As many others have stated, thank you for making this very easy to understand. It's fascinating how many bad profs there are out there attempting to teach this. If you think about it, it's not that hard but for some reason, many people struggle to explain this properly because they do not spend the time like you did to make it accessible. Again, thank you for doing this.
You turned convolution from a dreaded enemy to an important ally which springs up to rescue while performing inverse laplace of evil looking functions. You sir, are a hero.
Starting from 10:06 when you starting evaluating the integral & on the second line, the last part should have read: -0.5*TAU*cost t, because your're integrating w.r.t. TAU. Anyways, thanks v. much for all your efforts. God bless!
Just yesterday I was searching for a vid on convolution for my ODE class. Today this new vid popped up in my feed. I'm using it to replace the one I found yesterday, I suppose I should watch this one first, but that's not really necessary. If it is a Trefor Bazett vid, it is good.
at 10:00 I think you made a mistake in trigo identity, it should be (a-b) also (a+b) to prevent confusion. This identity is product to sum formula if I recall correctly
Little known fact: the verb for convolution is "to convolve," which means to roll something together. Although it absolutely also "convoluted" the two functions - meaning making something more difficult to understand, it is not what it intend to do :-D
Believe it or not, probability brought me here. I was looking for a more rigorous definition of a convolution. I never studied the Laplace transform. Interestingly enough, two nonnegative RVs that have the same Laplace transform have the same distribution.
I know what you meant fam, I saw the mistake in the video too. If you check the trigo identity he posted at 10:00 its (b-a) it should be (a-b) you'll arrive at 2T-t
If limit has between negative infinity to t in the convolution formula instead of negative infinite to positive infinite, should we call LTI system? Please reply.
Thank you for the explanation. There is just one thing which is bother me. Sometimes speak rate is very fast then it becomes slow suddenly. Sometimes I couldn't understand that I needed to slow the video and it can be distructor.
I don't know. The definition of convolution is integral from 0 to t, or from -inf to +inf? In different sources, it's defined differently. Can someone explain?
@@tjk581 But the Laplace transform only cares about the values of f(x) for positive x, so you can define f piecewise so that it is sin(x) only for x > 0, giving the result in the video.
As many others have stated, thank you for making this very easy to understand. It's fascinating how many bad profs there are out there attempting to teach this. If you think about it, it's not that hard but for some reason, many people struggle to explain this properly because they do not spend the time like you did to make it accessible. Again, thank you for doing this.
You turned convolution from a dreaded enemy to an important ally which springs up to rescue while performing inverse laplace of evil looking functions. You sir, are a hero.
😭😭😭
I like your t-shirt haha
You just explained convolution 100 times better than my textbook and my professor! Thanks!!
Haha thanks!
Wonderfully explained. Time to do my final exam. Thank you once again.
Good luck!
This playlist and the ODE playlist have been getting me through this 5 week summer class
I hope you grow in popularity. Not that it should be needed, but I think many people would benefit from your insight. Thank you for your videos.
this came in clutch, you made it so simple while my professor made it super confusing so thank you Trefor
Haha thanks!
Starting from 10:06 when you starting evaluating the integral & on the second line, the last part should have read: -0.5*TAU*cost t, because your're integrating w.r.t. TAU. Anyways, thanks v. much for all your efforts. God bless!
A quite difficult (but so essential!) concept very well explained! Thanks!
Glad you enjoyed!
*Over
You cleared up all my confusion. Thanks a lot. ❤️❤️❤️
You’re welcome 😊
Best video on RUclips till date
You are single-handedly carrying all my math related subjects throughout my degree.
Just got yourself a new sub :) thank you for the concise way you explain things
Thanks for subbing!
Dr Trefor, as usual excellent videos, If there are any math/engineering students that don't "Ace" their exams it is THERE fault...Great JOB !
Thank you!!
if a = tau and b = t - tau, then how did you get b - a = 2tau - t? shouldnt it be t - 2tau?
You and Dr Peyam have best explanation of Convolution!
Great video. Thank you for sharing. Regards from Panama 🇵🇦
Just yesterday I was searching for a vid on convolution for my ODE class. Today this new vid popped up in my feed. I'm using it to replace the one I found yesterday, I suppose I should watch this one first, but that's not really necessary. If it is a Trefor Bazett vid, it is good.
Dr. Trefor....
First of all, I like your T-Shirt.
Thank you very much for sharing the knowledge.
Wow. Only if the classes were this good.
As usual outstanding...❤❤👏👏
Great explanation! and also I liked the t-shirt..
Thanks so much. The example my teacher gived is so complicated and confusing. Your example helped me totally understand it.
So good, so far. Awesome!!!😄😄
Clear and concise.
Dr you really doing a good job...appreciate ur work.
..
You are of great help. Thanks
Your videos are so helpful doc ❤️🙏
What a concise explantation? Thank you Dr.
at 10:00 I think you made a mistake in trigo identity, it should be (a-b) also (a+b) to prevent confusion. This identity is product to sum formula if I recall correctly
Good stuff for my signals and systems class.
love from India sir !
Great explanations!
This was very helpful.
Thank you very much!!!!!
Nice T shirt sir, covered all functions 😊
Little known fact: the verb for convolution is "to convolve," which means to roll something together. Although it absolutely also "convoluted" the two functions - meaning making something more difficult to understand, it is not what it intend to do :-D
Believe it or not, probability brought me here. I was looking for a more rigorous definition of a convolution. I never studied the Laplace transform. Interestingly enough, two nonnegative RVs that have the same Laplace transform have the same distribution.
this is what i was looking for! thank you for the amazing video.
Thank you for your great work. Probably missing a little comment about the Domain of *.
