The proper logic for determining of 7/8 is this - R7C8 is either green (9) or yellow (8). The blue line in box 6 must have a 1 (since there are 2 4s looking at it) and not have 6, so it's either 125 or 135. R5C7 can't be a 1. If R7C8 is 8 (yellow), the blue line in box 6 is 125 and R5C7 becomes 3, forcing red to also be 8. Therefore, R7C8 must be 9 and then go from there
You need to be very very careful when colouring, in this case the orange 89 pair in box 9 was not useful and confused Mark into a wrong deduction. If anyone knows the way forward please elaborate, the mistake happens at 21:40
Assuming you've got most cells pencil marked by this point - Once you've got your possible red and yellows in place - check R7C8, and see if placing a number causes any issues with the digits on the green line that spans Box 2>Box 6.
From 21:40, if you explore the option of R7C8 being an 8, it forces R7C2 (red) to be "7" and the blue equal-sums line in box 6 to be "1-2-5" (since 1-3-4 isn't possible by the two 4s already in rows 5 and 6), this then leaves R5C7 to be "3" as the only option remaining. This "3" on a German Whispers green line pushes R4C6 (red) to be "8". Since R7C2 and R4C6 are both marked red (correctly by Mark), we have reached a contraction as red cannot be both "7" and "8". Therefore R7C8 must instead be "9". This doesn't immediately determine the colouring at the bottoms of columns 5 and 8 but there is more colouring to be completed in the rest of the grid. The "9" forces "1-3-5" on to Box 6's blue equal-sums line, leaving yellow ("7" or "8") to only be possible in the top row of Box 6 and thus also in R6C2 in Box 4 (as it can't be on the whisper since this is low in R6C3). The "1-3-5" in Box 6 also forces the "2" onto R5C7. Mark hasn't yet resolved the pencil marking in Box 8, which is now "1-3-5" down the left side and "2" and "4" on the right. The "2"s positioning in Box 6 and Box 8 forces R4C5 to be a "2". and, in turn, R6C3 to also be "2". This then means R8C3 is now a "3" separating an 8 and 9 (on the whisper) at the bottom of column 3 thus giving you that "7" is red and "8" is yellow. I'm allowing Mark a wine click given it's Christmas Eve!
I got a lot more of the puzzle done by colouring cells 'high' (6789) and 'low' (12345) before resolving the 7 and 8s. I used bifurcation to get the 6s on the blue lines. I finally used colouring and bifurcation again to resolve the 7 and 8s.
I got stuck on the 7-8's and came to the video for a solution. Was disappointing to see Mark solving from what I understand was a lucky guess. Surely the 8 below the 7 in box 9 could also have been red? Amyway, happy holidays to all!
*_"Red_*_ is definitely in one of those two [r9c7 or r8c8]..."_ (Mark @21:16) Incorrect. It is either in *r8c8* or *r9c8.* _"... so if it cannot go there [r9c7], it must be this [r8c8]"_ (Mark @21:38) Correct conclusion reached with incorrect logic. You did not rule out *r9c8❗* You missed the most enjoiable part of the solve, which was the final disambiguation for the *7-8* pair.
I did quite well up until near the end, got stuck and bifurcated on a hunch which actually worked out. 😛 Mark's coloring of the high would have shown me what I needed, but still managed to finish in 19:38 (conflict checker off), many thanks to James for a very nice puzzle!
I finished in 22:30 minutes. This was a really clean puzzle that perfectly executed region sum rules. That was one of the most fun kind that I have done. I think my favorite part was seeing that the region sum in box 6 couldn't be 8 with a 125 set as this causes a cascade that would force both r9c3 and r9c8 to both be the same number. That was so fun to spot in my head. This has to be one of my favorites. As always, it feels good to beat Mark's time. Great Puzzle!
Christmas finery, Christmas in the puzzle, all very fun. I don't have time to try this puzzle now, but will definitely do so soon. This was an interesting puzzle; I like the interactions between the blue and green lines. Thanks for the video, Mark, and a very Merry Christmas to you and yours!
