Step 1: check if the fuses have green eyes. Step 2: Light both fuzes Step 3: Pretend to jump through the fence, but miss so that the second fence will prioritize the third fence over you.
My friend: Ted-ed is a brilliant channel that educates you in different aspects and inspires you to find a better version of yourself Ted-ed: You are a bank robber. You need to escape prison
I really appreciate that Ted Ed has riddles for different levels and skill sets. I have a traumatic brain injury, so I like to watch their riddles from time to time; it helps to keep my brain stimulated. Some days I have worse symptoms than others and I can hardly even speak. Other days, I almost feel like my old self again. Thank you for this. :)
@@Core_Of_The_Void You can do that by adding underscores "_" at each side of the word. _Example_ You can also use asterisks "*" to make them like this: *Example* Or hyphens "-" to make them like this -Example-
You know that the jail is housing weirdos when the prisoner can A) move Super fast B)unable to count to 45 seconds and C)knows that the fuse burns for exactly 60 seconds even when his watch is broken
@@brunobottoni9661 You can count, but you have no guarantee that your counting is an infinity precise measurement of time. For example, I tend to count seconds more quickly between 1-10 because the English words are shorter, and the counting slows down as I move to numbers bigger than 20. If you doubt it, try asking other people to count off a minute by the second and compare it to your watch. They're going to be pretty close, but I wouldn't be surprised if they ended the minute off by a second or more.
Plot Twist: The jail knows that some prisoners will try to escape using the method and makes each fuse burn out in 59 seconds. This means that the prisoners will go through the fence three-quarters of a second earlier and get electrified.
Prisoner: Doesn’t know how to freaking count 45 seconds Also prisoner: Knows that fuses he had can burn in exactly 1 minute and counts exactly the time where the flame should meet a certain destination
Here are 2 quick riddles for u. 1. The two doors You are in a room with two doors - a red one and a blue one. One door leads to freedom, the other one leads to a ton of worms that you have to eat if you open that door. There are two guards in the room - one always tells the truth, the other always lies. The guard that tells the truth knows that the other one always lies, and vice versa for the other. Both guards know which door is to freedom. You don't know which guard is which. You may ask one guard one question. What question can you ask either guard to guarantee that you go through the right door? The answer is below. Pretend the red door is to freedom. The question to ask is, "What door would the other guard say is to freedom?" This works because if you ask the guard that tells the truth, he knows the other one always lies and would say the blue door, so he truthfully replies, "The blue door." If you ask the guard that always lies, he knows the other one always tells the truth and would say the red door, so he lies and says, "The blue door." So, they both said the blue door... so go in the other one! 2. The three light switches. In the attic of an old house, there are three light switches. They control three lightbulbs in the basement of the house. How can you figure out which light switch goes to which lightbulb while only going in the basement once? The answer is below. Turn the first two switches on and wait ten minutes. Turn off the second one and go in the basement. The lightbulb that is on is connected to the first switch. Then, feel the temperature of the other two bulbs. If it's hot, that bulb is connected to the switch you turned on, then turned off. If it's cold, that bulb is connected to the switch you never touched. This took half an hour to type, (on mobile) so please like for my effort! Hope you enjoy your new found knowledge!
Yeah he should be a scammer, way less risk, at least he's not a sucker that slaves away half of his waking hours to procure the bare necessities required to do it again until he's too decrepit.
I have a habit of counting down the time in my head along with a timer without looking at the timer of course. I usually ask myself "Will I ever need to be able to count down as accurately as possible?". Now ted ed has given me the answer.
@Caesar And maybe you need to get your attention span tested. Considering you have the patience to read this entirely, I only have one advice for you - Watch the video again. Obviously the fact you're actually pointing me out for something the video so obviously states means u need more of that focus you're so desperate to prove others don't have. Btw, I'm a national badminton player, so yeah, maybe I don't have strong reflexes just like you don't have patience.
@@Aaron_Walker_011 Damn, no need to get defensive over such a little thing. Btw, I'm a national prodigy in every subject, so yeah, maybe I don't have smart brains just like you don't have pride.
Narrator: But his watch is broken.. how can he tell time with fuses and ligh- Me: 1) who gives their prisoners freaking watches and 2) Just count physically!
Have you ever tried to count any amount of time longer than 10 seconds and then checked your watch afterwards? You might get close, but it's very rare and very difficult to get it exactly.
I tie the lighter to the end of the fuse, and use my knowledge that a standard Bic lighter is 8cm long to measure out a 25cm pendulum. 45 swings and I go through the fence.
