Your videos are so good.I would love to see your videos on topics such as Engg.dynamics and vibrations as well.I have been following your videos past few months and they all are super awesome.
The design of most structures are standard, for typical applications. Then depending on the load to be handled, the size and strength of the members need to be correctly chosen. (We have to calculate the stress and strain on each member to make sure they can handle it.
Due to a lack of time, we prefer communicating via comments. (But always start a new comment instead of attaching it to an old one, otherwise we may not see it (we receive a lot of comments)).
Dear Michel van Biezen, i have a school assignment that looks the same what here happens. Only i have a hinge point with a pulley on the end. Is it possible that i can make a picture of it and send it to you? And why i can't ask it to my teacher? I don't believe the answers are true what he gave me. And i say it to him but i make him more angry. So..... help me, please Greetings Mike
Instead of 2 forces A and B i have then 3 forces A, B and C. On the point were the weight is, is now the hinge point. The lowest and the upperst beam go through the hinge point. So they cross each other. The lowest beam is then above the other one. On the end of the lowest beam ,that now above the other one is, is a pulley. On that pulley is a weight. And the weight is attach on the beam below. I want to send the picture to you, to make it clear. Only it doesn't work on youtube, so sorry for that. So my question: what happens on point C? Is on point C a force on the Fcx direction? Greetings Mike
Hold a ruler between your thumb and finger only. Have the rules point horizontally away from you. Now push up on the other side of the ruler. The ruler will rotate between your thumb and finger. In that case the direction is counter clockwise. (that means a positive torque (or moment))
You said" we should neglect consideration of reactions at pivot joint". But, in this example you taken the reactions at pivot point. Can you explain it clearly ? Sir.
To find the torque, you do NOT include the forces at the pivot point. But when you use the sum of the forces in the x-direction of the sum of the forces in the y-direction then you MUST include them as well. Also not that you can pick different pivot points which means that you will have to include any forces who's line of action does not go through the chosen pivot point.
It doesn't matter what direction you choose initial for FAx. If the actual direction is opposite to the one initially chosen, the answer will be negative indicating that the actual direction is in the opposite direction from the chosen direction as seen in the video.
Sir i got F(a)x in positive direction , i put the direction of F(A)x in X but in negative direction at the first place because the Pin at point A hold the force from the mass , so i make it F(A)x in negative direction and Fay in positive direction which the opposite from force from the mass the calculation comes like this , Mb=0 -F(A)x . 2 + 10kN . 3 + 25kN . 8 = 0 ( clockwise mean positive ) and got Fax = 115kN, not -115kN could you explain more about how we can make decision to choose the direction of force? why you put F(A)x direction to positive line X at the first place ? thank you very much Sir
Naufal Ramadhan The reason he got a negative is because his arrow Fax actually acts in the opposite direction. You got a positive number because you chose the correct direction of Fax in the first place.
The convention is that a clockwise moment (or torque) is negative. If you just calculate the magnitude it doesn't matter as long as you stay consistent through the problem.
This appears mathematically wrong. There is no account of the angles involved as the non-horizontal nature of the crane beams introduces Vector forces in the X & Y Directions.
You're the embodiment of god, a true perfect being. Your acts of self-less education are seen as a transgression of the highest degree against educators who consistency fail to educate their pupils. You and Organic Chemistry Tutor are raging a crusade with the sole purpose of empowering engineering students who lack sleep, and proper mechanisms for self-education through classical college resources. God speed Miachel Van Biezen, and may the lord forever be in your grace.
You're so underrated.
Your videos are so good.I would love to see your videos on topics such as Engg.dynamics and vibrations as well.I have been following your videos past few months and they all are super awesome.
Thanks for the comment. We are working our way through many topics. We hope to get to those in the future.
I have a question. since we found the acting forces Fax, Fay, Fbx, how we can come up with the design that complies with the forces?
The design of most structures are standard, for typical applications. Then depending on the load to be handled, the size and strength of the members need to be correctly chosen. (We have to calculate the stress and strain on each member to make sure they can handle it.
@@MichelvanBiezen Do you have fb messenger or telegram? can i connect with you?
Due to a lack of time, we prefer communicating via comments. (But always start a new comment instead of attaching it to an old one, otherwise we may not see it (we receive a lot of comments)).
i want to send sample image. please
I understand it so much better now
YOU ARE THE BEST
Awesome!
excellent !
