You can also remember for aqueous solutions as:- 1.If the aqueous solutions have Cl-,Br- and I- ions ,cl2,Br2, and I2 are released at anonde. 2.Any other anions (other than Cl-,Br-,i- ),O2 gas is released at anode. 3.If the solution has 1A,2A group metal ions ,H2 is released at cathode. In other cases,the metal will undergo reduction. 4. In presence of active electrodes metal oxidation (M----> M^+n) always occurs at anode. Hope this helps🙃
You can also remember for aqueous solutions as:- 1.If the aqueous solutions have Cl-,Br- and I- ions ,cl2,Br2, and I2 are released at anonde. 2.Any other anions (other than Cl-,Br-,i- ),O2 gas is released at anode. 3.If the solution has 1A,2A group metal ions ,H2 is released at cathode. In other cases,the metal will undergo reduction. 4. In presence of active electrodes metal oxidation (M----> M^+n) occurs always. Hope this helps🙃
@@praveen9354U can understand which electrode is given by seeing the question.For example if a copper electrode is taken in cu^+2 solution then it is an active electrode (electrode and solution are same here).In that case metal oxidation takes place.
Answer -O2 Finally I get it here only.... I searched many times.... Now there will be no problem to keep this all in mind which I used to forget earlier... Thank you so much ma'am🙂
I wish if i knew this before. I always used to guess the answer or learn as it is...it was so helpful thankyou mam and last answer oxygen is liberated at annod.
The answer of test yourself question is option c 'O2' ... Bcoz as we know at anode oxidation occurs and since it has positively charged it attracts negative charged particels {oh- and SO4-2} and as mam tells in lecture that oh- has higher oxidation potential than SO4-2 . thats why o2 gas will evolve at anode... and at cathode pt will be always deposite independent of any cation... all regards to komali mam and a little to mine dedication to solve that ... :)) THANKS..
Kumar Saragadam As a teacher I'm really happy to have 30000 + students with me💕. Thanks for your support.. All the best for your bright future.. Study well 👍
So , basically stable elements resist their oxidation or reduction anions like f-, and resonance stablised entities are more stable then h20 cations of 1st , 2nd and alluminium are also more stable then h20 kind of, although stability is not proper term
Thanks to Mam for delivering good lecture on electrolysis in a very simple way for easy understanding to Higher Secondary Students of colleges in Bangladesh. Hopes for delivering such type of simple but good lectures on different chapters of classes 11-12 text book chemistry in coming days in continuously. Thanks
Mam your accent of speaking is very beautiful way of explanation is miraculous thankyou mam so much this was the most confusing topic for me in electrolysis but you made me understand everything tqq 😊😊👍👍
Ma'am how we have to balance the charge I haven't understood... Can we write like this.. Anode:cl-gives cl+electron Then cl+cl gives cl2 ..please reply 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏ma'am please reply
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heartedlyy tq tq tqqq it helps more mam love u mam god bless u
i sam arinjilla
Who asked @@rijinraj5664
You can also remember for aqueous solutions as:-
1.If the aqueous solutions have Cl-,Br- and I- ions ,cl2,Br2, and I2 are released at anonde.
2.Any other anions (other than Cl-,Br-,i- ),O2 gas is released at anode.
3.If the solution has 1A,2A group metal ions ,H2 is released at cathode. In other cases,the metal will undergo reduction.
4. In presence of active electrodes metal oxidation (M----> M^+n) always occurs at anode.
Hope this helps🙃
Thanks for the help Abhishek. Appreciate it 😊😊
@@sharuk2728 you're welcome 😄
Damn useful, thanks!!!
Yes very useful. Thanks!
Thankyou ✨
Good hand writing, amazing way of explaination liked your lecture a lot mam... May god bless you mam...
You can also remember for aqueous solutions as:-
1.If the aqueous solutions have Cl-,Br- and I- ions ,cl2,Br2, and I2 are released at anonde.
2.Any other anions (other than Cl-,Br-,i- ),O2 gas is released at anode.
3.If the solution has 1A,2A group metal ions ,H2 is released at cathode. In other cases,the metal will undergo reduction.
4. In presence of active electrodes metal oxidation (M----> M^+n) occurs always.
Hope this helps🙃
@@abhishekvarmasagi8358 really spr
@@praveen9354 😄
@@abhishekvarmasagi8358 pls explain 4th one
@@praveen9354U can understand which electrode is given by seeing the question.For example if a copper electrode is taken in cu^+2 solution then it is an active electrode (electrode and solution are same here).In that case metal oxidation takes place.
