This channel is highly trusted because I found some websites and other channels they don't take data accurate and also don't teach precisely but this channel teach everthing in precisely manner and whenever I study from this channel I don't take any tension for accuracy related problem....
Great explanation. I dont now why we added third case and then removed it through simplification. Even saying s3*(s2*+s1*), it was already covering number 10 - 15.
(0) We are representing each decimal digit by 4 bits (1) We add 6 because 4 bit includes numbers till 15 and we only want numbers till 9. For the rest of numbers between 10 and 15, we wish to take a carry of 1 to the next set of 4 bits (by adding 6). (2) To identify numbers between 10 and 15, we can look at just the MSB = 1, unfortunately, this includes 8 and 9. So we want all 4 bit numbers such that MSB (S3) is 1, excluding 8 and 9. (3) 8 and 9 have S1 = 0 and S2 = 0. => S1+S2 = 0. For the rest, we want S1+S2 = 1, and also MSB bit as 1. This is S3.(S1+S2) (4) The sum of 2 numbers between 0-9 can also lead to 5 bit numbers, 16, 17 and 18. For these also we need to add 6 as 16 in binary is 1 0000, but we want 1 0110 (similarly for 17 and 18) (5) So the required expression for which we need to add 6 is C + S3.(S1+S2)
@@ikshvaku_allegiance4015 The 1st digit (MSB of the BCD representation) is explicitly calculated by the or gate. So this is correct. Your claim: the carry from the second adder is also correct. Let's check this. Say the sum of the two numbers is 17. Then the binary is 10001. The 0001 is taken and added to 0110 by the second adder to get 0111 = 7. This has no carry. Therefore by your method, the final output will be 00111 (which is wrong). If you use the carry from the or gate, the answer is 10111 (Which is the required answer. See @4:09)
@@RahulMadhavan i have another doubt in video no. 143.Kindly resolve that as well.Thanks. I have posted it below as well. (@Rahul Madhavan .In very first question what happened to the carry outputs after subtraction of the first bit. Cin is 1 but then y0 + X0' must have given a carry which would have then propagated to next bit. How are we handling that?)
@@ikshvaku_allegiance4015 I'm sorry I don't have the context to this question as I don't have video numbers. Furthermore, I saw these videos 3 years back so I don't remember offhand. So maybe someone else can help on that.
@@RahulMadhavan ruclips.net/video/o22PeIImcKc/видео.html this is the video link.First question itself.Nobody else has been able to answer my doubt..kindly help
@@creativestudio5761 If u take the sum of s2* and s1* then you don't need 3no case..Cause it also includes the case..But if you want to take 3 cases then the equations have to be as the comment..
this was such a wonderful lecture, explaining each and every logic in simple and easy to understand way. Now I am safe to say that I will be able to do any question from this part. Thank You so much Sir!!
Watching it first time i didn't understood. But later after three months i understood. First time i say is the time when my sir explained and second time i watched during my semester exam and i finally understood
can you also do videos about verilog there isnt much source, i follow your lectures, thank you , you really give us the best quality lectures and really helpful for all electronic students
thanks a lot sir !!! you just made everything simple i think there are some problem with the subtitles.you are saying something(in the video) and subtitles are listing another
Hi @7:30 ------> In the (ii) case 12 to 15, instead of using " s*3.(s*2 + s*1)" we can use only "s*3 . s*2" Because 12 to 15 only s*3 and s*2 both is high(1).
Great and simple explanation sir, can u tell me which board are you using in the video for writing, It would be helpful for me to conduct online lectures for my students.
there is no need of taking a bit from the OR gate and giving it to final output, as we can directly get the 5 bit output from the second 4 bit full adder Thank you Good teaching
Why were 0&3 bits were called min term and maxterm ? Those terms are defined entirely different in some other video! Anyways excellent explanation. Thanks for that 👍
Just for all the people wondering about Case 3, it's not required. Even if u do take Case 3, it will get eliminated since we find the minimum possible function. Case 3 is not required.
Hi! your video is very informative and easily understandable so I always see the videos related to the digital logic design on your channel. thank you! But I have a question related to this video, what is the previous carry?
NESO ACADEMY ZINDABAD!!! I am passing this semester cause of you guys!!!!
Hey man did u passed ur semester
What are u doing now
This channel is highly trusted because I found some websites and other channels they don't take data accurate and also don't teach precisely but this channel teach everthing in precisely manner and whenever I study from this channel I don't take any tension for accuracy related problem....