Great video. 👍👍👍
Well explained. Thank you!
Professor Trefor your T shirt is fantastic. Can you please tell me where I can buy one?
Same haha, I was looking more at his shirt than listening to his explanation
I love ur T-Shirt!
Simply brilliant.
Everybody : let us revise for tomorrow's exam
Me at 12.am :
I'm sure I can't be the only one with this question. Where can we get that t-shirt? As always great video, thanks for helping those in need!!
Nicely done
Clear and Great
so what is the difference between multiplication and convolution
Great video as usual
very nice video.
Hello, thanks for the video, I appreciate it!
Btw, where did you get your t-shirt from? I like it, haha.
That was very helpful Dr. Bazzet, thank you. Can you please send me the link of the shirt you’re wearing? It’s amazing.
Dr, in your example, how can you get (2T - t) instead of (t - 2T) ? Help me out 🥺😭
Use trigo. Identities
from sin(T)sin(t-T)
let A=T & B=t-T
Then Subtract to get sinAsinB:
cos(A-B) = cosAcosB + sinAsinB
cos(A+B) = cosAcosB - sinAsinB
cos(A-B) - cos(A+B) = 2sin(A)sin(B)
sin(A)sin(B) = 1/2[cos(A-B) - cos(A+B)]
Then Substitute: (A = T ; B = t-T)
sin(T)sin(t-T) = 1/2{cos[(T) - (t - T)] - cos[(T) + (t - T)]}
Then you get:
sin(T)sin(t-T) = 1/2[cos(2T - t) - cos(t)]
Cos is an even function therfore cos(x) = cos(-x) for every x in R.
I know what you meant fam, I saw the mistake in the video too. If you check the trigo identity he posted at 10:00 its (b-a) it should be (a-b) you'll arrive at 2T-t
Whoah T shirt 👚 contains summary of one year of Mathematics.
6:25 but why is L[f(t) * g(t)] = F(s) . G(s) ? Is there a different derivation for this property??
I looked at your T-shirt more times than I used in the class.
At 4:00, how does dtau turn into negative du? Where did the t go?
Why do convolutions need to be so convoluted?
Please bring a video on generalized convolution ( reference t. M Apostol)
If limit has between negative infinity to t in the convolution formula instead of negative infinite to positive infinite, should we call LTI system? Please reply.
really well explained :)
Where did you get that your shirt from? I love it. I was hoping to see it in your store. Would definitely buy it if you're selling it
My wife actually gave it as a present years ago and I've never been able to find the exact one again!
@@DrTrefor Oh no! 😭
spent more time looking at the shirt than actually paying attention XD
Thank you for the explanation. There is just one thing which is bother me. Sometimes speak rate is very fast then it becomes slow suddenly. Sometimes I couldn't understand that I needed to slow the video and it can be distructor.
How did the sign of integral change? I did not get that part. What of we are integrating from -inf to inf??
I don't know. The definition of convolution is integral from 0 to t, or from -inf to +inf? In different sources, it's defined differently. Can someone explain?
If f and g are zero for negative values, then they are the same and the int from negative infinity to infinity is the same as 0 to t
@@DrTrefor But for evaluating convolution of f(x)=g(x)=sin(x) you used integral form 0 to t , when sin(x) isn't 0 for negative x.
@@tjk581 But the Laplace transform only cares about the values of f(x) for positive x, so you can define f piecewise so that it is sin(x) only for x > 0, giving the result in the video.
this was great
I like your T shirt!
10:15 what happened to the tau in the interation
I need to solved this integral and it really confuses me. I don't understand that t-tau part being in the argument.
Although I might not understand much of this yet, I'm beginning to grasp how to do the calculations
Thanks so much.
May I know where can I buy your t-shirt? It's so cute! (That blue one with many common math functions. )
I like your shirt!
Where can l get that T shirt ?
Thank you
what about differential property? time shift and fourier ? halpp ;u;
Thank you Marc Gasol
How did you get -(1/2)tcost?
Where can we buy the T-shirt you wear ☺️?
I heard another term called polynomial mutiplication used exchangable with the convulution.Are they the same or different?How do they relate?
Nice !
life saver
where did you get this Tshirt, professor?
6:20 Can we also say that this is an isomorphism?
@@DrTrefor Got it. Thank you!
where can i get this shirt?
Where can I get that t-shirt?
Oh thanks I'm taking electricity course and I'm using it very much
@@DrTrefor yeah of course it's almost all EM based on laplace transform for signals....
Hi, how is this related to a convolution in a Convolutional Neural Network?
I subbed for the shirt, stayed for the video
nice shirt btw, where can I get it?
I'm wondering the same thing
the only thing wrong with this video is we still don't know where to get the epic t-shirt.
🔥🔥🔥
your shirt but y is the indicator function on a dense set :)
How we get 2j-t, shouldnot be t-2j ?? 10:01
Use trigo. Identities
from sin(T)sin(t-T)
let A=T & B=t-T
Then Subtract to get sinAsinB:
cos(A-B) = cosAcosB + sinAsinB
cos(A+B) = cosAcosB - sinAsinB
cos(A-B) - cos(A+B) = 2sin(A)sin(B)
sin(A)sin(B) = 1/2[cos(A-B) - cos(A+B)]
Then Substitute: (A = T ; B = t-T)
sin(T)sin(t-T) = 1/2{cos[(T) - (t - T)] - cos[(T) + (t - T)]}
Then you get:
sin(T)sin(t-T) = 1/2[cos(2T - t) - cos(t)]
Great video, but actually I think sin function on your T-shirt is flipped, it is -sin ))
Awesome shirt