Jam Ham Time it’s funny. Calculating the period of a pendulum is surprising complicated. I don’t know what you know, it was a bit complicated for me, as I’m not very fluent in introductory level physics, but if I remember: You can think about gravity being the only non perpendicular force to the pendulum (if we ignore air resistance) and that will lead you to some sort of: angle’’ = a* sin (angle) Where angle’’ is the second derivative and a is a constant. This equation is one that I’m not sure there has been a solution to. So you probably won’t really find the exact algebraic solution to the problem. What you can do is approximate sin function around the angle 0 as a polynomial and try to use a pendulum that uses small angles as to keep the approximation the most accurate. With the approximation the differential equation can be solvable. The way others go is through conservation of energy, potential and kinetic energy considerations you can easily get an expression for the pendulums velocity at any angle. Great, so we can just integrate that expression to find the angle over time right? Well yeah but again I think it’s an unsolved if not impossible analytical problem, it ends up being an expression we don’t know a primitive for, and a such can’t integrate. The final answer is yeah we can use some sort of approximations in various ways and easily get good approximations, especially with the use of computers. But it’s annoying for me at least, there doesn’t seem to be an exact analytical solution. Which is what this problem was kind of asking for. For a real life robber, one might know an approximated formula for a pendulums period that is has an error much smaller than the 1 second or so the robber has to pass the grid though.
@@aienbalosaienbalos4186 i think it's the conservation of energy that should help, which gives us that the potential at the top must be equal to the kinetic at the middle. Height reached = L * (1 - sin alpha), but then i've forgotten what the trick was for finding out the speed through the mean position. :"> Apparently, the formula we should get is T (in seconds) = 2 pi SQRT( L (in meters) / g )... so we get a length of g/(4 pi²) ≅ 248.237 mm. So now, @Ipek... what happens if the fuses are slow-burning, thus with a length smaller than what is needed for this? 😈
This is easily one of the best puzzles I've seen here. I took forever trying to solve this before finally giving in and unpause to see the answer I never thought of and then TED-Ed goes to say "Looking for something a little trickier?" :/ Although I did solve the Three Gods one.
Here is another solution: Although the fuse burns irregularly the amount of gas used by lighter should be constant. You light one fuse and keep the lighter on constantly until the fuse burns out. You note starting level of gas and finished level of gas and that distance is your one minute. You divide it into 4 and 3/4 of that will be your 45 seconds. You then turn on the lighter when you see the signal and once the level drops by 3/4 of a minute’s distance, you got your 45sec. Though I realise there is a flaw in this logic that the amount of gas used up in 1 min will be small and hence impossible to measure 3/4 of that amount accurately, but that would be another way to solve it if time to be measured is longer and the lighter is transparent:)
If cut a fuse wire into half i ll get 30 sec fuse .and cutting the 30 sec fuse i ll get 15 sec fuse.now i have 30+15 sec fuse ,after the 30 sec fuse burnt out lit the 15 sec fuse .This is my idea tell me if iam wrong
A) If you light any of the fuses at each end simultaneously, then each end burns until they meet at exactly 30 seconds. Why? Because if they meet after burning for x seconds, then each would have had x more seconds to go to reach the other end. Thus, 2x = 60 seconds, and therefore x = 30 seconds. B) Let us therefore designate the fuses as Fuse A and Fuse B. We light Fuse A at both ends and Fuse B at one end only, all simultaneously. It will be exactly 30 seconds when the flames from both ends on Fuse A meet up. At that point, the flame on Fuse B would also have burned for 30 seconds. We immediately at that point, light the other end of the Fuse B (We can even use the flame at the moment of meeting on Fuse A to do so). The flames (on Fuse B) will meet at exactly the 15 second mark following the same logic as explained in A). Thus, 45 seconds would have elapsed and voila! ... You are a free man!
Wow I might have actually solved it: 1. Take the second fuse and cut it in half, then align them so they are parallel with each other. 2. Light the first fuse on both ends at the same time. 3. Wait until the first fuse burns out, since we lit both ends that would be 30 seconds. 4. As soon as the first fuse burns out, light the left end of one half of the other fuse, and at the same time light the right end of the other half. 5. One fuse is burning left to right and the other fuse is burning right to left. The point that the fuses burned are aligned would be 15 seconds. For a total of 45 seconds. Edit: Oh, I guess i forgot there is nothing to cut the fuse with. Pretty close tho. :D
Hmm. I tied the lighter to one end of fuse A which I tied to something else (perhaps my finger). I lit fuse B, while dropping fuse A and counted the pendulum swings for the 1 minute duration of fuse B. So, 3/4 of that number of swings is 45 seconds... which I can perform any number of times because I never actually burn fuse A.
Thats more of a vacuum situation since there would be other factors into play like wind, viscosity, gravity and stuff. So might not be exact. But that's really creative.
To the people that say 'just count 45 seconds': It's actually alot harder than you think to count 45 seconds precisely, you'll either count it 1 second too late or 1 second too early, if it really were that easy, this wouldn't exist, listen to 0:41, if you make even the slightest miscalculation, you'll get deep fried and served with a side of chips, so no, you can't just count 45 seconds if the fence comes on 2 seconds later
I had a different solution. I figured you can find some way to count at a steady pace. It does not matter if your counting equals one second per number, it just needs to be steady. You burn one of the 60 second fuses while counting steadily. Whatever number you reach when it burns out, you divide by 4, because that will equal 15 seconds. You then light the second fuse and let it burn while counting to that same number that equals 15 seconds, then you put the fuse out. The fuse now has 45 seconds left on it, so you can use it when you get the signal to measure 45 seconds. The result might be slightly imperfect, but given that it takes time to light a fuse and get it burning, the TED solution also is inherently imperfect.
