Probability a Red Ball Source and person speak Truth 3 out of 4 times Bayes Theorem Application
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- Опубликовано: 13 май 2018
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Q1. Bag A contains 3 red and 4 green balls.
Bag B contains 4 red and 5 green balls.
One ball is drawn at random from one of the bags and found to be red. What is the probability that it was drawn from Bag A?
Q2. A man is known to speak truth 3 out of 4 times.
He throws a die and reports that it is a six.
Find the probability that it is actually a six.
Tq so much Anil Sir for perfect n clear explanation ☺
Nice sir I AM your new subscriber
TQ so much sir
Box 1 contains two red balls and three green balls . Box 2 contains 4 red balls and 1 green ball . One ball is picked at random from box one and placed in box 2. Once more a ball is picked at random from box 2. Determine the probability that the ball picked from box 2 is green...(hello sir would you help me with this pliz?)
you are the best, thank you.
Thanks
Sir how can i find your book pdf
Tq sir 😊
Suppose one ball is picked at random from a box containing 60 balls with 15 in red, 15 in blue, 15 in yellow and 15 in green.Suppose the balls are marked with numbers ranking from 1 to 20 for each color, namely for each number there are fours balls in red, blue, yellow and green separately. Let A denote the probability of obtaining a ball with a number 20, and let B denote the probability of obtaining a ball in red color. Calculate P [A or B]. Can you help me with this?
Thankyou sur i understood the concept very clearly
Wow thank you for that...
Life saver
Clearly explained the concept 👍
Great sir
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Thanks
A company learns 1 out of 500 of their products are defective or 0.2%.
A company buys diagnostic tools that correctly identifies correctly positive defective part 99% of the time.
If a part is diagnostic defective what is the probability of defective parts??
Thq
good
very clear with bags, but the second example is not clear at all... I cannot see Bayes formula at all.
Thanks for the feedback. Will look in that.
Second example does not have conditional probabilties on the right side of the equation.
Probability 1/2 ela vachindi sir
Probability
In campus interview, there are 50 candidates,10 from M.E, 10 from A.E, 30 from EIE. The recruiter finally issued offer letters to 14 candidates. Find the probability that all selected candidates belonged to only EIE?
Answer for this question sir,,
I'm getting 0.00015636
Total number of candidates are = 50 + 10 + 30 = 90
14 are being selected.
If all are selected from EIE then n(EIE) = 30C14
Total possible combinations are n(S) = 90C14
Therefore P(EIE) = 30C14/90C14
Tq Soo much sir
But total number of candidates are 10+10+30=50.
So answer is 30C14/50C14.
8 letters are to be placed in 8 addressed envelopes.if letters are to be placed randomly into envelopes. What is probability that none of 8 letters are placed into wrong envelope?
30C14/50C14, Your answer is correct.
Choooran question from comprehensive
Share some questions from your comprehensive. Thanks
Are 😌😌 written mai to solve kr dete 🤮🤮
WinBUGS code for Q1:
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