The answer of the last question is O2 as oxidation potential of h2o is more than so4²-.👍👍
Thank you Ma'am 🙏
O2 obviously. Awesome presentation jee . God bless .
Ans: O2...as H2O has more oxd. potential than SO4 2- ...H2O will be oxidised
Yes
that means answer
is oxygen evolution at anode
They are asking has so correct ans is h2 😂😂😂
Yeah baku common man o2 is the answer
@@acommonman8878 mentooooo.......kuduuuu
Ur teaching method very simple and easy to catch...mam every average and below average student needs ur support mam.....extend ur platform please
Struggled with this topic many times mam.But now crystal clear.SIMPLY FELL IN LOVE WITH THE TRICK❤️❤️🔥🔥🎉
Answer -O2
Finally I get it here only....
I searched many times....
Now there will be no problem to keep this all in mind which I used to forget earlier...
Thank you so much ma'am🙂
i spend more than one day on this topic..........i never thought some like u will do magic with this stuff and make it enjoyable and effortless
I learnt it from many teachers but still unable to easily solve IIT JEE ADV questions....but now I am feeling its too simple to understand
Bhaiya kya rank bani ?
Nhi bani😂😂
Don't worry bro you are not alone 😂
Konsi rank
I am chemistry professor in Hydrabad university but i really felt your teaching marvallous keep it up..
It was very hard for me before but now it is too easy 🥰🥰 thanks ❤
I wish if i knew this before. I always used to guess the answer or learn as it is...it was so helpful thankyou mam and last answer oxygen is liberated at annod.
Answer to TEST YOURSELF QUESTION IS:- O2
You made this concept as much as simple. Well explained. Congratulations for 30K subs. Keep it up and All the best.
Kvrk S Thank you 💕
But now more 100k congrats mam
But now 300k 🔥🔥🔥
N̆̈Ŏ̈W̆̈ 310🅺︎+ 😘😊😇💐💐💐💐💐
But now 360+
Test your answer- O2 will be produced at anode ; Due to oxidation of H20. 🤗😊
The answer of test yourself question is option c 'O2' ... Bcoz as we know at anode oxidation occurs and since it has positively charged it attracts negative charged particels {oh- and SO4-2} and as mam tells in lecture that oh- has higher oxidation potential than SO4-2 . thats why o2 gas will evolve at anode... and at cathode pt will be always deposite independent of any cation... all regards to komali mam and a little to mine dedication to solve that ... :)) THANKS..
can you explain how the presence of platinum electrode makes a difference in the reaction
Komali Maam, Superb explanation and you way of treating and teaching✍️ is excellent. Thank you. Congratulations ma'am. You got 30K+ subscribers 👍👌
Kumar Saragadam As a teacher I'm really happy to have 30000 + students with me💕. Thanks for your support.. All the best for your bright future.. Study well 👍
@@KomaliMam and now 300k madam in such a short time🙏🙏🙏🎇✨🎊🎋🎉congrats madam
And now 400k+ students👀😁😁
So , basically stable elements resist their oxidation or reduction
anions like f-, and resonance stablised entities are more stable then h20
cations of 1st , 2nd and alluminium are also more stable then h20
kind of, although stability is not proper term
Trick start at 7:58...👍👍👍👍
Awesome explanation mam👌👌I always see u r videos to solve chemistry...
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Truly loved your way of teaching ma'am thank and please upload more videos so that we can learn difficult topics easily ,,😄
Nyc job mam ,I am from kashmir ,india .I love ur art of teaching
I was confused till my neet exam but today i understand concept thank you mam
Me too
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Wow .....Excellent Trick Mam ...Really helped Me .....Thanks ..
Thanks for giving more tips and tricks mam...as I am preparing for neet exam..tnx mam
Marvellous way for solve numericals. Thanks mam . Keep going on and help us as much as u can. Thanks alot
The class is more helpful . Thank you mam❤
Yeah
Mam's voice perfectly defines a shrill voice..💕
Sssssss yasssss😌
Thanks to Mam for delivering good lecture on electrolysis in a very simple way for easy understanding to Higher Secondary Students of colleges in Bangladesh. Hopes for delivering such type of simple but good lectures on different chapters of classes 11-12 text book chemistry in coming days in continuously. Thanks
Nice video mam, and helping me so much.... And your tricks awesome to crack our exams..... 👌👌👌👌👌👌👌👌👌👌👌
Wonderfully ..God give excellent knowledge mam God bless u
I was looking for the reduction potential of H3O+ ions, I got it thanks madam
Same🤔🤔
Wow this is the best video I have ever referred to ❤
Thanks for such videos ma'am God bless you
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How is your Neet preparation going on ?