Commenting before watching: When the signal is given, light up both ends of fuse 1, and one end of fuse 2. After 30s, fuse 1 will burn out, while fuse 2 is supposed to burn for 30 more seconds. At this time, light up the other end of fuse 2. Now fuse 2 will burn out in 15s, so total 45s
That resolution wouldn't hypothetically work based on the stated conditions. If the fuses burn erratically, than one end of the fuse could burn for 59 seconds and then finally burn really fast to burn the rest in 1 second. So there would be no way of splitting one fuse into 30 seconds simply by lighting both ends. They contradicted themself with the answer....
Before watching answer: Tie one fuse in a circle and another in a figure 8. Light the circle so it burns at 2 ends, counting 30 seconds, then light the figure 8 as soon as it finishes, burning at 4 ends, counting another 15 seconds.
That would've worked except with the figure 8, each end of the lobe from the central point will take a different time to reach the other Flame. So neither lobe of the 8 will burn out in exactly 15 minutes.
I've solved it considering the preparation of the fuse instead of doing it "live" as the solution proposed: if you cut the first fuse in 4 pieces, and you light them all at both sides simultaneously, and together you light one side of the second fuse, it means that the fuse parts will burn in exactly 15 seconds (in the exact moment where the last burning part is completely burnt), so when you see these parts completely burnt, you extinguish the fire in the second fuse. So you get a partially burnt fuse which will last exactly 45 seconds, to light up at your needs :D And if you're considering the time that gets through when you're litting the fuses, you just need to bend them together in order to have all the tips rolled up towards the flame of the lighter. And if you're considering the mess that would this action probably generate, maybe the burning tip of one fuse that puts fire at the middle of another fuse part (or the second fuse), well you're a prisoner, things can go wrong in jail.
Sorry to tell you but it doesn't work for two reasons: 1: Burning 4 parts from both ends would give you a time of 60/8 = 7.5s, not 15s. Per your own logic you should burn the 4 parts from one side only to get a 15 second burn time. 2: It doesn't work since the pieces will burn of a variable length. Lets say one burns for 7.5s. It means it will go out well before the 15s has passed. This means that another piece will still be burning after 15s has passed and thus you have no way to verify when 15s actually has passed and when to extinguish the fire on the second fuse. Nice thinking though.
But if the timing has to be that precise (within a 1-2 second margin) you might as well just count to 45, since timing the fuses would be just as hard as counting to 45 give or take 2 seconds. The precision of lighting the fuses the INSTANT it dies will be just as precise as counting to 45.
Roughly count 45 seconds then touch the fuse to the gate afterwards, if it is electroc it will probably catch fire anyway so just cut the fuse to pieces for multiple tries and touch the fuse to the gate ater aprox 45 seconds. When it doesnt catch then it is safe to go. Just test that they burn properly when it is electric.
I remember this riddle when I was young my brother told us it I wished I could solve it but my father solved it in like 3 minutes and spoiled the answer
but i thought you said they burn "irregularly"? Meaning those fuses could burn 52 seconds on one end and 8 seconds on the other end. Or 24 seconds on one end or 36 seconds on the other end 🤔
Light both ends of Fuse 1 and one end of Fuse 2 at the same time. When Fuse 1 goes out, 30 seconds will have passed, then light the unlit end of Fuse 2. Fuse 2 will have 30 seconds left, and by lighting the other end, you halve that to 15. 30 + 15 = 45.
There's a contradiction in the solution. How can you assume the ratio of 30:30 from both ends. It could be 20 seconds from left and 40 seconds from right to meet, or 25 seconds from left and 35 seconds from right to meet or 10 seconds from left and 50 seconds from right to meet and so on. The prisoner doesn't have the watch right. This guy mentioned himself by taking example of one side burning in 20 sec and other in 40 seconds. Now he suddenly assumed 30 sec from both sides.
Hmmm I might just rely on my counting skills
Tian Wang ikr
That's one weird riddle.
Are you including Mississippi's?
ONE MISSISSIPPI, TWO MISSISSIPI...
I like how this comment was left at 666 likes, I saw a comment at 420 likes earlier.
“1 Mississippi 2 Mississippi 3 Mississippi...”
I AM OKAY WITH THIS OkayChamp 👍
works for me
My state!
My state!
Good for a rough estimate, but you need something that misses by less than a second or two--something reliable.
Step 1: check if the fuses have green eyes.
Step 2: Light both fuzes
Step 3: Pretend to jump through the fence, but miss so that the second fence will prioritize the third fence over you.
so green eyes and wizard standoff. nice references
Oh god these memes... But what if the second fence says Ozo, though?
@@GoldChipz Then you're screwed if you haven't figured out how to add to infinity.
@Orange ball you can counter that pretty effectively If you find the corrupted disk
@@rgxyz1233 but the zombies will get to you in about 17 minutes
Prisoner : Messuring time
Wind : Im about to blow this man's whole escape plan
J Ahn ok
J Ahn *measuring*
Heh... blow
Prisoner: *becomes toast*
burning time , not measuring
Think outside the box: Push the guard into the fence and while it's shorted, climb through.