Ur explanation is great ...but u can believe that there is not a single soul in universe who watches ur video in normal speed🤣🤣🤣...#u r awesome
i am that one...
Even i am making notes of his presentation...
@@techvsfake6036you will watch in normal speed if you are making notes. But not if you are reading
@@noobCoder7 i generally watch in 1.25x and take notes after finish. For easy topics, i watch in 1.5 or 1.75x.
@@ImranALI-qh3je i make rough notes and watch in 2x speed always
@@noobCoder7 good
You are MY Online Guru where i can easily get all the things done thank you sir
I love how I can learn all my subjects from Digital Design to Siganls and Systems, Programming, etc with your videos ❤️
Excellent explanation in all the tutorials.
Easy to understand
Omggg, thanks for existing!! Excellent video!
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Thanks for all videos Neso Academy. Your videos are easy to understand and also clearly explain the basic concepts.
Thank you ,you really saved someone's life. really helping
one like is not enough ,if we could get such crystal clear concepts in all subjects
Then give two.
Thank u so much sir, its really very clear and easy , millions of thank u sir
the explanation is superb.All the contents are covered
thanks a lot.
Great explanation. I dont now why we added third case and then removed it through simplification. Even saying s3*(s2*+s1*), it was already covering number 10 - 15.
Don't forget + c*. But, yeah, what you're saying is ultimately correct.
I find using the K-map to find the equation simpler.
Thanks for being our teacher
(0) We are representing each decimal digit by 4 bits
(1) We add 6 because 4 bit includes numbers till 15 and we only want numbers till 9. For the rest of numbers between 10 and 15, we wish to take a carry of 1 to the next set of 4 bits (by adding 6).
(2) To identify numbers between 10 and 15, we can look at just the MSB = 1, unfortunately, this includes 8 and 9. So we want all 4 bit numbers such that MSB (S3) is 1, excluding 8 and 9.
(3) 8 and 9 have S1 = 0 and S2 = 0. => S1+S2 = 0. For the rest, we want S1+S2 = 1, and also MSB bit as 1. This is S3.(S1+S2)
(4) The sum of 2 numbers between 0-9 can also lead to 5 bit numbers, 16, 17 and 18. For these also we need to add 6 as 16 in binary is 1 0000, but we want 1 0110 (similarly for 17 and 18)
(5) So the required expression for which we need to add 6 is C + S3.(S1+S2)
can you tell why carry from or gate comes straight as is rather than coming from the second adder
@@ikshvaku_allegiance4015 The 1st digit (MSB of the BCD representation) is explicitly calculated by the or gate. So this is correct.
Your claim: the carry from the second adder is also correct. Let's check this.
Say the sum of the two numbers is 17. Then the binary is 10001. The 0001 is taken and added to 0110 by the second adder to get 0111 = 7. This has no carry.
Therefore by your method, the final output will be 00111 (which is wrong).
If you use the carry from the or gate, the answer is 10111 (Which is the required answer. See @4:09)
@@RahulMadhavan i have another doubt in video no. 143.Kindly resolve that as well.Thanks.
I have posted it below as well.
(@Rahul Madhavan .In very first question what happened to the carry outputs after subtraction of the first bit. Cin is 1 but then y0 + X0' must have given a carry which would have then propagated to next bit. How are we handling that?)
@@ikshvaku_allegiance4015 I'm sorry I don't have the context to this question as I don't have video numbers. Furthermore, I saw these videos 3 years back so I don't remember offhand. So maybe someone else can help on that.
@@RahulMadhavan ruclips.net/video/o22PeIImcKc/видео.html
this is the video link.First question itself.Nobody else has been able to answer my doubt..kindly help
case 3 is not required
case 2 is valid for both and
Exactly.... Thanks for confirmation 🙌
Thanks for your explanation! It seems clear to me after listening to your lecture!
Thanks for the awesome explanation otherwise its so hard to understand👍
thnx,earlier i memorized it but now i understand each component of bcd adder completely
the lecture was very very helpful...thank you
Clear explanation Tq sir I makes Me easy to understand the topic
Awesome explanation. Thank you. ❤
Cases should be like
1. c*=1 (for 16-19)
2. s3*.s2* (for 12-15)
3. s3*.s1* (for 10-11)
Yes you are right.
It doesn't matter either way, because when you take the sum of cases both answers are same.
Yes
@@creativestudio5761 If u take the sum of s2* and s1* then you don't need 3no case..Cause it also includes the case..But if you want to take 3 cases then the equations have to be as the comment..
