Doubt : In the below problem👇, where should we draw the true shape ? in HP or VP ?...Please clarify... Que: A pentagonal lamina of sides 25mm is having a side both on HP and VP. The corner opposite to the side on which it rests is 15mm above HP. Draw the top and front views of the lamina.
Hamara lecture aap hi hai sir Hamari college vo paisonke liye aane vaale lectures hai sir aap hai hamare asli lecture sir Saamne ho to aapki pair pakad ke danyavaad kehne ka man kar raha hai sir Hamari college ki lecture 6 mahine sunke bhi kuch nahi samjha lekin jab aap ki lectur sun raha hu na to makkhan ki tarah dimmakh me ghus Rahi hai sir ❤😊
A thin plate is of 50mm diameter Its diameter AB is inclined 45 degree to HP and other diameter CD perpendicular to AB is inclined 30 degree to VP. Draw its projevtions.
A Hexagonal lamina having edges 30 mm is placed on one of its corners on HP such that the surface makes an inclination of 45° with HP. The perpendicular bisector passing through the corner on which it rests appears to be inclined at 60° to VP. Draw the top and front views of the lamina Sir plzz... 🥹 Make the video of this prblm..... Let me know in comment after you solve this sir.... Please 🥺🙏🙏
Pentagonal plane of side 50 mm is kept on the HP on one of its sides in such a way that its surface makes an angle of 45° with HP. Draw the projection of plane when side which is in HP is inclined at 60° with VP in such a way that nearest corner point is at a distance of 20 mm from VP.
Waise koi bhi method ka use karo .....koi farak nahi padta. Aur question me kabhi bhi method ka naam nahi likha hota hai, ye pura aapke uper depend karta hai.....ki aap kis method se draw karna chahte hai. Waise general method se jyada time lagta hai......To hamaare hisaab se AIP method hi best hai.
A Hexagonal lamina having edges 30 mm is placed on one of its corners on HP such that the surface makes an inclination of 45° with HP. The perpendicular bisector passing through the corner on which it rests appears to be inclined at 60° to VP. Draw the top and front views of the lamina Sir can you please solve this question..... Plzz sir
Humne video me ye already bataaya hai ki, agar question me likha hai "side in HP", "edge in HP", "corner in HP" To hi true length XY me draw karna hai.
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koun koun is video ko 2024 me thek rahahai
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Dhanyawaad Gurudev...❤
Hi
Can u pls tell ki agar yeh ques AUXILIARY plane method se kre ... Toh kya FV ,XY line ke neeche aayega ?
Doubt : In the below problem👇, where should we draw the true shape ? in HP or VP ?...Please clarify...
Que: A pentagonal lamina of sides 25mm is having a side both on HP and VP. The
corner opposite to the side on which it rests is 15mm above HP. Draw the top
and front views of the lamina.
In HP as height is also given (think conceptually)
Good teaching
Thanks for watching
Thank you sir aapke video se bhut help mili h
Thankyou sir for your great explanation ❤❤🙏🙏
Real doubtnut for engineering 🤣❣️
Sir Aaap kabibi hamara man rahoge ❤
Thankyou sir 🙏 excellent 😎😎
Most informative 👌👌
Bahut bahut dhanyawad sir
Hi
Can u pls tell ki agar yeh ques AUXILIARY plane method se kre ... Toh kya FV ,XY line ke neeche aayega ?
Teacher ho to aisa ..😈😈😈
Sir , explained fastly
But teaching is very great
Thanks for watching
How will the front view of this hexagon be drawn??
How will it look like?
Please make the screen larger and make the presence of question till solving
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Thankyou sir...super vedios
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The day before exam 🥶⚡
Hamara lecture aap hi hai sir
Hamari college vo paisonke liye aane vaale lectures hai sir aap hai hamare asli lecture sir
Saamne ho to aapki pair pakad ke danyavaad kehne ka man kar raha hai sir
Hamari college ki lecture 6 mahine sunke bhi kuch nahi samjha lekin jab aap ki lectur sun raha hu na to makkhan ki tarah dimmakh me ghus Rahi hai sir ❤😊
.🤣
Thankyou so much sir
Thanks for watching
Harekrishna
Teaching is great
A thin plate is of 50mm diameter Its diameter AB is inclined 45 degree to HP and other diameter CD perpendicular to AB is inclined 30 degree to VP. Draw its projevtions.
