@@Lilyofc No it's protect itself. It has a special meaning. When something is so cute and makes you feel warm on the inside that you want to hold them in your pocket. Or in other words, makes you feel UwU. Sort of makes that person seem like an cute thing. He should be protected from all the negative things in the world
Method 2 As point of intersection of asymptotes is centre of HB therefore find the centre and substitute in given eqn of asymptote and check which option satisfies. Centre can found by partial differentiation Like here Differentiate keeping x constant x-2=0 ----(1) Differentiate keeping y constant y+3=0 -----(2) From 1 and 2 Centre is (2,-3) Clearly option b satisfies the centre. Therefore, ans is B
This man is a freaking legend and his sense of humour is of another level. We should protect him at all costs ❤️❤️❤️❤️🌟
You're damn right😂❤️
Protect ? Or support 😂😂
@@Lilyofc No it's protect itself. It has a special meaning.
When something is so cute and makes you feel warm on the inside that you want to hold them in your pocket. Or in other words, makes you feel UwU. Sort of makes that person seem like an cute thing.
He should be protected from all the negative things in the world
@@TheLegendaryMPGI've heard about Protecc*
@@TheLegendaryMPG xDDDDD
"As simple as that" has a dedicated fanbase
How many fans?
@@GengRizzKhan 🤣
CENTRE = (-1 , 2/3 )
Method 2
As point of intersection of asymptotes is centre of HB therefore find the centre and substitute in given eqn of asymptote and check which option satisfies.
Centre can found by partial differentiation
Like here
Differentiate keeping x constant
x-2=0 ----(1)
Differentiate keeping y constant
y+3=0 -----(2)
From 1 and 2
Centre is (2,-3)
Clearly option b satisfies the centre. Therefore, ans is B
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centre of the circle (-1,2/3)
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Center of the circle =(-1,2/3)
10:38
Centre = (-1 , 2/3)
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Centre (-1,2/3)
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Center = (-1, 2/3)
Thanks❤️
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Thank you so much ❤️❤️🔥🔥
(-1,2/3)
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-1,2/3
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(-1,2/3)
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(-1,2/3)