Any time you come across this kind of question were it ask us to solve for X but our X is power always make the base equal so that you can equate the power and solve for X.
Explaination:First better you (X^√X).have on LHS. By squaring this LHS you have 2 becoming 4. Then √X becomes X. So on LHS you have 4^X. Now take the RzHS. RHS is 8×X. If you square this it becomes 64X^2. Now in RHS you can write 64 as 2×2×2×2×22.=64. So RHS is 2^6×X^2. Now both LHS and RHS have the same base as 2. So you 2X=6X^2. Cancelling one X on both sides You get 2=6X. So Xus 2/6.
You do know though that everytime you square an unknown you lose a solution? This also the same reason why we don't "cancel out " unknowns. the solution we lose from squatng the unknown is -1/9 . if we let y = x^0.5 instead, we solve this as a quadratic equation without losing the solution. Forgive me I'm a purist I mean no harm.
Very nice but it would have been best if he had verified the answer 1/9 because the square root of an exponent is a little unusual. v1/9 = 1/3 2^1/3 = (2^3)^1/9 2^1/3 = 2^3/9 2^1/3 = 2^1/3
An alternate solution for final answer once you have X = 9 * (X ^ 2) X / 9 = X ^ 2 (X / 9) / X = (X ^ 2)/X divide both sides by X 1/9 = X X = 0 second value assumed by inspection
Before watching: First and foremost, x=0 gives us 2^0=8^0 -> 1=1, so x=0 is a solution. Are there others? Well, 8 =2^3, so the right hand side can be written as 2^(3x). We now have the same base raised to two different powers equal to one another; this can only work if the powers are equal. Thus we have Sqrt x = 3x. Square both sides... X = 9x^2 Divide each side by 9x to get... 1/9 = x Our solutions thus, are x=0 and x=1/9.
I have a question sir. (3x)^2 is the same as (3x)X (3x) right? So aren't we supposed to use the law that says "when you're multiplying powers of the same base you add the exponets" that our answer is 3x^2 ???
Good explanation sir , keep it up, thanks 👍👍👍
I have liked it sir thanks.
Any time you come across this kind of question were it ask us to solve for X but our X is power always make the base equal so that you can equate the power and solve for X.
Please can you be my teacher
I don't understand
Hey, which part
I don't understand
Exponent and Power are two different things.
Can't we use x(x-9)=0
Easy but genius thanks
Clear information sir thank you 😊
I'm Uzbek. Our mathematics the best of the world
@UniversalMATEMATIKA
That's great thanks
Great job
Thank you for teaching me
Easy and understandable
Correct sir👍
Very very nice
Nice 👍 solution
Well done 👍✅
Thanks sir, it came at the right time
Explaination:First better you (X^√X).have on LHS. By squaring this LHS you have 2 becoming 4. Then √X becomes X. So on LHS you have 4^X. Now take the RzHS. RHS is 8×X. If you square this it becomes 64X^2. Now in RHS you can write 64 as 2×2×2×2×22.=64. So RHS is 2^6×X^2. Now both LHS and RHS have the same base as 2. So you 2X=6X^2. Cancelling one X on both sides You get 2=6X. So Xus 2/6.
I do appreciate sir
Always you are the best teacher ❤
You do know though that everytime you square an unknown you lose a solution? This also the same reason why we don't "cancel out " unknowns. the solution we lose from squatng the unknown is -1/9 . if we let y = x^0.5 instead, we solve this as a quadratic equation without losing the solution. Forgive me I'm a purist I mean no harm.
The solution is okay
Great
Thanks you sir
1/9, 0
Greatest
I really enjoyed it... Thank you so much
Thank you so much Sir
Instead of using quadratic equations, we can also use indices to arrive at the same answer.
