Henry's Law and Gas Solubility Explained

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  • Опубликовано: 22 ноя 2016
  • www.thegreatcourses.com/course...
    I am Professor Davis, and in this short clip I explain how Henry's Law can be used to calculate the solubility of a gas using its partial pressure and its Henry's Law constant.
    This clip is just a short sample from my new 60-lecture course available from The Great Courses. Learn more about the course at the link above and learn more about me and my other projects at / chemsurvival

Комментарии • 88

  • @kerryjohnson1066
    @kerryjohnson1066 3 года назад +19

    The only explanation that's helped me understand Henry's Law. Much love from Washington!

    • @samuraijosh1595
      @samuraijosh1595 3 года назад +1

      Yo, a recent comment!

    • @Emoney131
      @Emoney131 Месяц назад

      @@samuraijosh1595 hello from the future! buy NVDA !

  • @revanwallace
    @revanwallace 6 лет назад +5

    When beer and soda peopled talk about the "volumes of CO2" in their beverages, what exactly do they mean? Based on this video, I would say that a beverage under 4 atm of pressure (or 59 psi) at room temperature would have 2.7 liters of CO2 (at STP) dissolved in it for every liter of water. That sounds like 2.7 volumes of CO2 to me...but my "PSI to Volumes" charts say differently. So what is the right definition of "volumes of dissolved CO2"?

  • @nellvincervantes3223
    @nellvincervantes3223 4 года назад +18

    How did you get the new pressure for CO2, 4x10^-4 atm?

    • @user-qn9ym6hz2c
      @user-qn9ym6hz2c 3 года назад +5

      It's the partial pressure of CO2 in air. About 400 ppm.

    • @sofiasirajsirajabdu4258
      @sofiasirajsirajabdu4258 3 года назад +4

      @@user-qn9ym6hz2c how did he came up with22.4?

    • @khairaniputrimarfi8453
      @khairaniputrimarfi8453 3 года назад +3

      @@sofiasirajsirajabdu4258 that's a standard constant which is apply in 0 degrees c (STP), and 24.4 for 25 degrees c (RTP)

  • @henrygagejr.-founderbuildg9199
    @henrygagejr.-founderbuildg9199 Год назад +1

    Well said. It happens my name is Henry and I love the science of absorption, adsorption, phase change, energy transfer etc because of my work with Hempcrete. Would love to start a conversation with you.

  • @sreeguru7055
    @sreeguru7055 3 года назад +1

    Thank you. Great explanation

  • @brandongriggs6934
    @brandongriggs6934 4 года назад +5

    Assuming the solubility of CO2 in water when the can opens was not negligible, would we subtract that amount from our final answer? Also, where did you get the partial pressure of 4.0*10^-4 atm from? Thanks! :)

    • @MdJunayed
      @MdJunayed 2 года назад +2

      Partial Pressures of Atmospheric Gases table... 0.3mm Hg = 3.9 x 10^-4

  • @nabu7354
    @nabu7354 5 лет назад +3

    Thank you for this explanation. I'm confused why they call it "dissolved" which usually refers to a solid dissolving into a liquid changing its physical structure. it just seems that it is only referring to the presence of CO2 (in its gas form) in the liquid, which needs a considerable amount of pressure to force it into that liquid anyway. So does its structure/physical properties change in any way when described as "dissolved" or is it still in its gas form? I'm confused as it seems to contacdict the physical phases graph of CO2 to refer to it as "dissolved". Apologies if this is a stupid question.

    • @magnuswootton6181
      @magnuswootton6181 2 года назад

      if you matched it one co2 for every h in the water, the co2 would probably class as a solid now u compressed it down so much. i think its about 20,000 psi to do it. (9-10 tonnes of pressure.)

  • @riepie13
    @riepie13 7 лет назад +45

    Just leave us hangin like that ?!

    • @isiTsotsi
      @isiTsotsi 4 года назад +6

      Yes, this is actually an ad and doesn't have the honesty to say so at the beginning. He didn't even talk about a partial pressures.

  • @sumitbarik6247
    @sumitbarik6247 2 года назад

    Can any one answer what is the relationship between the Henry's law constant and CO2 and affect on PH.

  • @m.r.5129
    @m.r.5129 5 лет назад

    This was helpful.

  • @nabu7354
    @nabu7354 3 года назад +1

    what about temperature? is that not in the equation?