You could identify purple as early as 7:45 when the 89 pair is established in box 9, by asking where purple goes in box 6. Either it's on a three-cell region sum line with a single digit sum and must therefore be 6, or it's in r7c8 and can't be 7, 8, or 9, so again it has to be a 6.
The rules in the green box in the video make sense. Those in the app do not. Box 7 is then confusing. Edit: then, I couldn't sort the blue lines in box 2. Was r2c4 part of a bendy line that went into boxes 4, 5, 2 or part of a different line that went into boxes 3 and 2? And how was that consistent with box 7... ? In short, what the blue lines did and how they were divided was not obvious to me.
There is another Definition of the Blue line which is slightly harder to understand but avoids disambiguity „box borders divide blue lines into segments of the same sum“
@@shadowpenguin3482 "box borders divide blue lines into segments of the same sum" - Unfortunately, even that rule does not disambiguate the blue line(s) spanning boxes 2, 3, 4, and 5. Specifically, is that one line straight line going from box 4 to box 3, which happens to include an offshoot (a branch) in box 2, or is it two lines (one from box 2 to box 3 and one from box 2 to box 4)? I haven't started the puzzle yet, so hopefully it'll become apparent while solving it.
There were 2 things that helped me. First, I know how region sum lines normally work, and second, the sum in box 7 as you mentioned cleared up that the rules in the app were not only confusing, but wrong. So I just assumed the normal use and carried on.
@@debrawilden1971 I'm not sure if that answers the question, though. Sure, you can get 9 out of that cell, but you can't get red out of there at this point in the solve - red is 7 or 8, so determining R9C8 is an 8 doesn't tell you whether it's red or not.
Assuming you've got most cells pencil marked by this point - Once you've got your possible red and yellows in place - check R7C8, and see if placing a number causes any issues with the digits on the green line that spans Box 2>Box 6.
Great construction. I needed separate colours only for *7-8* pairs at the end. 5 was white. Everything else was *blue* or *orange* to represent polarity. By the way, the final disambiguation of the *7-8* pairs was perhaps the most enjoyable part of my solve and Mark missed it because he used incorrect logic to reach the same result, as I explained in a separate comment.
Got as far as needing to resolve the identity of the 7/8 pair, then realised that if R5C7 was 3, then the orange would become 7 through the blue line in box 6, but this would also make the orange in R4C6 8. Hence breaking the puzzle. As I'd eliminated everything but 2/3 from R5C7, knew it had to be 2 and went from there. Don't know if there's any flaws in that thinking, but it solved me the puzzle in 37 minutes as a beginner/intermediate solver.
The rule on reguin sum line in this puzzle is incorrect. Classical ruling should be applied instead: Blue region sum line is split into segments by 3x3 box borders. Each segment along the line should have the same total, but different lines may have different totals.
117:49, broke the puzzle twice, looked at the video, saw that I ruled a 4 out of r7c6 at like the beginning because a 4 can't be in the middle of a green line (🤦♂️) and had to redo the puzzle. Of course, I mistyped a digit part way through and had to go through most of it a third time.
wow, I've never done 80% of a puzzle so quickly, only to grind to a half in the last 20%. 40ish minutes in the end, and I cracked the 7s and 8s a totally different way than Marc, which surprised me.
What is the proper method forward at 21:41? Mark's spouting nonsense at this point, as if red is not 7 it is 8, and that just means c8 in b9. Is bifurcation required to solve?
If you look at the 2-3 pair in box 6 attached to the German Whisper, if it is a 3 then "red" (in Mark's puzzle) is an 8. However, if it is a 3 then the region sum line in box 6 will sum to 8. That is a contradiction since the number attached to the region sum line in box 9 is not red.
1:16:40@#3669. Yet another one that started out reasonable, only to devolve into a quagmire. I got stuck for ages trying to break the deadlock. As clever as it is, I wish I hadn't started it. At least not today. I didn't really want to take this much time on a single solve.
