Fixed End Moments

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  • Опубликовано: 8 фев 2025

Комментарии • 85

  • @pkr786ind
    @pkr786ind Год назад

    For the case where you apply fixed end moments, where you’ve shown a rectangular moment diagram, the deflected shape is incorrect since it has positive and negative curvature whereas the moment will result in only a single constant negative curvature. Furthermore, the end conditions, shown as fixed, are incorrect as there is no way you can get a deflected shape with them present, for the applied end moments, since those moments will go into the supports, not into the beam.

  • @gowthamiv4841
    @gowthamiv4841 5 лет назад

    Worth watching.. great ahead.. expecting more to watch...

  • @Goodvibes4me
    @Goodvibes4me 2 года назад

    Now I can become fully fledged engineer

  • @vtriveni5765
    @vtriveni5765 5 лет назад +4

    Superb...u spoke how that formula came . Thanks a lot sir.every one is dictating the formula but not explaining but u didn't do that.plz continue ur videos like this

  • @debanjanpaul767
    @debanjanpaul767 6 лет назад

    you are great ... very nice video ... keep it up and make other video ...

  • @KazeTdr
    @KazeTdr 2 года назад

    Sir what's this method of equating the 2 areas for calculating moment is called?

    • @CivilEnggLectures
      @CivilEnggLectures  2 года назад

      Actually I used the concept of Equilibrium... Load equals to response..

  • @raisuddinbiswas2614
    @raisuddinbiswas2614 4 года назад

    How i contact you plz help i have some questions problem

  • @huffaz_group
    @huffaz_group 4 года назад

    Can you do a detailed example of kanis method?

  • @mohammadanasbeg5000
    @mohammadanasbeg5000 3 года назад

    اسلام علیکم
    Sir please drive one more case for eccentric point load

  • @FranCoVids
    @FranCoVids 6 лет назад +1

    So, what would be the FEM equations if you had two unequal concentrated loads and are spaced equally apart?

    • @CivilEnggLectures
      @CivilEnggLectures  6 лет назад

      It could be done by taking each load separately for calculation of Fem and then adding both

  • @kirankumar4863
    @kirankumar4863 5 лет назад

    But Mfab and Mfba are in opposite direction why the sign is not changing

  • @ruhiprawin1159
    @ruhiprawin1159 4 года назад

    Very nice 👌 sir

  • @shahzadali4801
    @shahzadali4801 4 года назад

    Nice explanation 👍

  • @rishabhpasi98
    @rishabhpasi98 6 лет назад +1

    sir one basic ques...how these fixed end moments are developed??

    • @CivilEnggLectures
      @CivilEnggLectures  6 лет назад +1

      Cos when member is loaded joints are required to rotates.. if joint is fixed it does not allow any rotation by developing resisting moment.. this is how it is developed

  • @utsav8530
    @utsav8530 7 лет назад +4

    please menage videos in playlist which wil be helpful to find videos

  • @abdelsattar6007
    @abdelsattar6007 4 года назад

    How to calculate the FEM in case of temperature variation or settlement?!

    • @CivilEnggLectures
      @CivilEnggLectures  4 года назад

      We can do it by knowing the magnitude of settlement.

  • @deepanjanpal6014
    @deepanjanpal6014 5 лет назад +1

    Thanks bro, it cleared all my doubts

  • @TreatSpin
    @TreatSpin 7 лет назад +1

    I don't understand. If there is no sagging or hoggging, there will be no deflection. In this beam there will be definitely be a deflection, so I do not see why you equate the two areas

    • @CivilEnggLectures
      @CivilEnggLectures  6 лет назад

      Sagging and hogging is there..
      More or less it is equal..
      Sagging will be more at midspan and hogging will be more at end of beam or at rigid joints..

    • @mahesh4943
      @mahesh4943 3 года назад

      @@CivilEnggLectures but sir sagging and hogging are not exactly equal then why u equate both areas?

  • @therose4872
    @therose4872 6 лет назад +1

    Sir What if the force was parellal to the member ? What is the formula of fixed end moment

    • @CivilEnggLectures
      @CivilEnggLectures  6 лет назад

      No fixed end moment is developed for parallel forces..

  • @rojab861
    @rojab861 2 года назад

    Nice explanation

  • @Goodvibes4me
    @Goodvibes4me 2 года назад

    Gud explaination

  • @xhsldnjd
    @xhsldnjd 2 года назад

    so useful sir

  • @arizkhan2183
    @arizkhan2183 7 лет назад

    great work sir ......doing a great job 😊

  • @arunndinesh
    @arunndinesh 7 лет назад

    sir, is there any standard formulae for fixed end moments of a beam with trapezoidal loading?

    • @CivilEnggLectures
      @CivilEnggLectures  7 лет назад

      Arun dinesh yeah

    • @arunndinesh
      @arunndinesh 7 лет назад

      Please give me the link or formulae description..

