All photoelectric effect graphs: Effect of intensity/frequency | Dual nature of light | Khan Academy

Let's explore various graphs of photoelectric experiment, and see how changing intensity and frequency changes the graphs.
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Created by Mahesh Shenoy

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the slope of the last graph will give us Planck's constant.

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[@kripasajo]

at 8:05 wont the stopping potential be in the negative y axis since it should be negative ?

[@lhamtsering9800]

8:06 won't the graph will be in the 4th quadrant given the stopping potential is negative?

[@anythinganymore3596]

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Can We say voltage is proportiomal to kinetic energy rather tham saying they are both equal?

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[@vipulsingh1863]

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[@AmeyKemkar]

6:06 how did we predict the intersection point of the reference graph and the graph that we drew?

[@orrazeen2091]

❤️

[@rishavjain5087]

@ 5:02 since the new stopping potential is lesser....it should have been drawn after the previous Stopping Potential as -3 > -5
Just a tiny error

[@anythinganymore3596]

Nope, here it implies negative max and min

[@anythinganymore3596]

7:47 I have a doubt, if we change the intensity, the no of photons increases and eventually no of photoelectrons emiited also increases. So by logic, it requires more -ve potential to stop the electron from reaching the collector plate when we increase the intensity of radiation. Thus the graph should increase ...
Pls reply where am i wrong

[@abh1n4vv]

A -ve stopping potential creates an electric field which repels the incoming electrons. So that shouldn’t depend on the number of electrons

[@astikpatil5773]

How to go on previous video of this series or topic ?

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Go to playlist

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[@h7opolo]

your graph is janky. the y axis should stem from the origin, aka coordinates (0,0).

[@h7opolo]

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Isn't it fun to do it logically. 😀💗. 6:08 😶🥲