The rule in the app -- "All digits along a blue line must sum to the same total in each 3x3 box the line visits" -- is incorrect. One needs only to look at boxes 4 and 7 to know this is incorrect. The rule in the video description -- "Box borders divide a blue line into segments with an equal sum" -- is correct.
*LOGICAL FALLACY* - 21:17 - Red could have been an '8' if it were in (Row 9, Col 8) = We *DEMAND* an apology...! LOL... We *DEMAND* perfection from Mark "Beast-Mode" Goodliffe...!
If r7c8 is 8 then r7c3 is 9 and R7c2 is 7. If r7c8 is 9 then the blue line is 135 and r6c6 is 135 as well so r7c3 cannot be 1. There is a 2/3 pair in column 3 (because the 1 in box 7 is in column 1), so r7c3 cannot be 7, and again R7c2 is 7.
Merry Christmas, or what is left of it. I think I had made a big mistake, but it turned out to be small... I had mislabeled 8 and 9 in boxes 7 and 9. After fixing that I was able to finish swiftly.
Rules: 02:23 Let's Get Cracking: 02:58 What about this video's Top Tier Simarkisms?! Three In the Corner: 1x (28:37) And how about this video's Simarkisms?! Ah: 8x (09:34, 11:44, 14:45, 18:02, 18:05, 18:45, 19:08, 27:57) In Fact: 4x (15:12, 16:29, 17:01, 20:37) Brilliant: 3x (00:48, 02:07, 28:40) By Sudoku: 3x (09:41, 27:21, 27:24) Obviously: 3x (00:44, 16:16, 19:27) Pencil Mark/mark: 3x (07:39, 25:12, 28:15) Naked Single: 1x (24:26) Lovely: 1x (24:37) Extraordinary: 1x (17:11) First Digit: 1x (10:01) Deadly Pattern: 1x (26:20) Hang On: 1x (27:42) Most popular number(>9), digit and colour this video: Thirty Five (4 mentions) One (79 mentions) Red (43 mentions) Antithesis Battles: High (15) - Low (11) Even (2) - Odd (0) Column (15) - Row (12) FAQ: Q1: You missed something! A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn! Q2: Can you do this for another channel? A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!
About the R9C8 controversy: I was able to desambiguate with A LOT of backtracking after assumptions. I don't know how Mark got it that fast without being confused by his own pencil marks.
The Description of the blue line is wrong. BOX 7 would have 4 numbers that the blue line visits and those sum at least to 10. Extra text needed like 'distinct groups on the same blue line count as different groups for the sum' .
I think the rules, while a bit awkward, do indicate 'the same total in each 3x3 box the line visits.' This means that every time the line enters the box, it will have the same total. It's not the sum of ALL the blue lines in the box that = the sum of the connected blue lines in another box. (In box 7, the line in C = R6C1 = R7C2.) (I know this to be the case because I've seen a lot of puzzles with this rule. The puzzling time is when the blue line is only in one box. That has happened and makes no sense! At that point, I think it's just cosmetic, but certainly leads to confusion.)
The text in the video and the description say "box borders divide the line into equal sum segments", which makes it clear. The rules in the puzzle itself is the less clear version, which sometimes tries to mean the equivalent to that, and sometimes means add all the segments together. Since it is impossible for 4 different cells to add to a single cell, it is clear that the alternate version used in the video and the description is correct. I think it is hard to edit the rules in an existing puzzle without making a new link and "resetting" the solution count for the puzzle.
Follow the usual solve process until you get stuck, and then look at the arrow clue that spans Box 9>Box 6 - there's a break in logic that doesn't require bifurcation to spot
The proper logic for determining of 7/8 is this - R7C8 is either green (9) or yellow (8). The blue line in box 6 must have a 1 (since there are 2 4s looking at it) and not have 6, so it's either 125 or 135. R5C7 can't be a 1. If R7C8 is 8 (yellow), the blue line in box 6 is 125 and R5C7 becomes 3, forcing red to also be 8. Therefore, R7C8 must be 9 and then go from there
"R5C6 can't be a 1" - citation needed!
