Aptitude Preparation for Campus Placements #9 | Probability | Quantitative Aptitude

[@amansayer4943]

15c2 * 10c1 / 25c3

[@user-lv3vn3si4y]

15c2x10c1/25c3=21/46 that is the answer

[@prince2k02]

and after this lecture, I remember lots of memories from my school life. thank you, mam! your teaching skill is exactly similar to my math's sir.

[@swagatabanerjee1904]

13:45 ans:
21/46

[@aabhaspise3650]

Correct

[@ravindrakarande59]

There should be a case when both A and B speak False. So you should calculate P(contradiction) = 1 - P(both speak Truth)

[@vishakhajadhav7064]

Thank you mam for crisp and to the point content❤

[@thedevlife1611]

Ans of last question will be - 21/46

[@GajendraSingh-pw1nz]

15c2*10c1/25c3 = 21/46

[@juniorartist2805]

thank you for this series

[@ravindrakumaryadav566]

Very nice playlist mam
❤❤❤❤❤

[@NitianRohitKumar]

Mam, may you provide the pdf of class notes?

[@aurangzebhassan24]

21/46 Ans

[@tarunpallela4727]

1/20 ?

[@FyjhcjChh-vq7zk]

Can you pls add english subtitles

[@parthib.1555]

ans : 21 / 46

[@Chandra__01]

21/46 is last question answer

[@vedikasangle7607]

21/46 is ans

[@rahuljoshi598]

21/46

[@review_by_haresh]

Last wala 21/46

[@deepakmaheshwari8383]

45.65℅

[@RaviKumar-dy5mt]

15c2×10c1/25c3

[@malavathshekar8280]

21/46

[@jitulsaikia508]

21/46

[@Omgupta520]

21/46

[@iys9319]

21/46