This is a riddle not a jhon wick movie
Genuis
Best answer yet
Allan Zhao thats exactly what I thought
That's one way to do it
My friend: Ted-ed is a brilliant channel that educates you in different aspects and inspires you to find a better version of yourself
Ted-ed: You are a bank robber. You need to escape prison
Dum dum dum
Plot twist: Your friend is a robber.
LMAO
So that's it, a bank robber is a better version of me.
He just wants to teach you for IF you go to jail
Step 1: confirm that you have green eyes
Step 2: ask the prison guard to leave
wrong riddle
@@paulasantana8227 r/woooosh
lol is this supposed to be an allusion
OK I guess I'm uncultured because I don't get it
@J. Enrique Guerra well i just did so
but what if it takes me some seconds to lit the fuses?
what if my lighter jams
Well too bad
What if I don’t have a lighter
@@spyperneer7399 Use your Pyro kenisis from your draconic and/or demonic ancestors Duh. Anybody with a brain can figure that out
@@zealotoftheorchard9853 Oh yeah! I forgot about my pyro powers.
I really appreciate that Ted Ed has riddles for different levels and skill sets. I have a traumatic brain injury, so I like to watch their riddles from time to time; it helps to keep my brain stimulated. Some days I have worse symptoms than others and I can hardly even speak. Other days, I almost feel like my old self again. Thank you for this. :)
I’m sorry to hear that. But I’m happy you found something that helps you.
Me too! Hope you’re doing better :)
@@kingwolf3044 Thanks. :)
@@Meli-Meliai Thank you! I'm doing pretty OK lately. :]
That’s great ^_^ I’m so glad to hear that.
_Wait, that's illegal_
How did you get that quote to lean?
You again !
@@Core_Of_The_Void
You can do that by adding underscores "_" at each side of the word. _Example_
You can also use asterisks "*" to make them like this: *Example*
Or hyphens "-" to make them like this -Example-
_t_ *e* -s- t
FBI open up
You know that the jail is housing weirdos when the prisoner can
A) move Super fast
B)unable to count to 45 seconds and
C)knows that the fuse burns for exactly 60 seconds even when his watch is broken
ikr! Who can get outside of that fence in one second!?
can you count exactly 45 seconds
@@estherqin3080 the question is who can't?
@@brunobottoni9661 You can count, but you have no guarantee that your counting is an infinity precise measurement of time. For example, I tend to count seconds more quickly between 1-10 because the English words are shorter, and the counting slows down as I move to numbers bigger than 20.
If you doubt it, try asking other people to count off a minute by the second and compare it to your watch. They're going to be pretty close, but I wouldn't be surprised if they ended the minute off by a second or more.
@@Al-Ash simple, he was doing plank
Plot Twist: The jail knows that some prisoners will try to escape using the method and makes each fuse burn out in 59 seconds. This means that the prisoners will go through the fence three-quarters of a second earlier and get electrified.
Second Plot Twist: It takes a bit longer than the prisoner in question expected for him to light the fuses and he ends up timing it perfectly.
Just a quarter of a second earlier actually I know I'm nitpicking
_ok_
__look_
Plot twist the outside of the prison is the real prison
didn't try to solve the riddle because i can't help a criminal escape jail
YOU are the criminal.
Well you failed anyways lmao
The current 2 replies get a woooosh from me.
@@dominickeijzer5844 lol no, i meant he got out anyways so he failed from keeping him in jail
Poor excuse.
In which prison do they allow prisoners to have lighter in pocket??
@@worldwidewebstertheinterne4924
Wait...so if the fence is electric...how TF is he sleeping there?!
@@sirjgn4868his body isn't in contact with the fence so it's fine
Prisoners find a way of smuggling things in. A bribe here and there can grease some palms.
Heard of smuggling.
The same prisons that make fuses as part of their prisoner work program.
hey everyone! ted ed is teaching us how to break out of jail! lets take notes!
Good idea😂
Step 1: have an accomplice who wasn't arrested and is somehow able to disable the only security measure.
@@fieldrequired283 step two: try to figure out the eight founders of your jail and find the secret houding area
I really like how they convert a small looking boring puzzle into an awesome puzzle by indulging it into some random story.
Agreed
Me too I really like that
Basically all their puzzles but it's so creative how they make these scenarios up
Starting fires in front of prison guard right before your escape. Hmmm... My gut tells me this is a bad plan.
lol
Hes sleeping
Prisoner: Doesn’t know how to freaking count 45 seconds
Also prisoner: Knows that fuses he had can burn in exactly 1 minute and counts exactly the time where the flame should meet a certain destination
Maybe because he tested one BEFORE he knew about the escape plan? When his wristwatch was still working?
But isnt a jailor the person who runs the jail?
@@a_pufferfish2936 this
hardly anybody can count exactly 45 seconds you always get to the end too soon or too late for it to be exact
Its "prisoner" or "criminal", not jailor.
Here are 2 quick riddles for u.