    • @CivilEnggLectures
      @CivilEnggLectures  7 лет назад

      Already you know it... trapezium can be converted into two figure.. rectangular and triangular.. rectangular means udl and triangular means uvl.. you need to add udl and uvl

    • @arunndinesh
      @arunndinesh 7 лет назад

      Sir, I am looking for trapezoidal load distribution from a 2 way slab,not the typical trapezium one you're saying. So I'm not getting formulae. Please help me with your idea.

    • @CivilEnggLectures
      @CivilEnggLectures  7 лет назад

      +Firoz Nadaf what you are asking is not trapezium loading...
      Its a load distribution on beam in case of two way slab.. which is nothing but udl

  • @aamirdurrany
    @aamirdurrany 6 лет назад

    Very well explained. Where are you from btw?

  • @utsav8530
    @utsav8530 7 лет назад +1

    and yes your videos are awesome

  • @rm3108
    @rm3108 5 лет назад

    I want solution for the trapezoidal load condition.can you please help me with the proof of the formula (-wl^2)/30?

    • @CivilEnggLectures
      @CivilEnggLectures  5 лет назад +1

      you can do it by using force or displacment Method.. Try it.. if not let me know.. but first try by yourself

    • @msrinivasakannan
      @msrinivasakannan 5 лет назад

      @@CivilEnggLectures pls explain... unable to do

    • @CivilEnggLectures
      @CivilEnggLectures  5 лет назад

      What's the condition of load

    • @CivilEnggLectures
      @CivilEnggLectures  5 лет назад

      @@msrinivasakannan what's the condition of load?

    • @msrinivasakannan
      @msrinivasakannan 5 лет назад

      1. Uvl triangular - max load at any edge..
      2. Uvl triangular - max load at center
      3. Uvl trapezoidal laod
      All cases for fixed beams

  • @rupeshmpradhan3871
    @rupeshmpradhan3871 7 лет назад

    Excellent sir

  • @udaysampath009
    @udaysampath009 6 лет назад +1

    Thank you

  • @sushantpathak2986
    @sushantpathak2986 7 лет назад +4

    Brother your videos are really very helpful and very easy to understand..... Plz continue....

  • @febinlalu5543
    @febinlalu5543 7 лет назад

    sir how we calculate fixed end moment when both udl and point load acting on same beam

    • @CivilEnggLectures
      @CivilEnggLectures  7 лет назад +1

      Febin Lalu calculate fixed end moment separetly for loadings and add it...

    • @hemrajkharka1467
      @hemrajkharka1467 2 года назад

      Principle of superposition

  • @sanjeevreddy1756
    @sanjeevreddy1756 6 лет назад

    Thq

  • @rigelsirius
    @rigelsirius 4 года назад

    Thank you!

  • @minminmibang7617
    @minminmibang7617 7 лет назад +1

    Nice video very informative

  • @msrinivasakannan
    @msrinivasakannan 5 лет назад +1

    In this method we are unable to solve
    1. Uvl triangular load
    2. Max at center triangular load
    Pls assist

  • @tusharkashyap8688
    @tusharkashyap8688 5 лет назад

    Thanks dude! u explained really well!

  • @sanjeevsinghyadav9462
    @sanjeevsinghyadav9462 4 года назад

    For UG physics
    ruclips.net/user/institutembw

  • @ashfaqt1605
    @ashfaqt1605 6 лет назад

    Partial UDL ke liye bhi batao

  • @yusraal-sabahi5309
    @yusraal-sabahi5309 5 лет назад

    Thanks

  • @prasadb4842
    @prasadb4842 7 лет назад +1

    great bro. well done. Hugely help full... keep going...

  • @nirajmaharjan7160
    @nirajmaharjan7160 7 лет назад

    Very well explained

  • @voiceofemaan3125
    @voiceofemaan3125 7 лет назад +1

    PLEASE MAKE VIDEO ON MDM FAME

  • @ashokgupta-wv5cn
    @ashokgupta-wv5cn 6 лет назад

    Sir plse resolve eccentric loading of fixed beam by area moment method..

  • @abhijitp
    @abhijitp 6 лет назад

    Thanks man

  • @hcStructuralDesigns
    @hcStructuralDesigns 6 лет назад

    sir upload more problems

  • @princedhinakarrekala9962
    @princedhinakarrekala9962 7 лет назад

    super sir

  • @vibhore9624
    @vibhore9624 6 лет назад

    Left support has anti clockwise moment and right support has clockwise moment....
    Why you consider both moments negative...
    Not LHS moment negative and RHS moment positive...

    • @CivilEnggLectures
      @CivilEnggLectures  6 лет назад

      Positive and negative sign does not merely depends on signs but on sagging and hogging..
      Sagging positive and hogging negative..

  • @jeetmondal6451
    @jeetmondal6451 6 лет назад

    not a good vedio i cant understand for which i open it