If r7c8 is 8 then it is yellow. But this forces r5c7 to be 3 which forces red (in box 5) to be 8!
@@peaoui165it might be R5C7, not R5C6. The previous statement says 1 is on the blue line, thus 1 cannot be in R5C7.
Thank you! That's exactly where I got stuck. And yes R5C6 is a typo it's R5C7 that can't be 1 at that point.
@@peaoui165 sorry, meant R5C7, will correct. Thank you for noticing
21:17 How its possible R9C7 to be red? Why it is a candidate? R89C8 is candidates
You need to be very very careful when colouring, in this case the orange 89 pair in box 9 was not useful and confused Mark into a wrong deduction. If anyone knows the way forward please elaborate, the mistake happens at 21:40
With bifurcation (trying out the WRONG path, to see what conflict arises) I ended up with a 3 adjacent to a 7 on the bottom right leg of the X.
Assuming you've got most cells pencil marked by this point -
Once you've got your possible red and yellows in place - check R7C8, and see if placing a number causes any issues with the digits on the green line that spans Box 2>Box 6.
From 21:40, if you explore the option of R7C8 being an 8, it forces R7C2 (red) to be "7" and the blue equal-sums line in box 6 to be "1-2-5" (since 1-3-4 isn't possible by the two 4s already in rows 5 and 6), this then leaves R5C7 to be "3" as the only option remaining. This "3" on a German Whispers green line pushes R4C6 (red) to be "8". Since R7C2 and R4C6 are both marked red (correctly by Mark), we have reached a contraction as red cannot be both "7" and "8". Therefore R7C8 must instead be "9". This doesn't immediately determine the colouring at the bottoms of columns 5 and 8 but there is more colouring to be completed in the rest of the grid. The "9" forces "1-3-5" on to Box 6's blue equal-sums line, leaving yellow ("7" or "8") to only be possible in the top row of Box 6 and thus also in R6C2 in Box 4 (as it can't be on the whisper since this is low in R6C3). The "1-3-5" in Box 6 also forces the "2" onto R5C7. Mark hasn't yet resolved the pencil marking in Box 8, which is now "1-3-5" down the left side and "2" and "4" on the right. The "2"s positioning in Box 6 and Box 8 forces R4C5 to be a "2". and, in turn, R6C3 to also be "2". This then means R8C3 is now a "3" separating an 8 and 9 (on the whisper) at the bottom of column 3 thus giving you that "7" is red and "8" is yellow. I'm allowing Mark a wine click given it's Christmas Eve!
I got a lot more of the puzzle done by colouring cells 'high' (6789) and 'low' (12345) before resolving the 7 and 8s. I used bifurcation to get the 6s on the blue lines. I finally used colouring and bifurcation again to resolve the 7 and 8s.
@@timlewis2168 Thank you!
I got stuck on the 7-8's and came to the video for a solution. Was disappointing to see Mark solving from what I understand was a lucky guess. Surely the 8 below the 7 in box 9 could also have been red? Amyway, happy holidays to all!
Merry Christmas, Mark! Thanks for all you do.
*_"Red_*_ is definitely in one of those two [r9c7 or r8c8]..."_ (Mark @21:16)
Incorrect. It is either in *r8c8* or *r9c8.*
_"... so if it cannot go there [r9c7], it must be this [r8c8]"_ (Mark @21:38)
Correct conclusion reached with incorrect logic. You did not rule out *r9c8❗*
You missed the most enjoiable part of the solve, which was the final disambiguation for the *7-8* pair.
I did quite well up until near the end, got stuck and bifurcated on a hunch which actually worked out. 😛 Mark's coloring of the high would have shown me what I needed, but still managed to finish in 19:38 (conflict checker off), many thanks to James for a very nice puzzle!