1. The two doors
You are in a room with two doors - a red one and a blue one. One door leads to freedom, the other one leads to a ton of worms that you have to eat if you open that door. There are two guards in the room - one always tells the truth, the other always lies. The guard that tells the truth knows that the other one always lies, and vice versa for the other. Both guards know which door is to freedom. You don't know which guard is which. You may ask one guard one question. What question can you ask either guard to guarantee that you go through the right door? The answer is below.
Pretend the red door is to freedom. The question to ask is, "What door would the other guard say is to freedom?" This works because if you ask the guard that tells the truth, he knows the other one always lies and would say the blue door, so he truthfully replies, "The blue door." If you ask the guard that always lies, he knows the other one always tells the truth and would say the red door, so he lies and says, "The blue door." So, they both said the blue door... so go in the other one!
2. The three light switches. In the attic of an old house, there are three light switches. They control three lightbulbs in the basement of the house. How can you figure out which light switch goes to which lightbulb while only going in the basement once? The answer is below.
Turn the first two switches on and wait ten minutes. Turn off the second one and go in the basement. The lightbulb that is on is connected to the first switch. Then, feel the temperature of the other two bulbs. If it's hot, that bulb is connected to the switch you turned on, then turned off. If it's cold, that bulb is connected to the switch you never touched.
This took half an hour to type, (on mobile) so please like for my effort! Hope you enjoy your new found knowledge!
First riddle not only very popular and well known, but I believe they already covered it. The second one is pretty cool, though.
Dangg.. I saw first riddle long ago, but couldn't find or think of the answer. Thanks for that!
I could get the first one. But I solved the second one. thanks for this mate!
@unknown ent1ty yeah, but then you wasted your one question and you have a 50/50 chance of success
The first one I know and solved a long time ago, but the second one is new to me.
I think if the guy is that smart he doesn't really need to be a robber.
True tho
Problably was forced to do so.
Do u think they aren’t smart? Some thief are genius, they just use it for wrong purposes
Maybe he likes the chase
Yeah he should be a scammer, way less risk, at least he's not a sucker that slaves away half of his waking hours to procure the bare necessities required to do it again until he's too decrepit.
Robber: can't afford inaccuracies while counting the seconds.
Also robber: here let me take my sweet time to light the fuse.
Based
my thoughts exactly :)))))
I have a habit of counting down the time in my head along with a timer without looking at the timer of course. I usually ask myself "Will I ever need to be able to count down as accurately as possible?". Now ted ed has given me the answer.
@sbtopjosh Hhahahhaha
Wait couldn't you just listen for the hum to stop,
Wouldn't it take him a moment to react to that & by then, it's on again
@Caesar And maybe you need to get your attention span tested.
Considering you have the patience to read this entirely, I only have one advice for you -
Watch the video again.
Obviously the fact you're actually pointing me out for something the video so obviously states means u need more of that focus you're so desperate to prove others don't have.
Btw, I'm a national badminton player, so yeah, maybe I don't have strong reflexes just like you don't have patience.
Or just count in your head (or loud would be a bit suspicious)
@@Aaron_Walker_011 Damn, no need to get defensive over such a little thing.
Btw, I'm a national prodigy in every subject, so yeah, maybe I don't have smart brains just like you don't have pride.
@@darksideorbit8898 I somehow doubt that lol.
"You have a lighter"
Me: Oh so we burn the guard
"And two fuses"
Me: so we electrocute him or something??
Whoa, calm down, satan
@@alfinakmal5644 I think he has played a bit too much hitman. Also he does not seem to be a fan of silent assassin.
@@VodShod why would you assume her gender?
Just use they/them ¯\_(ツ)_/¯
@@YourFoodIsBland use the pronoun 'it'
Very good ! Not just the idea and the script but also the production. Congrats🤞
0:27 I only have "a second or two" time window to negotiate an electric fence? To be honest I would rather just stay and serve out my time!
I’d rather stay in jail too.
Narrator: But his watch is broken.. how can he tell time with fuses and ligh-
Me: 1) who gives their prisoners freaking watches and 2) Just count physically!
Also, he could probably use the watch to short out the fence himself (sticks to bring the wires close enough, then a tap with the metal)
And also, who gives prisoners lighters and lets them make fuses????
3) Why is there even a watch repairing station
Have you ever tried to count any amount of time longer than 10 seconds and then checked your watch afterwards? You might get close, but it's very rare and very difficult to get it exactly.
*_El Chapo has joined the chat_*
Omg lol
I see you every where
*Is Justin Y. yo senpai?*
_Bob McCoy, why is the “.....Punch!” Spray your channel icon?
*El Chapo left the group*
M/Haseena sops all chats
*BUT I HAVE GREEN EYES*
i didn't get it
Mohamed Khaled it’s a reference to another riddle
@@carriejones2827 k
Guard: understandable, have a nice day
every one get it
Ted-Ed: “looking for a harder puzzle?”
Everyone: “how many times we gotta teach you this lesson, old man?!”
Millions times
Yeah! Always love a good Ted-Ed riddle.
Sarcasm?
@sachinr2204 it's honestly the only reason I'm subbed!
