There is a problem with this. When you are solving an equation, you must not just divide both sides by an expression involving x, because by doing so, you lose solutions. What he should have done is move everything to one side and factorise to give x^2(x^2-1)(x^4+x^2-8)=0 which gives potential solutions as x=0, 1, -1 aswell as as his solutions. We then exclude 0,1 -1 as solutions as when we substitute them into the original expression we get 0/0 which is undefined.. So we end up with just his solution, but his method would lose about half the marks.
There is a problem with this. When you are solving an equation, you must not just divide both sides by an expression involving x, because by doing so, you lose solutions. What he should have done is move everything to one side and factorise to give x^2(x^2-1)(x^4+x^2-8)=0 which gives potential solutions as x=0, 1, -1 aswell as as his solutions.
We then exclude 0,1 -1 as solutions as when we substitute them into the original expression we get 0/0 which is undefined..
So we end up with just his solution, but his method would lose about half the marks.
Okey
А как же х в степени 8 должно иметь 8 корней?
В заставке одно уравнение, а по факту решается другое 😂
Ah you announced another fraction in the beginning ::
But it is easier with x^4 - x^2 😉
x^2-1で、割っちゃだめ。x=±1は？
Comme ça , ça va mieux
サムネと実際解いてる問題が違う。
問題にxは実数とは書いていない。虚数でもいいんじゃないのか。