16:17 You explained very well sir , there are 4 more cases possible when both the observer and the source are moving . 1. When both the observer and the source coming towards each other. f/f'=(V+Vo)/(V-Vs) 2. When both the observer and the source going away from each other. f/f'=(V-Vo)/(V+Vs) 3. When observer coming towards the source and source is going away from observer. f/f'=(V+Vo)/V+Vs) 4. When the observer is going away from source and source is coming towards observer . f/f'=(V-Vo)/V-Vs)
Mujhe is tarah ke chapters jaldi samjh nhi aate the but aapki vajah se bahut acche se samjh me aa gya . Honestly aap bahut acche teacher ho science ke jo live example ke sath bde easily concept clear kar dete ho short time me. Thanku so much sir
fo=1473.21 Hz Formula 2nd ,source moving away from the observer .fo=V/V-(-Vs)*fs where A/q V=330m/s Vs=6m/s fs=1500. fo=330/330-(-6)*1500 =330/336 *1500 =1473.21Hz.
F' mtlb shrota arthat sunne wala ki abhashi friquency mtlb avriti and f.mtlb vastvik avriti and v= dhwani tarag ki veg and vs = shrot dvara veg v0= sunne Wale shrota dvara veg
Also velocity of observer and source should be much less then the velocity of wave and both should be along the straight line, only then you can experience Doppler's effect!
Thank you Neeraj sir...🙏🙏❤️ आपने बहुत अच्छे तरीके से Animation के साथ बताया जो ये क्लास औरो से बेहतर सिद्ध साबित होती है..❤️❤️ Ans of the Qn 1473.21HZ✍️✍️
Fruit Vs Vegetable | टमाटर फल (Fruit) है…. कैसे ?
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4codition daopler prabhav me jab shrot arthat gadi rest me aur shrota sunne wala shrot se dur bhag Jaye tab abhashi friquency f'=[(v-v0)/v)]f
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16:17 You explained very well sir , there are 4 more cases possible when both the observer and the source are moving .
1. When both the observer and the source coming towards each other. f/f'=(V+Vo)/(V-Vs)
2. When both the observer and the source going away from each other. f/f'=(V-Vo)/(V+Vs)
3. When observer coming towards the source and source is going away from observer. f/f'=(V+Vo)/V+Vs)
4. When the observer is going away from source and source is coming towards observer . f/f'=(V-Vo)/V-Vs)
Mujhe is tarah ke chapters jaldi samjh nhi aate the but aapki vajah se bahut acche se samjh me aa gya .
Honestly aap bahut acche teacher ho science ke jo live example ke sath bde easily concept clear kar dete ho short time me.
Thanku so much sir
Hi
fo=1473.21 Hz
Formula 2nd ,source moving away from the observer .fo=V/V-(-Vs)*fs
where A/q V=330m/s
Vs=6m/s
fs=1500.
fo=330/330-(-6)*1500
=330/336 *1500
=1473.21Hz.
❤
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Crystal clear.
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Very must content
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Great approach n very helpful video
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Science aapse accha koi nhi samjha pata h thanks sir love u sir
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Home work Question Right Answer option 1473
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Nice teaching.. ❤️❤️
Gjb sir apki padai bahut achcha laga hai
330//330-(-6)×1500==1473.21 HZ,
(by second case)
TQ sir ji, nice session.🙏
F' mtlb shrota arthat sunne wala ki abhashi friquency mtlb avriti and f.mtlb vastvik avriti and v= dhwani tarag ki veg and vs = shrot dvara veg v0= sunne Wale shrota dvara veg
Aaj tak kisi ne aysa nhi smjhaya..sair jiii🙏🙏🙏🙏
Good class and nice animations use for example
Thank you sir ❤️❤️
For this video
Thanku sir aj Doppler effect pura clear ho gaya 🙏
Maza aagaya...😍😍thank u sirji..❤️❤️
Bhot achhe se samjh diye sir ji😊
Excellent topic sir🙏
Also velocity of observer and source should be much less then the velocity of wave and both should be along the straight line, only then you can experience Doppler's effect!
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Sir Aaj lab assistant me apki kripa se science ke 87que shi huye h.thanku sir ji 🙏
HW ans-1473.21 thankyou sir ji best video sir👍👍👍👍
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sir "Frquency, Weblenth , valocity,
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Frequency 1473.21 Hertz
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330×1500/336 Hz=1473.21 Hz
Sir if a source moving ➡️one side and sound producing opposite side ⬅️ then sir?
(330/336)×1500=1473.21 Hz
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1second me jitne bar dhwani me kapan ota hai use avriti
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2 garto ya 2 shringo ke beech ke duri ko tarang darthya khte hai
Thanks🙏❤ sir jii bahut achha h aise h Or class lijiye
Thank you sir 😀Ans-1473.21hz
Sir i understand 😁 very well thanku ❤️✨
I search this topic and i got 😊🎉
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This is so helpful.. thank you so much❤
330/ 330-(-6)*1500= 1473.21 Hz
& Tq sir ji
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Nice teaching 👌 sir
1473 Hz hoga frequency.
Kya aaisa bhi case ho sakta hai, jab source aur observer ek dusre ki aur aa rhe hain....?
Thank you so much sir ❤
1500×330/330+6=1473 approx
Answer: 1473.21 hz
U r genius sir👍🏻
Same as real frequency
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H0mew0rk..
F'= ?
Fs= 1500htz
V= 330m/s
Vs= 6m/s
F'= V/V+Vs× Fs
= 330/336×1500
= 1473.22m/s
Answer
Thanku so much sir ❣️
Level of sound is belongs to amplitude
1473 .21 Hz, tq sir ji and nyc session bhut helthful short video 🙏
Thank you so much sir awesome class! Ans-1473.21Hz
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Thank you Neeraj sir...🙏🙏❤️
आपने बहुत अच्छे तरीके से Animation के साथ बताया जो ये क्लास औरो से बेहतर सिद्ध साबित होती है..❤️❤️
Ans of the Qn 1473.21HZ✍️✍️
Observer ko sound 1473.21 hz ki moti frequency se sunai degi
330×1500/330-(-6)=1473 HZ approx
Nice class sir
Thanks sir ji
1/250hz...thnq. Sir. Ji. 🙏
Sir ham chahte aise aise small videos
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Sir ji class xi ka physics ka previous question paper ka revision Kara dete
1475 hz is frequency of the observer
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Ans of the day =330/336*1500=1473.21apx
Here;Vs=6
F= 1500Hz
V(in air) given=330
Thanqu sir🙏🙏🙏
Nice video sir
Ans- 1473.21 Hz ( approx)
1473.21 Hz is right answer sir
Nice sir
Thanks a lot.
sir ans 🙏🙏🙏 324/330 *1500 sir