@@justjess-zl3pm No. Absolutely not
Damit u could count
I tie the lighter to the end of the fuse, and use my knowledge that a standard Bic lighter is 8cm long to measure out a 25cm pendulum.
45 swings and I go through the fence.
truthsmiles can you even get 45 swings out of a fuse and lighter pendulum
That only works without air resistance
How does it work tho? 1 swing from a 25cm pendulum made by an 8cm lighrt is perfectly 1 second?
Jam Ham Time it’s funny. Calculating the period of a pendulum is surprising complicated.
I don’t know what you know, it was a bit complicated for me, as I’m not very fluent in introductory level physics, but if I remember:
You can think about gravity being the only non perpendicular force to the pendulum (if we ignore air resistance) and that will lead you to some sort of:
angle’’ = a* sin (angle)
Where angle’’ is the second derivative and a is a constant.
This equation is one that I’m not sure there has been a solution to.
So you probably won’t really find the exact algebraic solution to the problem. What you can do is approximate sin function around the angle 0 as a polynomial and try to use a pendulum that uses small angles as to keep the approximation the most accurate. With the approximation the differential equation can be solvable.
The way others go is through conservation of energy, potential and kinetic energy considerations you can easily get an expression for the pendulums velocity at any angle.
Great, so we can just integrate that expression to find the angle over time right?
Well yeah but again I think it’s an unsolved if not impossible analytical problem, it ends up being an expression we don’t know a primitive for, and a such can’t integrate.
The final answer is yeah we can use some sort of approximations in various ways and easily get good approximations, especially with the use of computers.
But it’s annoying for me at least, there doesn’t seem to be an exact analytical solution.
Which is what this problem was kind of asking for.
For a real life robber, one might know an approximated formula for a pendulums period that is has an error much smaller than the 1 second or so the robber has to pass the grid though.
@@aienbalosaienbalos4186 That guy...is a robber.
@@aienbalosaienbalos4186 i think it's the conservation of energy that should help, which gives us that the potential at the top must be equal to the kinetic at the middle. Height reached = L * (1 - sin alpha), but then i've forgotten what the trick was for finding out the speed through the mean position. :">
Apparently, the formula we should get is T (in seconds) = 2 pi SQRT( L (in meters) / g )... so we get a length of g/(4 pi²) ≅ 248.237 mm. So now, @Ipek... what happens if the fuses are slow-burning, thus with a length smaller than what is needed for this? 😈
I was actually able to solve this one! This is the smartest I've ever felt ngl
Wow great job I’ve never solved one
These videos are always so well done and interesting
"Pause the video to figure it out yourself"
Me: Ha! U cant tell me what to do
This is easily one of the best puzzles I've seen here. I took forever trying to solve this before finally giving in and unpause to see the answer I never thought of and then TED-Ed goes to say "Looking for something a little trickier?" :/
Although I did solve the Three Gods one.
I Solved this riddle but failed there gods one, we are oppisites
I just love TedEd's riddles, it just has more logic compared to a lot of the riddles in the web. It actually makes you think and solve stuff
2:57 Dont ever take your helmet off while riding kids, be safe out there!
ted ed: its almost noon and ur partner will be giving the signal any minute
me: spends a few minutes figuring out how to do this
I literally live 4 these
@@vigneshdodla3020 hi
Thank you for helping us escape prison. This really helped me ^-^
Woah woah woah safety first what’s up with tossing the helmet. This ain’t red dead where you ditch the mask soon as you go around a corner lol
Video: Burn wires this way and that
Me: "1 Mississippi, 2 Mississippi, 3 Mississippi..."
Here is another solution: Although the fuse burns irregularly the amount of gas used by lighter should be constant. You light one fuse and keep the lighter on constantly until the fuse burns out. You note starting level of gas and finished level of gas and that distance is your one minute. You divide it into 4 and 3/4 of that will be your 45 seconds. You then turn on the lighter when you see the signal and once the level drops by 3/4 of a minute’s distance, you got your 45sec. Though I realise there is a flaw in this logic that the amount of gas used up in 1 min will be small and hence impossible to measure 3/4 of that amount accurately, but that would be another way to solve it if time to be measured is longer and the lighter is transparent:)
I think the idea is that you only realize you lost your watch right before the signal
If cut a fuse wire into half i ll get 30 sec fuse .and cutting the 30 sec fuse i ll get 15 sec fuse.now i have 30+15 sec fuse ,after the 30 sec fuse burnt out lit the 15 sec fuse .This is my idea tell me if iam wrong
A) If you light any of the fuses at each end simultaneously, then each end burns until they meet at exactly 30 seconds. Why? Because if they meet after burning for x seconds, then each would have had x more seconds to go to reach the other end. Thus, 2x = 60 seconds, and therefore x = 30 seconds.
B) Let us therefore designate the fuses as Fuse A and Fuse B. We light Fuse A at both ends and Fuse B at one end only, all simultaneously. It will be exactly 30 seconds when the flames from both ends on Fuse A meet up. At that point, the flame on Fuse B would also have burned for 30 seconds. We immediately at that point, light the other end of the Fuse B (We can even use the flame at the moment of meeting on Fuse A to do so). The flames (on Fuse B) will meet at exactly the 15 second mark following the same logic as explained in A). Thus, 45 seconds would have elapsed and voila! ... You are a free man!