Glad you liked the video!
But which forces is counteracting the forces of F(A(x)) and F(B(x))?
FBx is keeping the crane from rotating, and FAx also keeps the crane from rotating
Why when you sum moments here you don't include a term for moment at A but when you sum on a cantilever beam you include a moment about A?
Since all the forces acting on A go through the "pivot point", they do not contribute to the moment since the do not have a moment arm (d = 0).
Dear Michel van Biezen, i have a school assignment that looks the same what here happens. Only i have a hinge point with a pulley on the end. Is it possible that i can make a picture of it and send it to you? And why i can't ask it to my teacher? I don't believe the answers are true what he gave me. And i say it to him but i make him more angry. So..... help me, please
Greetings Mike
We sometimes respond to questions if time permits. can you describe the problem?
Instead of 2 forces A and B i have then 3 forces A, B and C.
On the point were the weight is, is now the hinge point. The lowest and the upperst beam go through the hinge point. So they cross each other. The lowest beam is then above the other one. On the end of the lowest beam ,that now above the other one is, is a pulley. On that pulley is a weight. And the weight is attach on the beam below.
I want to send the picture to you, to make it clear. Only it doesn't work on youtube, so sorry for that.
So my question: what happens on point C? Is on point C a force on the Fcx direction?
Greetings Mike
Dear sir, I am really getting the problem about finding the direction of the moment in the 3D problem. May you help me, please? thanks
Hold a ruler between your thumb and finger only. Have the rules point horizontally away from you. Now push up on the other side of the ruler. The ruler will rotate between your thumb and finger. In that case the direction is counter clockwise. (that means a positive torque (or moment))
@@MichelvanBiezen thanks sir.
@@MichelvanBiezen clockwise is positive, right?
Are there other cases when the moment is 0 when they are not fixed on the wall for this example? Like would a normal force have a moment of 0?
+Conrad Pro
The requirement is that the object does not move (or accelerate) and that it does not rotate.
You said" we should neglect consideration of reactions at pivot joint". But, in this example you taken the reactions at pivot point.
Can you explain it clearly ? Sir.
To find the torque, you do NOT include the forces at the pivot point. But when you use the sum of the forces in the x-direction of the sum of the forces in the y-direction then you MUST include them as well. Also not that you can pick different pivot points which means that you will have to include any forces who's line of action does not go through the chosen pivot point.
I could not understand the direction sign chosen for F(Ax). please help
It doesn't matter what direction you choose initial for FAx. If the actual direction is opposite to the one initially chosen, the answer will be negative indicating that the actual direction is in the opposite direction from the chosen direction as seen in the video.
Thank you
Sir i got F(a)x in positive direction , i put the direction of F(A)x in X but in negative direction at the first place because the Pin at point A hold the force from the mass , so i make it F(A)x in negative direction and Fay in positive direction which the opposite from force from the mass
the calculation comes like this , Mb=0
-F(A)x . 2 + 10kN . 3 + 25kN . 8 = 0 ( clockwise mean positive )
and got Fax = 115kN, not -115kN
could you explain more about how we can make decision to choose the direction of force?
why you put F(A)x direction to positive line X at the first place ?
thank you very much Sir
Naufal Ramadhan The reason he got a negative is because his arrow Fax actually acts in the opposite direction. You got a positive number because you chose the correct direction of Fax in the first place.
@@mode1charlie170 okay , i finally understand ,thank you very much sir
Clockwise is positive right?
The convention is that a clockwise moment (or torque) is negative. If you just calculate the magnitude it doesn't matter as long as you stay consistent through the problem.
@@MichelvanBiezen oh. Thank you sir
This appears mathematically wrong. There is no account of the angles involved as the non-horizontal nature of the crane beams introduces Vector forces in the X & Y Directions.
The video is correct. (No angles needed here).
@@MichelvanBiezen kindly explain why sir coz i dont know why
You're the embodiment of god, a true perfect being. Your acts of self-less education are seen as a transgression of the highest degree against educators who consistency fail to educate their pupils. You and Organic Chemistry Tutor are raging a crusade with the sole purpose of empowering engineering students who lack sleep, and proper mechanisms for self-education through classical college resources. God speed Miachel Van Biezen, and may the lord forever be in your grace.