Distance of a point to a line in 3D using 3 different techniques.

Demonstration of 3 methods of finding the shortest distance from a point to a line in 3D space. Thereby also revising a good amount of 3D vector content and application.
1. Using a perpendicular plane containing the point.
2. Using the scalar product to find a perpendicular vector.
3. Using the vector product to find the altitude of a parallelogram on the line.

[@205mlee]

By far the most extensive, helpful and intuitive method on finding the distance of a point to a line in 3D. Thanks!

[@CaptainZavec]

Helped me for the unit test a few months ago, and now for the exam. Thank you very much!

[@MallyGx]

That last method we use explains it so well!

[@darkness9484]

actually, with the 2nd method, you don't need to calculate t at all. you just need the minimum module of that vector, that is, minimize a quadratic equation. you know that the minimum is found at (-b/2a, -delta/4a), so the answer will be sqrt(-delta/4a). anyway, very good explanation :D

[@Usagimusical]

This was an excellent video! You have superb teaching skills!

[@visuaviewer]

Awesome video. Great to see 3 different ways to go about this problem. Technique 1 is very helpful as it gives practice to 4 "topics" in 12.5. Thanks for the video!

[@TheMatttm]

Great man, thanks!!

[@Svajok]

what a legend, thanks a lot

[@ShivamSharma0515]

Awesome video...really helpful!!! :)

[@nidhishgautam9043]

Fucking awesome

[@arunjyotisinharoy3449]

thank u vry much...:)

[@dmytro6080]

Really nice video.