Worked example: Determining a rate law using initial rates data | AP Chemistry | Khan Academy
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- Опубликовано: 11 окт 2014
- The rate law for a chemical reaction can be determined using the method of initial rates, which involves measuring the initial reaction rate at several different initial reactant concentrations. In this video, we'll use initial rates data to determine the rate law, overall order, and rate constant for the reaction between nitrogen dioxide and hydrogen gas. View more lessons or practice this subject at www.khanacademy.org/science/a...
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Helped so much!! Doesnt make sense that I pay thousands for tuition, only to come to Khan Academy to learn for free!
absolutely right! going to donate a huge amount after I grow up
thank god for khan academy. The tutoring service, Study Edge, at UF is crazy expensive and I was worried that i would fail my exam just because I can't afford it but Khan Academy is helping soooooo much.
This is what I don't like how education has a price!
Awesome tutorial! Way more simplified explanation than textbooks!
Brilliantly articulated 🤝🏅🔥
Even after 8 years, this channel is underrated
may be 9 😊
Wow this was so helpful 👏
this was very helpful thank you Khan
Thank you for your help!!
Thank You 😎
fucking brilliant mate. this was a life saver
Too bad I cannot use a calculator on the MCAT
wow. this is what was went over in 2 lectures. saving my grade!!!
that is amazing
Khan academy videos are always the best! Thank you!
THANK YOU!!!!!
no u
thank you
I love y'all
just saved me ass, its 7am and i have a quiz on this today 😭thanks so much
Hi, if we arent given the experimental data how to determine the orders
and can you give an example of methane and air order of reaction
order of oxygen
Anybody know where I can get some sample problems?
Zeke Skulski Do you have a text book? Usually in the chapter there are practice problems.
I had a question where my rate constant units were mmol^(-5/2) L^(5/2) s^(-1)
How do I change this into the sensible mmol L^(-1) s^(-1)??
that was just amazing man, seriously you should charge us for these stuff.
what do you do if the rate determine step is the second step?
Tqq sir
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hey, isn't 250 * 0,012^2 * 0,006 = 2,16*10^-4 ? (the answer to the last part of exercise)
KvotheTheVegan Its to 2 decimal places
What if you get something like k [Y]^ x [Z]^ y? The data gives me 2^x = 2.5. Then x would approximately be 1.322 to get 2.500 on the calculator. If I end up with k [Y]^ 1.322 x [Z]^2, would the order of Y be 1.32 or 1?
I love you.(sobbing)
What if we get a fraction?
omg thank you sm! this made 0 sense to me in class lmao
7:27 RIP, my teacher would dock marks with a big smile for saying ".005 M" for sig figs because it's supposed to be "0.0050 M"
:)
Is it possible to get the rate constant if one of the concentrations was never kept constant
For u lazy bois out there u can do ( ln ((r1/r2) ) / ( ln ( [1] / [2] ) )
[ ☆ ] Concentration
1 and 2 is for experiment 1 and 2 not other substance
r stands for initial rate
Make sure the concentration of the other reactant stays the same and this will give u the order of reaction without any thinking necessary
BRO thank u i couldn't understand my **** professor.
God bless
God bless again (exam edition)
Asalam-O-Alaikum.....thank u sooo much......but.....isn't there anyway to find the order of reaction without experimental values???
There is not
omg Can you be my chemistry prof please
But what if we have no rates to compare to?
Please you did not make use of the temperature
exactly why i donate lol
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