Design of plate girder |Design of steel structure (DSS)
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- Опубликовано: 17 окт 2024
- part -2 video link 👇👇👇👇👇
• Design of plate girder
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Thanks.....
Great effort to explain all thing beautiful and nicely .. easiest way to found all solution .
Good going sir .
The video was really good and helpful but why you are not considering spacing between stiffeners (c) in order to calculate c/d ratio which will finally govern the value of Kv for Tcr,c. d
Sir i really like ur videos..u teach so well thank u🙏❤️
Thank you bhaiya ....aache se clear hogaya solution
Sir Can u please do calculations for Box type girder (2 web plates) ...please reply ...don't ignore
K=180: stiffener provided
Ok but while calculating shear strength aap kv from code 5.67 he liye
Stifferener ka tho bool gayena aap
Sir koi cran ka span or capital
Video ma voice bhot slow ha bas
Nice video
Can we contact you sir .....
Thank you so much sir💖🙏
sir very nice sir can you please upload 2nd part
Aaj he hogaa😃😃😱
2nd part video uploaded 😊😊
(Design of plate girder)
@@gkstudybk ...hi sir I have dout can you provide mail
Thanking you
Sir
D = (mk/fy)0.33
Please explain this calculation
Mera amount match nahi ho raha hai
m(B.M) ke value KN-M ma aayaa ha steps-2 ma. BUT
But hum m ke value N-mm ma put kartaa ha , to 10^6 sa multiple kartaa ha.
10^6 sa multiple karoo Ans aa jayaga😊
I hop you understand.when you understand then reply me 😊
@@gkstudybk
Example
M = 9960.93
K =180
Formula
= (Mzk/250)0.33
=( 9960.93 x 10^6 x 180 / 250 ) 0.33
=( 9960.93 x 1000000 x 180 / 250 ) 0.33
= √ 1792967400000 / 250
= 12148.54 / 6.30. (cube root )
= 1928.46
(1787.96 this ans on your video )
Please explain me
1787.96 he aa rahaa ha
(0.33 power ha.)
=(9960.93×10^6×180÷250)^0.33
=(1792967400000÷250)^0.33
=(7171869600)^0.33
=1787.96
I hop you understand 👍👍
When you understand then reply me 😊
Plz sir foot bridge karba do
Loud bol bhai