I finished in 22:30 minutes. This was a really clean puzzle that perfectly executed region sum rules. That was one of the most fun kind that I have done. I think my favorite part was seeing that the region sum in box 6 couldn't be 8 with a 125 set as this causes a cascade that would force both r9c3 and r9c8 to both be the same number. That was so fun to spot in my head. This has to be one of my favorites. As always, it feels good to beat Mark's time. Great Puzzle!
I couldn't tell where r2c4 belongs to
Christmas finery, Christmas in the puzzle, all very fun. I don't have time to try this puzzle now, but will definitely do so soon. This was an interesting puzzle; I like the interactions between the blue and green lines. Thanks for the video, Mark, and a very Merry Christmas to you and yours!
Pretty sure red could also be at r9c8.
came looking for this kind of comment
Finished in 25:56. Great puzzle!
You could identify purple as early as 7:45 when the 89 pair is established in box 9, by asking where purple goes in box 6. Either it's on a three-cell region sum line with a single digit sum and must therefore be 6, or it's in r7c8 and can't be 7, 8, or 9, so again it has to be a 6.
The rules in the green box in the video make sense. Those in the app do not. Box 7 is then confusing.
Edit: then, I couldn't sort the blue lines in box 2. Was r2c4 part of a bendy line that went into boxes 4, 5, 2 or part of a different line that went into boxes 3 and 2? And how was that consistent with box 7... ? In short, what the blue lines did and how they were divided was not obvious to me.
Same for me.
There is another Definition of the Blue line which is slightly harder to understand but avoids disambiguity
„box borders divide blue lines into segments of the same sum“
@@shadowpenguin3482 "box borders divide blue lines into segments of the same sum" - Unfortunately, even that rule does not disambiguate the blue line(s) spanning boxes 2, 3, 4, and 5. Specifically, is that one line straight line going from box 4 to box 3, which happens to include an offshoot (a branch) in box 2, or is it two lines (one from box 2 to box 3 and one from box 2 to box 4)? I haven't started the puzzle yet, so hopefully it'll become apparent while solving it.
@@shadowpenguin3482 the comment mentioned the rules in the green box in the video which you copied verbatim.
There were 2 things that helped me. First, I know how region sum lines normally work, and second, the sum in box 7 as you mentioned cleared up that the rules in the app were not only confusing, but wrong. So I just assumed the normal use and carried on.
Merry Christmas to you and Simon!
21:13 Why can red not be in R9C8 here exactly?
Not sure exactly where you are in the solve, but I got R9C8 by seeing the blue lines in box 6 adding to 9.
@@debrawilden1971 I was the at a point where they could still be either 8 or 9, 125 or 135
so couldn't use that yet
@@debrawilden1971 I'm not sure if that answers the question, though. Sure, you can get 9 out of that cell, but you can't get red out of there at this point in the solve - red is 7 or 8, so determining R9C8 is an 8 doesn't tell you whether it's red or not.
@@Samoth1995 (Sorry I can't help further. I didn't follow the whole video, and I used diff colors then deleted them when all use.)
Assuming you've got most cells pencil marked by this point -
Once you've got your possible red and yellows in place - check R7C8, and see if placing a number causes any issues with the digits on the green line that spans Box 2>Box 6.
Wishing you and your family a Merry Christmas
Great construction.
I needed separate colours only for *7-8* pairs at the end. 5 was white. Everything else was *blue* or *orange* to represent polarity.
By the way, the final disambiguation of the *7-8* pairs was perhaps the most enjoyable part of my solve and Mark missed it because he used incorrect logic to reach the same result, as I explained in a separate comment.
Sounds like my xmas dinner, fun, a little bit of crunch, and satisfaction at the end
Wonderful puzzle. Merry Christmas from Germany.
