02. Nephron Structure: Renal Corpuscle
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- Опубликовано: 4 сен 2024
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Video Summary:
Going ahead with structure of nephron. In this video we will study structure of renal corpuscle in detail. We will see glomerulus, its afferent and efferent arterioles, glomerular endothelial cells, glomerular basement membrane, structure & parts of Bowman's capsule viz. visceral epithelial later (podocytes), Bowman’s space and parietal epithelial layer.
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DISCLAIMER: This video is for education purpose only. Although every effort is made to ensure accuracy of material, viewer should refer to the appropriate regulatory body/authorised websites, guidelines and other suitable sources of information as deemed relevant and applicable. In view of possibility of human error or changes in medical science, any person or organization involved in preparation of this work accepts no responsibility for any errors or omissions or results obtained from use of information in this video.
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A doubt regarding proximal convulated tubule
Removal of proximal convoluted tubule from the nephron will result in
a)more diluted urine
b)more concentrated urine
c)no change in quality or quantity of urine d)
no urine formation.
The ANSWER is given to be " a "
EXPLANATION is as follows
as maximum water re-absorption (approx 67%|) takes place in PCT, it's removal will result in dilute urine.
My QUERY:
But why are not we considering the Na+ re-absorption? That's maximum in PCT as well (about 65-70% ).Removal of PCT will cause retention of these ions and won't it make urine more concentrated??why is option b incorrect?
Hi Zoya, I agree with your doubt partly. Although the explanation to the answer (a) is not satisfactory, removal of PCT, shouldn't produce concentrated urine either. The reason is, PCT is freely permeable to water, so wherever solutes go, water follows. Because of that filtrate leaving PCT is iso-osmotic even in presence of PCT. In absence of PCT, similar iso-osmotic filtrate will directly enter into the later part of nephron. So relative solute and water reabsorption in PCT is out of discussion in my opinion.
Although I couldn't find satisfactory answer anywhere, here is my opinion: I still think that removal of PCT should produce dilute urine, although explanation is different. Removal of PCT will leave that 67% of water (with solutes) into the tubule unabsorbed, resulting in faster filtrate flow in loop of Henle and that should wash out the medullary osmotic gradient. Without osmotic gradient, kidneys will produce dilute urine.
Will update if I get alternative explanation.
I did not understand the following
"Removal of PCT will leave that 67% of water (with solutes) into the tubule unabsorbed, resulting in faster filtrate flow in loop of Henle "
why should it result in faster filtrate flow in loop of henle?
Normally 67% Na and water is removed from PT. So out of 125 ml filtrate, 83.75 ml will get reabsorbed in PT and 41.25 ml will enter into the loop of Henle every minute. Means incoming flow in loop of henle will be 41.25 ml/min. Now if you remove PT, all 125 ml filtrate will go into the loop of Henle. So flow will be 125 ml/min, which is almost 3 times as faster. With this high flow, more water would reach the inner medulla and dilute it. We know that medullary gradient is used to concentrate urine in CD. So when medulla itself is dilute, urine will also be dilute.
2nd rather simple though process is, parts other than PT are relatively less permeable to water as compared to Na. You see, only descending limb of loop of Henle freely is permeable to water. Ascending limb and DT have very restricted water permeability. In CD water permeability depends on presence of ADH and its not fully permeable all the time. So evantually, more solutes would be reabsorbed down the tubule as compared to water resulting in dilute urine.
Again these are just my opinions. But yes, ultimately i think it should produce dilute urine.
thank u so much for taking your time to write such a detailed answer. It makes so much sense now. thanks again
one more explanation I have come to know. That's osmotic diuresis. As pct is removed glucose which is reabsorbed 100 percent in pct , will not be reabsorbed. This excess glucose accumulates in the tubules within the kidneys. Once there, it blocks the reabsorption of water, leading to an increased concentration of water in the bloodstream. The kidneys then act to remove the excess water, causing dilute urine.
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can i provide link of your video in one of my videos ?
Yes, sure. Do share link of that video here also. Thanks
Good video but explanation is hard to understand
Thanks for comment Stephen. Can you please suggest why it is so and how can it be improved?
Periodically throughout the video but especially at the 0.51 mark, closed captioning would have been really helpful.
Thank you for pointing it out. I have added captions for this particular video.
@@NonstopNeuron that really helped a lot, I finally get the concept. Thanks!
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