Thank you sir 🔥🔥🔥
Amazing class 🙂🙂
A Hexagonal lamina having edges 30 mm is placed on one of its corners on HP such that the surface makes an inclination of 45° with HP. The perpendicular bisector passing through the corner on which it rests appears to be inclined at 60° to VP. Draw the top and front views of the lamina
Sir plzz... 🥹 Make the video of this prblm.....
Let me know in comment after you solve this sir.... Please 🥺🙏🙏
Nice class sir Ji 😊😘
Nice 👍
Sir hum 2nd TV hai woh line ke upar le sakte hai?
Beta construction nahi ayega kya sir isme length reduce ho rahi na
Pentagonal plane of side 50 mm is kept on the HP on one of its sides in such a way that its surface makes an angle of 45° with HP. Draw the projection of plane when side which is in HP is inclined at 60° with VP in such a way that nearest corner point is at a distance of 20 mm from VP.
Tq sir😍
Thanks for watching
👍👍👍
Tq so much sir tq tq tq
In 16:25 Sir, can we draw the E1D1 line anticlockwise instead by taking a point which is further, for 30 deg inclination?
Yes you can take, No problem at all.
@@TIKLESACADEMY Thank you Sir
Tita angle value batna ,super teaching sir
thankyou very much SIRJI
Thank you.......sir
Sir ji app toh kammal ho
Sir 30 degree to vp hai pr apne तो 30 degree to hp bna diya
Thanks sir
Thanks for watching.
As time passes thou shall the video find lost souls giving them hope.
Thank you sir
Thanks for watching
Thank you sir 💯👍💯
Sir u teaching very well sir
Sir, what angle you took for drawing the true shape of Hexagon??
120
@@Islamic_bayan123-w2s 105
@@memepage8153 120°
60
Kya aayenga aayenga laga rakha hai 😂
Sir aapne jo first problem me front view draw karne ki method batayi thi usse bhi same hi answer aaega na??
Yes 100%
@@TIKLESACADEMY upload some problems for homework please
Thank you very much sir
Sir your explanation super
result : surface inclination with HP=57degrees
❤❤👌👌
Jai Hind sir
sir aap projection of plane surface ke only one degree ke prblm bhje
Sir in this qstn if we use auxiliary method then FV will be below HP .....pls explain
Kon kon meri tarah exam ke 1 din pahle dekh raha he 😂
Thank you sir. :))
.
..
...
🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Sir how did u draw true shape.. I mean wat is the angle to be taken
For HEXAGON it's 120 degree.
Sir hame sikhane ke liye lecturer hi nahi hai to ham AIP method ka use kare ya general method ka use kare?
Waise koi bhi method ka use karo .....koi farak nahi padta. Aur question me kabhi bhi method ka naam nahi likha hota hai, ye pura aapke uper depend karta hai.....ki aap kis method se draw karna chahte hai. Waise general method se jyada time lagta hai......To hamaare hisaab se AIP method hi best hai.
❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
Thanks siir
Sir you are genius
🙏🏻🙏🏻
Sir ko vp me 30 degree pe hexagon banaya h use left side hi banana jaruri h kya... Right side me nahi bana sakte kya?
Bilcul chalega......bana sakte hai.
A Hexagonal lamina having edges 30 mm is placed on one of its corners on HP such that the surface makes an inclination of 45° with HP. The perpendicular bisector passing through the corner on which it rests appears to be inclined at 60° to VP. Draw the top and front views of the lamina
Sir can you please solve this question..... Plzz sir
Sir agar 30 degree wala angle auxiliary method se banaye toh will the answer be different or it will remain same?
bro kya answer hai iss question ka vaise??
Sir auxiliary draw krne ke liye e1,d1 ki jagah a1,b1 vali line ko extend kr skte he na?
No ...read question...45 mm above hp and incline 30degree to VP...and we took d'e' 45 mm above so...same line should be inclined at 30 degree :)
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Thank You sir !
Sir apne hexagon banane ke leye kitna angle leye protector mai
Gud evening sir
Sir isme kb true length xy line pr hi hota hai
Humne video me ye already bataaya hai ki, agar question me likha hai "side in HP", "edge in HP", "corner in HP" To hi true length XY me draw karna hai.
Thank u sir
Sir jo q send kiye h use solve kr digiye
Night before exam💀
❤
sir u made all the projection with first angle projection..
but how to recognize that where will be plan drow .first and 3rd angle.
plz reply🙏🙏 thnku.
❤❤