I would like to know how x=9x² can be solved by indices
Thank you so much easy and understandable
Nice
Sir there is a quicker and easier method
3x=√x
3= √x/√x×√x
3=1/√x
3√x=1
9x=1
X=1/9
Very nice but it would have been best if he had verified the answer 1/9 because the square root of an exponent is a little unusual.
v1/9 = 1/3
2^1/3 = (2^3)^1/9
2^1/3 = 2^3/9
2^1/3 = 2^1/3
Think you, it's helpful
Try taking the natural log of both sides: √x*ln2=x*ln8; x=(ln2/ln8)^2=1/9
Check: 2^(1/3)=8^(1/9)=∛2
The answer is not consoling with the question sir
Thanks alot sir that was great. May you please solve for me this: 4X^3 -X^2 -58X +60=0
x=
4
1
−
3
(
64
9801
+
16
3
1766271
i
)
1/3
−
16(
64
9801
+
16
3
1766271
i
)
1/3
235
Take log on both the sides , and enjoy .
2^√x = 8^x = 2^(3*x)
√x = 3*x
√x*(1 - 3*√x) = 0
√x = 0, 1 = 3*√x
x = 0, 1/9
Thanks
THIS WAS TOO MUCH EASY!
Yeah I solved it in my head in 5 seconds 😅
Or just take log base 2 on both sides
X= 1/9 or X=0
You are ✅️
An alternate solution for final answer once you have X = 9 * (X ^ 2)
X / 9 = X ^ 2
(X / 9) / X = (X ^ 2)/X divide both sides by X
1/9 = X
X = 0 second value assumed by inspection
Simplest
It clear
The answer is 0
Thank you very much sir 🙏
Sir thank but my sir solve this in 10 second and in easy way 😅😅
Mathematics is good 😊😊
🎉
Before watching:
First and foremost, x=0 gives us 2^0=8^0 -> 1=1, so x=0 is a solution. Are there others?
Well, 8 =2^3, so the right hand side can be written as 2^(3x). We now have the same base raised to two different powers equal to one another; this can only work if the powers are equal. Thus we have
Sqrt x = 3x.
Square both sides...
X = 9x^2
Divide each side by 9x to get...
1/9 = x
Our solutions thus, are x=0 and x=1/9.
Top. Excelente aula.
.
Bom vídeo.
X=0 and X =1/9
We're young just suppose to square root 3x then cancel out in both sides🤨🤨🤨
❤
negative 8 =o it's not easy to solve without a specific domain.
thanks for teaching sir
Thanks sir for teach
0 or 1/9
i am watching it right now
X=0 etX=1/9
0 , 1/9
I dont understand because you multiplied 3x to the power of 2 but after getting the answer the power still remains why
x-9x^2=0 is a 2nd order equation and needs 2 answers, x=0 and x=1/9.
I didn't stress myself doing this
The answer is 1/9
Full support from India 🇮🇳
Your nw sub. Hre
I am from India but I like a video ❤❤❤❤
Neden beğenmeyesin ki? Matematik dünyanın her yerinde aynı ve senin milliyetinle bir alakası yok. Ucube😂
0 и 1/9
✅
❌ x =9
Existe alguna aplicación práctica de estas ecuaciones?
Ó solo son teorías complicadas?
3 determines how many times 2 multiply by itself to get 8
Getting the square root doesn't mean you square a number but instead raise it to one half
Wow
X=1/3
1/9
Thanks you sir I will appreciate
Thank you sir l can now do it my self thanks again ❤
Mr sichamba where is 3 coming from?
Am enjoying ba sir❤❤❤
X=0 and ×=1/16
Pls sir l need a video on modular arithmetics
X = 1/9
2 cube =8 and when we shift root symbol from one side to the another it turns to square
I have a question sir. (3x)^2 is the same as (3x)X (3x) right? So aren't we supposed to use the law that says "when you're multiplying powers of the same base you add the exponets" that our answer is 3x^2 ???
No. (3x)^2 is not the same as (3x)x. They are totally different
0
0 and 1/9
Please can someone help me to learn math I will never forget him and God bless him 😢😢
look there you said negative 1 over negative 9 where did that negative on 1 go
2x2x2= 8
✓x =3x so x=1/9
the ans is x=3^½/3
Is great
9x^2
I don't understand what you are doing sir,
He forgot to give the condition that x not equal to 0😂😂
Based on inspection alone, x = 0 works. 1 = 1. Is there another solution? Yeah, do some log work, but I don't give a rip.
Highest marks 😮