  • @saurabhmodh1899
    @saurabhmodh1899 6 лет назад +5

    Nice Expanation

  • @raghavendrapotluri5861
    @raghavendrapotluri5861 5 лет назад +2

    Is there a law or formula to calculate what time is required for the dissolved gases to affervate (come out of the liquid) once the pressure is removed???

    • @yashdeole1413
      @yashdeole1413 5 лет назад

      No

    • @ishowspeedsuyi
      @ishowspeedsuyi 3 года назад +2

      I think Graham's law of diffusion or effusion will help you indeed which states that rate of effusion is directly proportional to pressure/square root of molecular mass.
      And well that's a comparative law! You can use to compare two different effusions or diffusions!
      Hope this helps :)

  • @nyhyl
    @nyhyl 4 года назад +10

    Why does it drop to 4.0 * 10^-4 atm? The standard atmospheric pressure is 1 atm and not 0.0004 atm.

    • @marladeklotz6693
      @marladeklotz6693 4 года назад +26

      .0004 atm represents the amount of CO2 in the atmosphere as a partial pressure. All the atmospheric gases act independently and add up to 1 atm.

    • @beulahnarendrapurapu2029
      @beulahnarendrapurapu2029 4 года назад +6

      There is 0.04% CO2 in the atmosphere (approximately). So according to Daltons Law of partial pressures, the partial pressure of CO2 should be (mole fraction or fraction of molecules)*(total pressure)= (0.04/100)*(1 atm) = 0.0004 atm

    • @athiholotibusinesstalk321
      @athiholotibusinesstalk321 4 года назад +2

      Where’s did we get 0.04% now. From the statement we have 4atm Pco2.

  • @dakshjashnani6584
    @dakshjashnani6584 3 года назад

    Very helpful to clear my concept .......... from a student of class XI

  • @andrejulian8378
    @andrejulian8378 3 года назад

    what could be the reason for the exclusion?

  • @siddharthkumar4279
    @siddharthkumar4279 3 года назад +2

    Thank you sir. Much love from india❤️❤️

  • @andreichicos
    @andreichicos 7 лет назад +2

    Useful

  • @prathamhalder4620
    @prathamhalder4620 2 года назад

    thanks for such a lovely explanation. love from India

  • @vadtaldhampatelamee4127
    @vadtaldhampatelamee4127 4 года назад +1

    Thanks for video

  • @dr.pathak1954
    @dr.pathak1954 4 года назад +5

    Veryy helpful.
    Love from India.

    • @ChemSurvival
      @ChemSurvival  4 года назад +4

      I'm so glad it was useful to you! Love back from America.

  • @winnervinny396
    @winnervinny396 6 лет назад +1

    Very interesting

  • @oseremeeromosele8578
    @oseremeeromosele8578 7 лет назад +7

    Where is the 22.4 L/lol derived from?

    • @ChemSurvival
      @ChemSurvival  7 лет назад +12

      PV = nRT
      When:
      P = 1 atm
      n = 1 mol
      T = 273 K
      R = 0.082 L*atm/(mol*K)
      V must be equal to 22.4 L

    • @MrAntsunator
      @MrAntsunator 6 лет назад

      ChemSurvival But the problem says that it's room temperature (25°C = 298,15K).

    • @tarveshmaheshwari
      @tarveshmaheshwari 5 лет назад +1

      @@MrAntsunator Hi, *Note that In PV=nRT, both side the unit of temperature is in Kelvin, so it doesn't matter weather the temperature is in Kelvin of Celsius. If 25°C = 298.15K then R must be in Celsius also...* I hope you understand that...

  • @blueblood-_-
    @blueblood-_- 2 года назад

    The lecture was amazing but it would have been even better if you discussed mole fraction relation .

  • @mokshsurya1681
    @mokshsurya1681 2 года назад

    Keep it up sir 🙏

  • @rudrasaiprasad
    @rudrasaiprasad 4 года назад

    Where did you got the value of k

    • @khushichogle1266
      @khushichogle1266 4 года назад

      Rudra sai prasad it’s a constant....you have specific value for each gas

  • @06howea1
    @06howea1 2 года назад

    This may help us solve risigg sea temps and sea acidification

  • @b3bravebybrain167
    @b3bravebybrain167 3 года назад +1

    Thanks sir

  • @furtherpoint
    @furtherpoint 3 года назад +2

    Very helpful thanks for this video 💖 from INDIA

  • @abdelrahman_alrawi
    @abdelrahman_alrawi 3 года назад

    thanks a lot

  • @bscc181
    @bscc181 3 года назад

    Thank u sir

  • @brettruss3359
    @brettruss3359 5 лет назад +1

    killed it

  • @leosev
    @leosev Год назад

    Thanks for the video! But isnt it true that CO2 doesnt obey Henrys law???

