Wouldn't the distance from the pivot point to the center of the uniform meter stick be 10 cm? I am assuming the length of the stick is 80 cm and if the string is hung at 30 cm, the difference of 30 cm to the center, 40 cm, would be 10 cm. Clarification appreciated!
The length of the meter stick is 100 cm, whereas the 0.2kg mass is hung at 80cm. Paying attention to little details in the question like "meter stick" is key!
This is kinda late but because the string hangs from the 30 cm mark it isn't perfectly balanced. If the stick had no extra weight gravity would bring it down lopsided in the clockwise direction. Try and picture it in your head, it'll make sense.
How do you know when it is ok to keep it in cm and when to covert to m? because even though it cancels out, the answer is different depending on m or cm. you either multiply by 20 or 0.2, which changes the answer drastically
You always keep it in meters because in physics we use the si unit for meter when it comes to length even if it’s given as cm you need to convert to meter to make it make sense.
I know this is too late, but in case someone has the same question - g would be on every component of this equation, and therefore would cancel out. He anticipated and skipped that step.
@@xitroxide so was he suppose to use g? I also don't understand why he cancel g out if that's how you find f. or was it because we are only looking for m?
this is incredibly helpful.
Wouldn't the distance from the pivot point to the center of the uniform meter stick be 10 cm? I am assuming the length of the stick is 80 cm and if the string is hung at 30 cm, the difference of 30 cm to the center, 40 cm, would be 10 cm. Clarification appreciated!
The length of the meter stick is 100 cm, whereas the 0.2kg mass is hung at 80cm. Paying attention to little details in the question like "meter stick" is key!
@@rachelspanier Thanks for your clarification! I was curious as well and didn't think about that
@@rachelspanier wow thank you for this!!!
Hi! How do we know that the stick wants to produce a CW torque?
This is kinda late but because the string hangs from the 30 cm mark it isn't perfectly balanced. If the stick had no extra weight gravity would bring it down lopsided in the clockwise direction. Try and picture it in your head, it'll make sense.
How do you know when it is ok to keep it in cm and when to covert to m? because even though it cancels out, the answer is different depending on m or cm. you either multiply by 20 or 0.2, which changes the answer drastically
You always keep it in meters because in physics we use the si unit for meter when it comes to length even if it’s given as cm you need to convert to meter to make it make sense.
How come you didn't add the 10m/s^2 for g?
I know this is too late, but in case someone has the same question - g would be on every component of this equation, and therefore would cancel out. He anticipated and skipped that step.
@@xitroxide so was he suppose to use g? I also don't understand why he cancel g out if that's how you find f. or was it because we are only looking for m?