i did not get the logic why we are taking small displacements in the second question... maybe analytically if the answer satisfies small displacements then it is valid for large displacements as well.. but to judge that the small displacements case will suffice how to do intuitively see that in the beginning of the question?
It's not a homogenous mass system - 2m mass ring and m mass at a corner means it's centre of mass is not geometric centre. Look at question order too.. First ring is said to be kept (stationary) then the mass m is mounted. Therefore it is undergoing small displacements.. This is wt I think..
@@JaswanthSaiUppalapati yes brother what you are saying is correct, but my doubt was that we wanted to find r/R such that slipping does not occur right? so we are taking displacement from the centre and finding minimum value of r/R. but my main doubt is that how do we know that we will get the minimum value of r/R with small displacements, the minima may exist for a larger angle and i asked for the justification of that.
Small suggestion: Make the thumbnail more bright and large so that diagrams are clearly visible Will help to attract more students to such wonderful sessions
How did you take the exit velocity to be V2 in the derivation of impulse equation and then claimed the outlet velocity to be equal to inlet velocity? Please clarify.
It's just continuity equation Av= constant. In the problem A is not varying so v remains the same at all cross sections. With the derivation I wanted to point out it's outlet velocity - Inlet velocity that way it looks cleaner.
@@Phyx_IITM If outlet velocity is equal to the inlet velocity,then shouldn't the impulse be zero? Sorry if I am being too oblivious, also l have been watching your videos for a while, keep up the good work.
Bhaiya how can we say that that small dm mass would have constant velocity for dt time as that body is accelerating, I mean is there any general statement for it
Its just that when the vanes speed is u let's say after dt sec it's speed will be u + adt. We are adding a differential term to a finite quantity right so we can neglect that term for the small time dt . Like adding 0.0000001 to 5
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This question would have become more interesting if coeff of fr was given and then v as a fn of time was asked .
Saleem student
i subscribed you because of this video
He eats jee advanced qs for breakfast 😂
Great content, thanks a lot
Hey can you make more videos on liquid type questions they’re very interesting. Also great job 👏
Bhaiya please upload questions of electrostatics, wave optics or class 12 th related
Gokul bhaiya back with 1/cos c questions
Goat 🐐
Thank you ❤ for this types ❤❤❤❤❤❤❤❤❤❤❤❤😊😊😊😊😊😊😊😊😊😊😊
Thanks bhaiya
7:29 but why can't i use mb dvb/dt= Q(v-vb)? Isn't it the same thing? Just vrel dm/dt... Then you get an exponential
Sir how long do you take to solve these problems?
i did not get the logic why we are taking small displacements in the second question... maybe analytically if the answer satisfies small displacements then it is valid for large displacements as well.. but to judge that the small displacements case will suffice how to do intuitively see that in the beginning of the question?
It's not a homogenous mass system - 2m mass ring and m mass at a corner means it's centre of mass is not geometric centre. Look at question order too.. First ring is said to be kept (stationary) then the mass m is mounted. Therefore it is undergoing small displacements.. This is wt I think..
@@JaswanthSaiUppalapati yes brother what you are saying is correct, but my doubt was that we wanted to find r/R such that slipping does not occur right? so we are taking displacement from the centre and finding minimum value of r/R. but my main doubt is that how do we know that we will get the minimum value of r/R with small displacements, the minima may exist for a larger angle and i asked for the justification of that.
A suggestion:
It would be helpful if you make video on a particular chp/topic!!
Yea I'll do that from now 😁 realised this was getting very random 👍🏻
@@Phyx_IITM Yah
@@Phyx_IITMcn u make video on the topic of 3-d rotational motion or shape of string between 2 pegs
bhaiya could you please add topics to video so that we know which chapter are they from
Sir solve mixed problem from all chapters
Sir can you please please continue CYU series??
Sir please videos ko chapters wise arrange kar do😢
For first question, why was pseudo force in accelerating frame not included?
Goat of physics
Small suggestion:
Make the thumbnail more bright and large so that diagrams are clearly visible
Will help to attract more students to such wonderful sessions
Hllo sir just found our video i am 25 asp can u suggest how to start from channel as there are many video pls tell imporatn ones which one i should do
Is FIITJEE AITS (Adv.) 2025 already concluded?
Don't think so
How did you take the exit velocity to be V2 in the derivation of impulse equation and then claimed the outlet velocity to be equal to inlet velocity? Please clarify.
It's just continuity equation Av= constant. In the problem A is not varying so v remains the same at all cross sections. With the derivation I wanted to point out it's outlet velocity - Inlet velocity that way it looks cleaner.
@@Phyx_IITM If outlet velocity is equal to the inlet velocity,then shouldn't the impulse be zero? Sorry if I am being too oblivious, also l have been watching your videos for a while, keep up the good work.
From where I can strong my concepts to do this type questions pls reply
Fitjee aits ur are taking about?
Bhaiya how can we say that that small dm mass would have constant velocity for dt time as that body is accelerating, I mean is there any general statement for it
Its just that when the vanes speed is u let's say after dt sec it's speed will be u + adt. We are adding a differential term to a finite quantity right so we can neglect that term for the small time dt . Like adding 0.0000001 to 5
🙏thanks bhaiya for your reply
woahh
😮
Black wheel