    • @ChemSurvival
      @ChemSurvival  Год назад +1

      You're correct. The CO2/water system is a particularly non-ideally behaving system when it comes to Henry's law and maybe wasn't the best choice for an example. This is largely because of the complex equilibria among dissolved carbon dioxide, carbonic acid bicarbonate and carbonate ions that results when CO2 is dissolved in water. In hindsight a different gas or a different solvent might have been a smarter choice. Nonetheless, the fundamentals of Henry's law are well covered I think.

  • @jasjeetsingh9458
    @jasjeetsingh9458 3 года назад +3

    Henery's law is P=kS and not what stated in the the video.

  • @shripratapsinhjihindividha5556
    @shripratapsinhjihindividha5556 4 года назад +1

    Love from India 🖤🖤🖤
    From a jee aspriant 🖤🖤🖤

  • @pradeepkumarp6870
    @pradeepkumarp6870 4 года назад +1

    I have good idea to increase solubility of gas in water without increase pressure...

    • @vevo5086
      @vevo5086 4 года назад

      what is this idea.i wanna get a wider understanding of this topic.
      another point can we be whats friends.

    • @pradeepkumarp6870
      @pradeepkumarp6870 4 года назад

      @@vevo5086 surface of water and area of gas is too high... so it is required more pressure for solubility... So we divide it to very small particle... Its up to 300 - 500nm tube for water... 2000-2500 milli litter for gas... We can achieve this... Definitely we increase solubility of gas...

  • @suheshraj2677
    @suheshraj2677 Месяц назад

    Badiya hai mere pass😊

  • @Munda0.94
    @Munda0.94 2 года назад

    Thanku sir😍 I'm from India🖤

    • @ChemSurvival
      @ChemSurvival  2 года назад +1

      You are very welcome!!!!

    • @Munda0.94
      @Munda0.94 2 года назад

      @@ChemSurvival thanku 🖤 so much sir again

  • @theexamgyani6371
    @theexamgyani6371 4 года назад

    Rajkiran Sir Rocks

  • @crazzetrain
    @crazzetrain 4 года назад +2

    could you give us the weather report while you're there?

    • @ChemSurvival
      @ChemSurvival  4 года назад +3

      Partly cloudy with a 100% chance of the partial pressure of a gas being proportional to the concentration of that gas dissolved in the solution below it...... duh

    • @crazzetrain
      @crazzetrain 4 года назад

      ChemSurvival 😂😂

    • @shripratapsinhjihindividha5556
      @shripratapsinhjihindividha5556 4 года назад

      @@ChemSurvival 😂😂👍👍👍

  • @quartzzz165
    @quartzzz165 3 года назад

    hi sheldon

  • @jaysingh-pj2oq
    @jaysingh-pj2oq 3 года назад

    Hey

  • @Silver_Eagel_95
    @Silver_Eagel_95 3 года назад +1

    Hello

  • @piyushlohani5
    @piyushlohani5 3 года назад +1

    Easy to understanding love from India I am a jee aspirents

  • @amanmo862
    @amanmo862 3 года назад

    Just proved soda gets flat over time once opened

  • @nraishanzr3333
    @nraishanzr3333 4 года назад +2

    he looks like a freakin meteorologist on TV loll

    • @ChemSurvival
      @ChemSurvival  4 года назад +4

      Today's prediction... 100% chance of you subscribing to my channel B-)

  • @DubMastersNetwork
    @DubMastersNetwork 6 лет назад +1

    there is a problem in this answer

  • @Wolfeywolf16
    @Wolfeywolf16 6 лет назад +6

    That dramatic music at the beginning....really???

    • @ChemSurvival
      @ChemSurvival  6 лет назад +5

      Just having a little fun with Movie Studio.... Don't be hatin' :-)

    • @Wolfeywolf16
      @Wolfeywolf16 6 лет назад +1

      ChemSurvival uhhh...im not

    • @ChemSurvival
      @ChemSurvival  6 лет назад +2

      good to hear (and I hope you liked the rest of the video more than the intro). Plenty more videos on my channel that I hope you will check out, also.

    • @Aguafrescas
      @Aguafrescas 4 года назад

      Yes it was necessary

  • @brandonpetrovich2023
    @brandonpetrovich2023 4 года назад

    Soda.

  • @enrihoward6077
    @enrihoward6077 Год назад

    Never trust anyone that does scientific notation for .12.