i had about 30 minutes to hand in a quiz for uni and this was one of the exercises. i was frantically searching for how to solve it and this video saved me! everything was fast and clear and i got a good grade because of it :) i found out later that you also have a video with the general formula, which would have been even faster, so i wrote it down for future use lol
You say "voltmeter or galvanometer", but they have different resistances. The voltmeter resistance will be very high, but if you connect a galvanometer (= very sensitive ammeter), its resistance is very small, and the bridge potential will be forced to be (very close) to zero, with a finite current across it. (Your other bridge video on solving for currents would then be needed.)
question: when we figure out the voltage across the unbalanced bridge can we place a resistor in place of the voltmeter and still have the same voltage across it?
For this case it's not too bad. First find the total current through the battery, then how it is divided into each branch, then use V=IR to calculate the voltage drop across each resistor.
Hello , I have a small suggestion for you...maybe you should change your channel name because When I search it on RUclips your channel doesn't show up . And I think this is a real problem
your mathematic calculations are written in a way that is confusing. The 1/2.4 ohms is wrong. It should be 1 over ((1 over 4)plus (1 over 6)) im not being pedantic, as that implies the answer is 0.41666 recuring
i had about 30 minutes to hand in a quiz for uni and this was one of the exercises. i was frantically searching for how to solve it and this video saved me! everything was fast and clear and i got a good grade because of it :) i found out later that you also have a video with the general formula, which would have been even faster, so i wrote it down for future use lol
this comment made my day.
Thank you for helping speed along my learning process of this step! God bless!
You say "voltmeter or galvanometer", but they have different resistances. The voltmeter resistance will be very high, but if you connect a galvanometer (= very sensitive ammeter), its resistance is very small, and the bridge potential will be forced to be (very close) to zero, with a finite current across it. (Your other bridge video on solving for currents would then be needed.)
Correct, I shouldn't have said galvanometer... Thanks!
Thank you thank you thank you I was so stuck until I saw this
Welcome!
Is it acceptable to just say: 3 - 2,25 = 0,75V. Is it always necessary to use the 9V or will that always give the same answer? Thank you
question: when we figure out the voltage across the unbalanced bridge can we place a resistor in place of the voltmeter and still have the same voltage across it?
no. that is a different circuit. however i have posted a video on how to solve that type of circuit.
Thank you. This really helped!
You're welcome!
Have you done the video solving the bridge just using variables?Thanks
Sorry no.
For this case it's not too bad. First find the total current through the battery, then how it is divided into each branch, then use V=IR to calculate the voltage drop across each resistor.
very helpful thank you
Very helpful 🙏
Glad to hear that
Hello , I have a small suggestion for you...maybe you should change your channel name because When I search it on RUclips your channel doesn't show up . And I think this is a real problem
I appreciate the suggestion.
your mathematic calculations are written in a way that is confusing. The 1/2.4 ohms is wrong. It should be 1 over ((1 over 4)plus (1 over 6)) im not being pedantic, as that implies the answer is 0.41666 recuring