This will come in handy later on in life
-when I’m breaking out of jail-
Meanwhile the guard: wtf is he doing eh in just gonna do nothing as I watch him climb over the fence
the guard was asleep.
Wow I might have actually solved it:
1. Take the second fuse and cut it in half, then align them so they are parallel with each other.
2. Light the first fuse on both ends at the same time.
3. Wait until the first fuse burns out, since we lit both ends that would be 30 seconds.
4. As soon as the first fuse burns out, light the left end of one half of the other fuse, and at the same time light the right end of the other half.
5. One fuse is burning left to right and the other fuse is burning right to left. The point that the fuses burned are aligned would be 15 seconds. For a total of 45 seconds.
Edit: Oh, I guess i forgot there is nothing to cut the fuse with. Pretty close tho. :D
1:19 the guard sleeping on the fence nice logic
More than the riddle itself.. I congratulate you for the art and work you always deliver!!!
Domo!!
"You find something that you might help"
Me : Well that's good... :D
"A lighter and 2 fuses which you make in the prison"
Me : .....
Meanwhile prisoner B climbs over the fence using the ladder he built in the prison’s shop class.
I'm so happy that I was finally able to solve a Ted-Ed riddle by myself without cheating :D
🧐 Daammnnn booy your good
same lmao this one is so easy.
Me too! I'm thinking this was one of the easier riddles but I'll take the W.
This one's a classic in my family! So proud to be able to solve it! 😊
Criminal: Constantly trying to figure out how to beat the system.
Me: Constantly trying to figure out how NOT to be part of the system.
Hmm. I tied the lighter to one end of fuse A which I tied to something else (perhaps my finger). I lit fuse B, while dropping fuse A and counted the pendulum swings for the 1 minute duration of fuse B. So, 3/4 of that number of swings is 45 seconds... which I can perform any number of times because I never actually burn fuse A.
OrbitalBliss Genius! This is far more easy.
They said “precise”, not to mention the fuses aren’t threads, and that the oscillations will die out very soon.
So underrated comment
Thats more of a vacuum situation since there would be other factors into play like wind, viscosity, gravity and stuff. So might not be exact. But that's really creative.
@@Monkeynertia Also the fuel in the lighter would keep opposing the motion of the pendulum here so, will literally kill the oscillations too soon!
I love ted ed riddles
Tell the guard that you’ll give him two fuses and a few matches if he tells you when exactly 45 seconds have passed.
My God, this is one of the few TedEd puzzles I actually solved
2:48 He was holding the wire for three seconds
To the people that say 'just count 45 seconds':
It's actually alot harder than you think to count 45 seconds precisely, you'll either count it 1 second too late or 1 second too early, if it really were that easy, this wouldn't exist, listen to 0:41, if you make even the slightest miscalculation, you'll get deep fried and served with a side of chips, so no, you can't just count 45 seconds if the fence comes on 2 seconds later
I had a different solution. I figured you can find some way to count at a steady pace. It does not matter if your counting equals one second per number, it just needs to be steady. You burn one of the 60 second fuses while counting steadily. Whatever number you reach when it burns out, you divide by 4, because that will equal 15 seconds. You then light the second fuse and let it burn while counting to that same number that equals 15 seconds, then you put the fuse out. The fuse now has 45 seconds left on it, so you can use it when you get the signal to measure 45 seconds. The result might be slightly imperfect, but given that it takes time to light a fuse and get it burning, the TED solution also is inherently imperfect.
My brain thinking: JUST BURN THE FENCE
me: but that is going to take ages
My brain : ... do you have a better idea
me: in 3 seconds yes
Commenting before watching:
When the signal is given, light up both ends of fuse 1, and one end of fuse 2. After 30s, fuse 1 will burn out, while fuse 2 is supposed to burn for 30 more seconds. At this time, light up the other end of fuse 2. Now fuse 2 will burn out in 15s, so total 45s
I absolutely enjoy these fun little riddles!
That resolution wouldn't hypothetically work based on the stated conditions. If the fuses burn erratically, than one end of the fuse could burn for 59 seconds and then finally burn really fast to burn the rest in 1 second. So there would be no way of splitting one fuse into 30 seconds simply by lighting both ends. They contradicted themself with the answer....
That would indeed be one erratic fuse.
Brilliant! I didn't see that one coming...
Could you really depend on a fuse being that accurate, down to the very second?
This dude has the best voice
Who?? The robber
Before watching answer: Tie one fuse in a circle and another in a figure 8. Light the circle so it burns at 2 ends, counting 30 seconds, then light the figure 8 as soon as it finishes, burning at 4 ends, counting another 15 seconds.
That would've worked except with the figure 8, each end of the lobe from the central point will take a different time to reach the other Flame.
So neither lobe of the 8 will burn out in exactly 15 minutes.
What will I do if the lighter doesn't work with me from the first press!
That’s when you start counting
And then you notice,
TOYOUR HORROR!
that ur watch is broken XD
Finally! A sensible, reasonable, unconvoluted riddle! (I talk sincerely.) And it's relevant to my daily life!