Got as far as needing to resolve the identity of the 7/8 pair, then realised that if R5C7 was 3, then the orange would become 7 through the blue line in box 6, but this would also make the orange in R4C6 8. Hence breaking the puzzle. As I'd eliminated everything but 2/3 from R5C7, knew it had to be 2 and went from there.
Don't know if there's any flaws in that thinking, but it solved me the puzzle in 37 minutes as a beginner/intermediate solver.
The rule on reguin sum line in this puzzle is incorrect. Classical ruling should be applied instead: Blue region sum line is split into segments by 3x3 box borders. Each segment along the line should have the same total, but different lines may have different totals.
I really dislike box being counted as one segment without calling it out
117:49, broke the puzzle twice, looked at the video, saw that I ruled a 4 out of r7c6 at like the beginning because a 4 can't be in the middle of a green line (🤦♂️) and had to redo the puzzle. Of course, I mistyped a digit part way through and had to go through most of it a third time.
wow, I've never done 80% of a puzzle so quickly, only to grind to a half in the last 20%. 40ish minutes in the end, and I cracked the 7s and 8s a totally different way than Marc, which surprised me.
Mark didn't crack that part at all. He confused himself with the orange colouring in box 9 and simply got lucky it was the solution anyway.
Merry Christmas, and a very happy day if you don’t celebrate Christmas. Gorgeous jacket, Mark!
12:10 for me. Great puzzle!!
Nice fireplace in the back ;) Merry Christmas, Mark!
37:46 for me. I messed up the puzzle, but was able to salvage it. Now I'm off to Christmas Eve church service. Merry Christmas, all!!
22:04 for me this time. MUCH better!
90 minutes for me very enjoyable
26:09 ... a nice solve for Christmas Eve
Nice puzzle!
You look nice, Mark! Merry Christmas everyone!!
What is the proper method forward at 21:41? Mark's spouting nonsense at this point, as if red is not 7 it is 8, and that just means c8 in b9.
Is bifurcation required to solve?
If you look at the 2-3 pair in box 6 attached to the German Whisper, if it is a 3 then "red" (in Mark's puzzle) is an 8. However, if it is a 3 then the region sum line in box 6 will sum to 8. That is a contradiction since the number attached to the region sum line in box 9 is not red.
Ah, yes, if r5c7 is a 3, both r7c2 and r7c8 have to be 8, and that is a contradiction. I see now.
I can confirm. It's a beautiful sunny Christmas Day down here in Australia.
1:16:40@#3669. Yet another one that started out reasonable, only to devolve into a quagmire. I got stuck for ages trying to break the deadlock. As clever as it is, I wish I hadn't started it. At least not today. I didn't really want to take this much time on a single solve.
The rule in the app -- "All digits along a blue line must sum to the same total in each 3x3 box the line visits" -- is incorrect. One needs only to look at boxes 4 and 7 to know this is incorrect. The rule in the video description -- "Box borders divide a blue line into segments with an equal sum" -- is correct.
*LOGICAL FALLACY* - 21:17 - Red could have been an '8' if it were in (Row 9, Col 8) = We *DEMAND* an apology...! LOL... We *DEMAND* perfection from Mark "Beast-Mode" Goodliffe...!
If r7c8 is 8 then r7c3 is 9 and R7c2 is 7. If r7c8 is 9 then the blue line is 135 and r6c6 is 135 as well so r7c3 cannot be 1. There is a 2/3 pair in column 3 (because the 1 in box 7 is in column 1), so r7c3 cannot be 7, and again R7c2 is 7.
Another lucky placement!
I was just wanting to look for a nicer way of placing 78 than I have used.
Merry Christmas, or what is left of it.
I think I had made a big mistake, but it turned out to be small... I had mislabeled 8 and 9 in boxes 7 and 9. After fixing that I was able to finish swiftly.
Don t forget the given 4 in box 4 😉
26:12 finish. Merry Christmas to all!
You can get pretty far w/o givens but seems like the 3 givens dissolve 3 different cluster of cells
80m for me. A fun and festive solve
Rules: 02:23
Let's Get Cracking: 02:58
What about this video's Top Tier Simarkisms?!
