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I did it this way: Given that √x/(x+1)=1/3. Squaring both sides we get, x/(x^2+2x+1)=1/9. Now applying invertendo we get, (x^2+2x+1)/x=9/1. Dividing both sides by 2 we get, (x^2+2x+1)/2x=9/2. Now applying dividendo on both sides , (x^2+1)/2x=7/2. Dividing both sides by 2 , (x^2+1)/x=7/1. Now applying invertendo we get , i.e x/(x^2+1)=1/7.
Τι γεύση πορτοκαλιού 🍊 Let's solve this We have to find x/x²+1 =? Let's simplify the denominator x/ (x+1)² - 2x --------------(1) And if you cross multiply the given equation we get 3sqrt(x) = x+1 -------(2) Put 2 in 1 we get x/9x -2x =x/7x =1/7 😊😊😊😊😊😊😊😊😊😊😊
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A tale of two videos: SyberMath and aplusbi.
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(x+1)^2 = 9x
x^2 + 2x + 1 = 9x
x^2 = 7x - 1
x^2 + 1 = 7x
x/(x^2+1) = 1/7
Great!
I did it this way:
Given that √x/(x+1)=1/3.
Squaring both sides we get,
x/(x^2+2x+1)=1/9.
Now applying invertendo we get,
(x^2+2x+1)/x=9/1.
Dividing both sides by 2 we get,
(x^2+2x+1)/2x=9/2.
Now applying dividendo on both sides ,
(x^2+1)/2x=7/2.
Dividing both sides by 2 ,
(x^2+1)/x=7/1.
Now applying invertendo we get ,
i.e x/(x^2+1)=1/7.
Let t= x/(x²+1) which we want.
We take the reciprocal of first equation.
(x+1)/√x = 3
→ (x²+1+2x)/x = 9
→ 1/t + 2 = 9
→ t = 1/7
Got it using the first method.
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without watching:
(√x)/(x² + 1) = 1/3
(x + 1)² = 3√x
x²+ 2x + 1 = 9x
x²+ 1 = 7x
x/(x²+ 1) = 1/7
...and after? 😜
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You are amazing! 😍😁
@@SyberMath: Thank you. So are you!
@@roberttelarket4934thanks! ❤
√x = (x+1)/3 so x=(x² + 1 + 2x)/9 Remplacing x/(x² + )=x/7x = 1/7 It takes less than 1 minute :-)))
Τι γεύση πορτοκαλιού 🍊
Let's solve this
We have to find x/x²+1 =?
Let's simplify the denominator
x/ (x+1)² - 2x --------------(1)
And if you cross multiply the given equation we get
3sqrt(x) = x+1 -------(2)
Put 2 in 1 we get
x/9x -2x =x/7x =1/7 😊😊😊😊😊😊😊😊😊😊😊
9x=x^2+2x+1...x^2=7x-1...?=x/7x=1/7
I did it
Answer = 1/7
🔥😃✌️👍🔥😃✌️👍
3(x)^1/2/x+1=1 3(x)^1/2=1(x+1)
3(x)^1/2=x+1 (x)^1/2=x+1/3
x=0,146 => 0,146/(0,146^2+1)=0,142 ≙ 0,97x
[ x/(x^2+1)=1/7 ]
Don't need a delta, x² +1 =7x. Only rewrite this.
why thi tooooooooooooo easy
[sqŕt(x)]/(x+1)=⅓
(x+1)/sqrt(x)=3
Squaring: (x²+2x+1)/x=9
x +(1/x)=7
Let t=x/(x²+1) --> 1/t=(x²+1)/x
=x+(1/x)
=7 --> t=1/7
x/(x²+1)=1/7
√x/(x + 1) = 1/3
(x + 1)/√x = √x + 1/√x = 3
E = x/(x² + 1)
1/E = (x² + 1)/x = x + 1/x
(√x + 1/√x)² = 3²
x + 1/x = 7
1/E = 7 => E = 1/7