Amazingly explained Sir. I wish you were our lecturer during my graduation. So clearly you have walked us step by step leaving us with utmost clarity. I would request you to explain in the same way a little more complex examples and also on Slopes and Deflection of beams. Thanks in advance Sir.
This video is excellent. But can I take clockwise moment negative and anticlockwise moment positive? Then the graph doesn't remain same. So, what's the solution?
But we take bending moment using the right side forces from the point which we take moment, then the same value in negative sign. But it should be same from any side.how to solve this?
For calculation of reactions you converted udl into point load, but why you didn't repeat the same thing for calculation of S.F and B.M , can we first convert UDL into Point load for Calculation of SF and BM? Please reply
You can convert the u.d.l. to point load only for the calculations of moments & hence that approach is used for the calculations of reactions and B.M. For the calculation of S.F. we require to calculate S.F. at the left or right of the point and hence u.d.l. cannot be converted to point load for S.F. calculations. Hope it will clear the doubt. Thanks & Happy new year from CHINMAY ACADEMY.
Hi sir , plz why you take it moment & point load at the same point ?? It is not suppose to be moment only ?? How i can understand the a point load is must as well. Plz am waiting ?? Big Thaks.
If a beam carries an eccentric load then its effect at that point is observed by adding both direct load as well as bending moment. Thus we can say that the free body diagram consists of the both direct load as well as bending moment .
Thanks a lot !!!! The video is recorded on Samsung Galaxy Tab (without voice) and in OneNote and then that video is inserted in the PowerPoint presentation and explained..... Hope its clear now.
Then why some crazy ppl make it hard when they take shear left and right ?? They go further and draw one dashed lines and ask to look left and right and see convensions fuck them ..time consuming .. you make it easy thanks
Amazingly explained Sir. I wish you were our lecturer during my graduation. So clearly you have walked us step by step leaving us with utmost clarity. I would request you to explain in the same way a little more complex examples and also on Slopes and Deflection of beams. Thanks in advance Sir.
Thanks for your complements. Will surely try to upload the solution of complex problems in future.
welcome eng students, a day before exm 😅
Really Bhai .... Tomorrow is my som exam 😁
Wish you all the best! Do visit often !!
Why have you taken 10kN point load as well? Isnt it producing a moment only?
It is eccentric load which is producing both ... the point load as well as the moment. Thanks.
This is the exact video what I want👌
BMD and SFD (100%)
ruclips.net/video/BT0LLe4_M3A/видео.html
Thx man this is exactly what i need now
Welcome ! You can find more videos on shear force & bending moment diagram here: ruclips.net/p/PLW4Rtyezg8ykVPRmuZ-8d_HixvQTxNJFt
perfectly explained sir ..thankyou so much ..plz make videos on more such topics
Thanks for the complements.. Will surely try to make more videos on the topic..
Sir solve numerical using moment given at midspan and other positions with point loads also
Will surely try. Thanks.
If we solving from right hand side S.F. at A will be zero . So why we should neglect it
This video is excellent. But can I take clockwise moment negative and anticlockwise moment positive? Then the graph doesn't remain same. So, what's the solution?
The solution is that .... start drawing the diagram from Right Hand Support .
Yes you can take it as u want but keep your sign convention same till end of paper
Sir I have one query how to know it is a concave or convex parabolic curve in bmd
Point of contraflexure kyu nhi calculate kiye sir ap iss question mein
But we take bending moment using the right side forces from the point which we take moment, then the same value in negative sign.
But it should be same from any side.how to solve this?
For calculation of reactions you converted udl into point load, but why you didn't repeat the same thing for calculation of S.F and B.M ,
can we first convert UDL into Point load for Calculation of SF and BM?
Please reply
You can convert the u.d.l. to point load only for the calculations of moments & hence that approach is used for the calculations of reactions and B.M. For the calculation of S.F. we require to calculate S.F. at the left or right of the point and hence u.d.l. cannot be converted to point load for S.F. calculations. Hope it will clear the doubt. Thanks & Happy new year from CHINMAY ACADEMY.
@@CHINMAY_ACADEMY thnx
Great. It is very useful in gtu exam time
Most welcome!!!
In summation of moment =0
Why the length not multipled to bending moment at point B
Pls explain.
Because its directly a moment that is given !!
Hi sir , plz why you take it moment & point load at the same point ?? It is not suppose to be moment only ?? How i can understand the a point load is must as well. Plz am waiting ??
Big Thaks.
Its actually the effect of eccentric load that is converted into a point load+ moment at the given point. Hope it will be clear. Thanks...