No one can explain such a complex method in one go,just understand his efforts
Explained very nicely😎
Soooooooooooo much great explanation sir...........
sir u r lecture is awesome !! I like it sir
Neso Academy you are the best...
Such easy after your explanation...and how genius ppl who created this
Case 3 can be obtained from case 2 itself. Instead of eliminating s3*. s1* during simplification we can just have two cases.
Yes I thought the same I expect the creator to respond to this
Your videos are super easily understandable.
Excellent Sir!
awesome....extremely awesome...he made it so easy for me to understand...thanks
Excellent explanation thank you so much for making this video 😊😊😊
just wow i got it within 1 view.great explanation .love from Nepal.Thank u
nepaad
this was such a wonderful lecture, explaining each and every logic in simple and easy to understand way. Now I am safe to say that I will be able to do any question from this part. Thank You so much Sir!!
Very well explained....sir
Excellent Explanation.
Really nice explanation
Awesome explanation....great
Really helpful tomorrow is my exam and I got the logic from this
lol same here!
Thank you so much sir for posting such amazing videos !
I think you can group 10 and 11 in the group of 12,13,14,15 as well since their expression holds true for 10 and 11 as well
Watching it first time i didn't understood. But later after three months i understood. First time i say is the time when my sir explained and second time i watched during my semester exam and i finally understood
You made it really easy
Sir, I really like your video. If you make a lot of videos like this, I would be very happy.
Nigga nobody cares about u
very nicely explained.
Great explanation sir!!
can you also do videos about verilog there isnt much source, i follow your lectures, thank you , you really give us the best quality lectures and really helpful for all electronic students
7:10 y r u considering 12-15 and not 10-15?
thanks a lot sir !!! you just made everything simple
i think there are some problem with the subtitles.you are saying something(in the video) and subtitles are listing another
Superbb explanation..
Nailed it buddy .....!!!
Thank you, this helped quite a lot!
+Mohammad Sultan Khaja I know, watching it Porota!
Farhan Waseehahahhahahahhahahahhah
Helped alot. Thanks
such a great teacher👍
lecture is awesome
Thank you so much for the video!
really,,it's very much helpful for me,thank you
for these video lectures students are getting passed in the sem exams:) thanks a lot
Good explained.
Hi
@7:30 ------> In the (ii) case 12 to 15, instead of using " s*3.(s*2 + s*1)" we can use only "s*3 . s*2" Because 12 to 15 only s*3 and s*2 both is high(1).
agreed
www.geeksforgeeks.org/digital-electronics-bcd-adder/
I thought the same thing
yes. you can use case two only. but to understand it better use condition 3.
Yes I agreed
Thnx for easy explanation
Thanks yaar bhai Maza aagya💙
Thank You so much for the great content !!! 😊
Very GOOD Keep it up! man
it was easy to understand.....ty
Nice explanation
who's here one day before exam at 1.75x
HAHA me
2x 😅
Great and simple explanation sir, can u tell me which board are you using in the video for writing, It would be helpful for me to conduct online lectures for my students.
Thanks To You , It's Really Helpfull
superb lecture sir
super lecture salute u
awesome sir.u are great
Thank u Its was a good help
thank you nice explanation
Excellent 👌 thanks
there is no need of taking a bit from the OR gate and giving it to final output, as we can directly get the 5 bit output from the second 4 bit full adder
Thank you
Good teaching
🥳🥳🥳🥳
Thank you very much, sir.
Why were 0&3 bits were called min term and maxterm ? Those terms are defined entirely different in some other video! Anyways excellent explanation. Thanks for that 👍
Thanks,that was really helpful
Best teaching!!
Is there any video in ur series for serial adder?
at 7:45 u can say s3*.s2*=1,u can add 6(0110)
There is no requirement for case 3 from the first place
But great explanation ,thankss
Nicely explained!
Just for all the people wondering about Case 3, it's not required. Even if u do take Case 3, it will get eliminated since we find the minimum possible function.
Case 3 is not required.
Thanks a lot. I am still clueless about what my stupid professor taught us in class. This was so simple.
Very well explain sir. But how do you write this is verilog code?
Great Job!!
When will you complete your videos?
please make lecture on digital signal processing also.it is the toughest subject.
really superb
thank you so much
Thank you sir
love you sir
you're the best!!
Thank You So Much
This one is super🔥
May I know why we are adding 0110->6 to 2 digital Decimal while converting to bcd?
Hi! your video is very informative and easily understandable so I always see the videos related to the digital logic design on your channel. thank you! But I have a question related to this video, what is the previous carry?
Well done.