/x^2 ) cos(x - 1/x) dx

  • @karma_kun9833
    @karma_kun9833 Год назад

    Same integral 0 to infinity

  • @9WEAVER9
    @9WEAVER9 2 года назад

    the argument of that integrand is not quite a nice place to stop... maybe add a 1/x^2 term to 1-1/x
    .?.?.?

  • @pandabearguy1
    @pandabearguy1 2 года назад

    I cant even integrate the classification of all finite simple groups over the unreal numbers

  • @Noam_.Menashe
    @Noam_.Menashe 2 года назад

    This looks like the cauchy smolich transform.

  • @leif1075
    @leif1075 2 года назад +1

    WHO came up.woth this integral to begin with and WHY would they??

  • @Unidentifying
    @Unidentifying 2 года назад +1

    i did three substitutions to come to that even function argument switch 🤦‍♂🤦‍♂
    clever solution, thumbnail is wrong btw

  • @dsacton
    @dsacton 2 года назад

    I'm not seeing the step at 6:23. It seems like the x^2 should cancel the x^-2, yielding the original integral.

    • @bjornfeuerbacher5514
      @bjornfeuerbacher5514 2 года назад +3

      There is no x² anywhere in that integral which could cancel the x^-2. What are you talking about?
      He essentially is only renaming the dummy integration variable from u to x.

  • @micomrkaic
    @micomrkaic 2 года назад +8

    I have a feeling that this problem was constructed going backwards. It is fun, but very artificial. Speaking as someone who studies physics -- you will almost never encounter something like this in "real life".

    • @l1mbo69
      @l1mbo69 2 года назад

      You can do this by a less clever method too, and the problem itself is also very non specific and simple to state

    • @jesusandrade1378
      @jesusandrade1378 2 года назад +3

      Yes, the bounds or limits of integration are very artificial or very special, or cooked up, in order to solve the integral.
      I think the indefinite integral is very hard to find or may not be an elementary function.

    • @Unidentifying
      @Unidentifying 2 года назад

      but when you do, you now know how to solve it

    • @l1mbo69
      @l1mbo69 2 года назад

      @@jesusandrade1378 but the only thing relevant about the bounds is b-a=π/3 and ab=1

  • @wagsman9999
    @wagsman9999 2 года назад

    whoa !

  • @ddognine
    @ddognine 2 года назад +1

    6:25 I don't understand how we can substitute u=x back into the integral when u was previously defined as 1/x. Can someone please explain? Thanks

    • @YoshiActorEggman
      @YoshiActorEggman 2 года назад +3

      Variable names don't matter

    • @chri-k
      @chri-k 2 года назад

      he just re-named u to x

    • @BridgeBum
      @BridgeBum 2 года назад +3

      Further, the new x and the old x are not the same but that's ok when dealing with definite integrals. When all is said and done we are ending with a constant after evaluation.

  • @CGMossa
    @CGMossa 2 года назад

    I don't get the even function argument, but I guess it is simple enough...

  • @ojas3464
    @ojas3464 2 года назад +1

    👍

  • @leif1075
    @leif1075 Год назад

    Why not use cosine difference formula tonsokve. Isnt this SCREAMING gor youbto do that? Dodnt any onebekse do this??

  • @राजनगोंगल
    @राजनगोंगल Год назад

    👍👍👍👍👍👍

  • @ennead322
    @ennead322 2 года назад

    Did he really look up sin of 60? 10:14

  • @hoangnguyennguyen6445
    @hoangnguyennguyen6445 2 года назад

    insane :DDDD

  • @d.h.y
    @d.h.y 2 года назад

    Seriously, can anyone solve this integral question at first sight? There are so many tricks here. In my opinion, even a calculus teacher would take some long time to find all the tricks in this question. ( I wonder whether my assumption is right🙄🙄)

    • @EquuleusPictor
      @EquuleusPictor 2 года назад +1

      It's easier than it appears because of two factors: 1) substituting u = 1/x is quite natural; 2) the integration bounds are so specific that serve as hints basically for point 1)

    • @d.h.y
      @d.h.y 2 года назад

      Oh, your point makes sense! Maybe I should be more used to wider range of problems. Thanks!!

  • @kqp1998gyy
    @kqp1998gyy 2 года назад

    🌹

  • @user-pr6ed3ri2k
    @user-pr6ed3ri2k 2 года назад +1

    barely complicated

  • @Vladimir_Pavlov
    @Vladimir_Pavlov 2 года назад +2

    I looked at the screen. The integral function cos(1-1/x) is depicted.
    I paused in watching the video and started to solve. Got the result. I decided to compare.
    It turned out that the integrand function cos(x-1/x).
    Complete shit and lack of respect for the audience.

    • @bsmith6276
      @bsmith6276 2 года назад

      Not the first time the thumbnail was wrong, though it seems to be changed now. I do wonder what's going on because Michael is the only math guy I follow that has recurring instances of mismatched thumbnails at time of upload.

    • @Vladimir_Pavlov
      @Vladimir_Pavlov 2 года назад

      The picture was imperceptibly corrected. and my comment turned into not adequate.)))

    • @TheCloudyoshi
      @TheCloudyoshi 2 года назад

      I think that was an honest mistake by him- part of me thought it was the equivalent of a mobile game ad where the ad is fake just to lure you in, but the fact that he corrected it makes me think it was just a mistake

  • @tcmxiyw
    @tcmxiyw 2 года назад +1

    Cute!

  • @echandler
    @echandler 2 года назад

    cute!

  • @user-pr6ed3ri2k
    @user-pr6ed3ri2k 2 года назад +1

    21hourzslate