I've solved it considering the preparation of the fuse instead of doing it "live" as the solution proposed:
if you cut the first fuse in 4 pieces, and you light them all at both sides simultaneously, and together you light one side of the second fuse, it means that the fuse parts will burn in exactly 15 seconds (in the exact moment where the last burning part is completely burnt), so when you see these parts completely burnt, you extinguish the fire in the second fuse. So you get a partially burnt fuse which will last exactly 45 seconds, to light up at your needs :D
And if you're considering the time that gets through when you're litting the fuses, you just need to bend them together in order to have all the tips rolled up towards the flame of the lighter. And if you're considering the mess that would this action probably generate, maybe the burning tip of one fuse that puts fire at the middle of another fuse part (or the second fuse), well you're a prisoner, things can go wrong in jail.
Sorry to tell you but it doesn't work for two reasons:
1: Burning 4 parts from both ends would give you a time of 60/8 = 7.5s, not 15s. Per your own logic you should burn the 4 parts from one side only to get a 15 second burn time.
2: It doesn't work since the pieces will burn of a variable length. Lets say one burns for 7.5s. It means it will go out well before the 15s has passed. This means that another piece will still be burning after 15s has passed and thus you have no way to verify when 15s actually has passed and when to extinguish the fire on the second fuse.
Nice thinking though.
*_in the end the jailor dies a sad death, due to do fact that he was busy freaking burning fuses, instead of simply counting it by himself..._*
And his accomplice was quickly apprehended because standard police cruisers are faster then standard motorcycles.
You mean prisoner. Jailor is in this case the one dozing while leaning on an electric fence and somehow not getting electrocuted.
Actually due to sleeping next to the fence.
But if the timing has to be that precise (within a 1-2 second margin) you might as well just count to 45, since timing the fuses would be just as hard as counting to 45 give or take 2 seconds. The precision of lighting the fuses the INSTANT it dies will be just as precise as counting to 45.
I SOLVED IT WTH THIS NEVER HAPPENED TO ME
Carl aM agic omg cool
Congrats!!! 😆😆😆😆
We’re all proud of you
I should hope that you've never escaped from prison....
SAME!
Plot twist : The lighter started acting up in between and delayed some seconds, he got the wrong time and got friend. rip
Roughly count 45 seconds then touch the fuse to the gate afterwards, if it is electroc it will probably catch fire anyway so just cut the fuse to pieces for multiple tries and touch the fuse to the gate ater aprox 45 seconds. When it doesnt catch then it is safe to go. Just test that they burn properly when it is electric.
I’ve watched Ted’s puzzle for the first time.
This is a very interesting video!
I wanted to know the puzzles’ existence earlier
I'm sorry, why does the prisoner have a lighter?
This requires impeccable lighting skills as I have never been able to light something less than 5 seconds before.
I remember this riddle when I was young
my brother told us it
I wished I could solve it but my father solved it in like 3 minutes and spoiled the answer
Plot Twist: The robber took too much time watching this video and the wires are already live again
It's so satisfying to see TedEd coming to the same conclusion you did
but i thought you said they burn "irregularly"?
Meaning those fuses could burn 52 seconds on one end and 8 seconds on the other end. Or 24 seconds on one end or 36 seconds on the other end 🤔
True, but no matter what, they take sixty seconds to burn, no matter how they burn they burn for the same amount of time and this method works.
"Well, me, I'd just cut the wires" - Tony Stark
And you realize that you actually wasted 30seconds watching the first fuse burn out to light the second.
1. Confirm you have green eyes
2. Ask the police to let you leave
0:18
McGee: ITS HIGHHHHHHHHHHHHHHHHHHHHH-
ppl in these riddle videos: criminals, hostages, giants, dwarves
ted ed: and they were all raised perfect logicians
Ted ed is my favorite RUclips channel and the video's is also very interesting
2:48 you touched it longer than 2 seconds. You're a dead man
Light both ends of Fuse 1 and one end of Fuse 2 at the same time. When Fuse 1 goes out, 30 seconds will have passed, then light the unlit end of Fuse 2. Fuse 2 will have 30 seconds left, and by lighting the other end, you halve that to 15. 30 + 15 = 45.
Me, an intellectual : Throws the fuse and lighter away, starts counting 45 seconds in my mind.
But those 45 "seconds" could be 44 seconds or 46 seconds.
Or he could have asked someone with a watch to do a count down
There's a contradiction in the solution. How can you assume the ratio of 30:30 from both ends. It could be 20 seconds from left and 40 seconds from right to meet, or 25 seconds from left and 35 seconds from right to meet or 10 seconds from left and 50 seconds from right to meet and so on. The prisoner doesn't have the watch right.
This guy mentioned himself by taking example of one side burning in 20 sec and other in 40 seconds. Now he suddenly assumed 30 sec from both sides.
Animation is the best
That jail watch repair was really funny.
great puzzle
Cute mathematical puzzle - even though it's explained thru a totally unrealistic situation.
Wait...
WHY AM I IN JAIL HUH?