You just have to rewrite the function into e^(ln 2^x). It's equivalent to 2^x. After rewrite it into e^(ln 2^x), we can bring the x down using logarithm property, and it would be e^( x*(ln 2) ). Then, we can differentiate this exponential functions using chain rule and still be getting the same answer.
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Never heard ln pronounced "lawn" before.
Its actually also a general formula:
d(a^x)/dx = a^x(ln(a))
Why you have only a hundred subscribers 😭😭😭
PS: I really like your videos please don't ever stop doing them
I just started this channel a month ago. Thanks for your support anyway! I'll be uploading as frequent as I could.
not a fan of lawn. just call it log. log = ln. if the base is not e, then say log base b. we just get rid of bases not e anyway in most applications.
Use first principles.
Couldn’t you just use chain rule?
Actually, chain can be used as well!
You just have to rewrite the function into e^(ln 2^x). It's equivalent to 2^x. After rewrite it into e^(ln 2^x), we can bring the x down using logarithm property, and it would be e^( x*(ln 2) ). Then, we can differentiate this exponential functions using chain rule and still be getting the same answer.