Three In the Corner: 1x (28:37)
And how about this video's Simarkisms?!
Ah: 8x (09:34, 11:44, 14:45, 18:02, 18:05, 18:45, 19:08, 27:57)
In Fact: 4x (15:12, 16:29, 17:01, 20:37)
Brilliant: 3x (00:48, 02:07, 28:40)
By Sudoku: 3x (09:41, 27:21, 27:24)
Obviously: 3x (00:44, 16:16, 19:27)
Pencil Mark/mark: 3x (07:39, 25:12, 28:15)
Naked Single: 1x (24:26)
Lovely: 1x (24:37)
Extraordinary: 1x (17:11)
First Digit: 1x (10:01)
Deadly Pattern: 1x (26:20)
Hang On: 1x (27:42)
Most popular number(>9), digit and colour this video:
Thirty Five (4 mentions)
One (79 mentions)
Red (43 mentions)
Antithesis Battles:
High (15) - Low (11)
Even (2) - Odd (0)
Column (15) - Row (12)
FAQ:
Q1: You missed something!
A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn!
Q2: Can you do this for another channel?
A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!
Pretty sure you missed his mistake at 21:17, and him getting lucky.
14:53 a nice, quick, and easy Xmas Eve puzzle!
lookin' fine, mark!
Man I'm stuck on the puzzle and while trying to figure out what I should find on the video I instead see wrong logic to solve the puzzle.
How do the region sum lines in the X work? Is it two lines? Three lines? One line?
About the R9C8 controversy: I was able to desambiguate with A LOT of backtracking after assumptions. I don't know how Mark got it that fast without being confused by his own pencil marks.
Solve was wrogn!
18:24 for me today!
Why was R8C3 not a possible 4 ? ( because it would need two 9s in the box to be 5 away, so correct but not explained
What song is the into music from??
63:36 for me, after missing some very obvious sudoku
The Description of the blue line is wrong. BOX 7 would have 4 numbers that the blue line visits and those sum at least to 10. Extra text needed like 'distinct groups on the same blue line count as different groups for the sum' .
I think the rules, while a bit awkward, do indicate 'the same total in each 3x3 box the line visits.' This means that every time the line enters the box, it will have the same total. It's not the sum of ALL the blue lines in the box that = the sum of the connected blue lines in another box. (In box 7, the line in C = R6C1 = R7C2.)
(I know this to be the case because I've seen a lot of puzzles with this rule. The puzzling time is when the blue line is only in one box. That has happened and makes no sense! At that point, I think it's just cosmetic, but certainly leads to confusion.)
The text in the video and the description say "box borders divide the line into equal sum segments", which makes it clear. The rules in the puzzle itself is the less clear version, which sometimes tries to mean the equivalent to that, and sometimes means add all the segments together. Since it is impossible for 4 different cells to add to a single cell, it is clear that the alternate version used in the video and the description is correct. I think it is hard to edit the rules in an existing puzzle without making a new link and "resetting" the solution count for the puzzle.
"box borders divide the line into segments" - so we know that there are 2 different segments in box 7.
24:40 for me
nice puzzle
00:54:51
Nice. 25:28 for me
Mark's pencil marking is simply hopeless in this one...
25:50 for me.
34.01 for me
36:41 for me and solver #1746.
Not a great solve Mark
You did an error in concluding that red had to be 7, that’s not proper logic
BTW solved it in 25 mins 23 secs with proper logic
19:46 for me. not happy. i missed one line that made me waste a lot of time.
Seems this can't be solved without bifurcation. Thumbs down
Follow the usual solve process until you get stuck, and then look at the arrow clue that spans Box 9>Box 6 - there's a break in logic that doesn't require bifurcation to spot
I solved this without any plug and chug at all.
If r5c7 is a 3, it provides an instant contradiction between r7c2 and r7c8.
00:38:43
26:41 for me