Superb explanation mam 💕 thank you ❤️
Ans o2 mam awesome tricks
Really you have made it very easy
Thnq u so much ma'am
Love from Kashmir ...
Thanks mam for these very helpful tricks....
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Mam u r awesome superb plz add many more video 🙏🙏 ...u make chemistry awesome and easy may god bless u mam
Madam H+ reduction potential is more than Zn2+ so H+ should get reduce
It is O2 mam why beaucause SO4-2 has oxidation poteinal Less than OH- and OH- liberates O2
O2 is the gas evolved. You re amazing maam😊
Extradionary teaching mam .And also your voice is so sweet.
Thanks 😊 for such easy trick....
Thank you mam for covering the difference between the inert and active electrodes, thank you so much!
Gas evolved at Anode is O2 gas mam due to water has more oxidation potential.
Wonderful explanation thank you helps a lot
❣️
Ans of test que is O2 ...but mam what will be in the solution other than cathodr and anode ?
Mam i love your lectures 💞💞
O2 is the answer am I correct and Mam you are amazing I lack words to describe your efforts
Mam words me explain nahi kr sakte aapka help bas dua krte hai aap hamesa acche se rahe aur humlog ka help krte rahe.
Thanks ma'am your videos make chemistry really easy for me. With your help i am now able to understand chemistry easily.
Option C O2 gas
Thankyou ma'am 🥰🥰🥰🥰🥰❤️🥰❤️❤️🥰🥰❤️
Diluted means h2o is present so at anode o2 gas because h2o has more discharge potential than so4 and at cathode h2 gas is evolved
mam ur teaching way is awesome
answer for test yourself question is O2 gas released at anode
Maa learning qualities may be increase day by day ....after watching ur videos......the way u explain Awwwww chanceee Ella mam🤗🤗
Mam your accent of speaking is very beautiful way of explanation is miraculous thankyou mam so much this was the most confusing topic for me in electrolysis but you made me understand everything tqq 😊😊👍👍
Mam u r best chemistry teacher
Excellent mam I was really thinking that I was over but now feeling much confident 😃
You are a blessing for students Ma’am
the different coloured sketch pens u use makes the topic interesting .mam
Mam in electrolytic cell we say positive electrode and negative electrode rod...how we prepare positive and negative electrode...plz answer.
Mam last ques. Ans is O2 gas
8:21 is it applicable for all the 1,2,13 group elements
I don't understand it so I will skip it but in search I found this video and I understand it better ....
So thank you very much ....
Thank you so much ma'am,😘😘😘😘😘😘
Mam same question has been asked in neet 2020 so glad thq a lot
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Mam your tricks are best and you also best teacher
simply awesome mam... no one can explain in this way... You just nailed it mam.....
How to describe u.....
No words.... Absolutely 😇
Mam I'm from kerela... U?
H2 will evolve.. Because it goes under oxidation according to potential of oxidation
You have the magic to make any concept easier mam. glad to be your student 💯❤💫💫💗💗
Ma'am how we have to balance the charge I haven't understood...
Can we write like this..
Anode:cl-gives cl+electron
Then cl+cl gives cl2 ..please reply 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏ma'am please reply
Thank you so much mam......... please upload more videos 😊😀😁😍
Wow Mam..What a osm explanation.. Really your tricks are Op😍🥰🥰🥰🥰🥰✨✨✨✨✨🌝🌝Now, I can easily Solve my All Questions realated to this topic 🔥🔥🔥🔥💥💥 Really you are great🥰😍😍
Mam , this was previously so difficult to understand for me , but your superb trick helped me to get this clear ...thank you Mam...
Amazing trick mam . Thank u so much . U made it very easy ❤️
Mam So Thank U.. ☺☺.. I really Understood and I searched so many videos but I didn't get the matter.. Once again Thanks Mam..
Madam for (Dil.Nacl solution) and also for (Rcoona solution) what are the products released at anode and cathode???
12:53 SO4²- is having less "OXIDATION POTENTIAL" I think ma'am said it wrong by mistake.
You made it easy mam . Thanks for the wonderful vedio. God bless you 🙂
Ur way of explanation..🥺💯❤️❤️❤️
Excellent tricks ma'am
Thank you very much mam...you made this concept completely clear to me
I love you madam.becuz of you I started loving chemistry which I used to hate..
Mam
I love your teaching....
Ans is O2 . Thanks madam
Can you give notes of this topics
Very well explained👍👍