@@CHINMAY_ACADEMY Sorry i didnt get you.
If a beam carries an eccentric load then its effect at that point is observed by adding both direct load as well as bending moment. Thus we can say that the free body diagram consists of the both direct load as well as bending moment .
Sir why didn't you take load and distance ie.(10*2) at 9:31 plz tell🙏
exactlyyy
Nice sr but hve a little confusion in contonous beam having four support ?? How to find reaction at support. Sr can u help me out here
Please send the image of your question so that I can answer easily & precisely... Thanks !!!!
amazing explanation......& you really selected good question.
BMD and SFD (100%)
ruclips.net/video/BT0LLe4_M3A/видео.html
great explanation , could u tell me please the device name u used to write the solutions ^^!?
it will be great for my lectures notes and organisation
Used Samsung Galaxy Tab with S pen !!!! Thanks !!!
That was really helpful. Thank you.
Most welcome !!!
in moments about A doesn't the 4th moment act at a distance of 3 meters from A
Well explained sir.
Please what app do you use in making your videos.
It would really be of help to me
BMD and SFD (100%)
ruclips.net/video/BT0LLe4_M3A/видео.html
What if Rb is replaced by a Roller support?
Kindly give an answer...
BMD and SFD (100%)
ruclips.net/video/BT0LLe4_M3A/видео.html
nice explanation Sir. How do you inserted OneNote in PowerPoint ?
Thanks a lot !!!! The video is recorded on Samsung Galaxy Tab (without voice) and in OneNote and then that video is inserted in the PowerPoint presentation and explained..... Hope its clear now.
Thank you for your kind information
Then why some crazy ppl make it hard when they take shear left and right ?? They go further and draw one dashed lines and ask to look left and right and see convensions fuck them ..time consuming .. you make it easy thanks
Most welcome !!
This is very usefull sir. Thank you
Hello sir can I use this kind of clock wise and anticlockwise moment instead of sagging hogging??in exam?
Yes .. Surely !!!
that's more of the same thing ... observe carefully
I have exam tomorrow😁
The udl is acting exactly at the point where Rd acts
C to D and D to E slope should equal in the graph
BMD and SFD (100%)
ruclips.net/video/BT0LLe4_M3A/видео.html
why 10kn is not taken in to find RA????
Why the need for adverts every few minutes?!
BMD and SFD (100%)
ruclips.net/video/BT0LLe4_M3A/видео.html
thank you 😊 upload more😊
Most welcome !!!
I thought the 10kn.m is you time yourself at first was not at there I mean the 10 moment
ruclips.net/video/eKFlA5qb-Cg/видео.html
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Bm at point b is incorrect. It will be 30
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Thanks! Helped a lot.
Most welcome !!!
Ad three times in the same video irritating
BTW nice explaination
How did we get 17 in SF about d
Great concept sir g
The signal of moments around A it is opposite of what u did
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Tq sir this is helpful..
Most welcome !!!
Fantastic video sir ji
Thank you so much !!!!
Create some more example
Surely !! Thanks...
Thank you Sir!
Mst bhai and thanks
Thanks !!!
Thanxx very helpful 😄
Most welcome !!!!
Thanks Sir
Welcome ! You can find more videos on shear force & bending moment diagram here: ruclips.net/p/PLW4Rtyezg8ykVPRmuZ-8d_HixvQTxNJFt
How to calculate BM@B
BMD and SFD (100%)
ruclips.net/video/BT0LLe4_M3A/видео.html
Thanks a lot Sir ...
Most welcome !!!
Means concept of sfd bmd
ruclips.net/video/eKFlA5qb-Cg/видео.html
Please watch this video and subscribe
Thank you sir
Most welcome !!!
Typical example on SFD & BMD :ruclips.net/video/NyIHgrWpjuM/видео.html
Nice sir
Thank you !!!
thanks u so...Much...Sir..
Most welcome !!!!
Awsome
Thank you...
Anyone can learn with it
BMD and SFD (100%)
ruclips.net/video/BT0LLe4_M3A/видео.html
Nice
Thank you !!!!
Thanx...
Most welcome !!!!
tq sir
Most welcome !!!!
good problem
Thank you so much !!!
SFa = 5kn
Sir plz tell from starting..I don't know plz plz plz
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🤗😊😊
More interesting videos for you : ruclips.net/p/PLW4Rtyezg8ykVPRmuZ-8d_HixvQTxNJFt
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MATLAB & SimuLink course : bit.ly/3OEI8Yw
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Thank you so much sir..
Most welcome