Uniform Continuity (Example 1): The Basics

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  • Опубликовано: 6 сен 2024
  • Uniform Continuity Basic Example
    In this video, I work out a basic example of how to show that a function is uniformly continuous
    What is Uniform Continuity? • What is Uniform Contin...
    Example 1 • Uniform Continuity (Ex...
    Example 2 • Uniform Continuity (Ex...
    Example 3 • Uniform Continuity (Ex...
    Example 4 • Uniform Continuity (Ex...
    Continuity Playlist: • Limits and Continuity
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Комментарии • 46

  • @dylank6191
    @dylank6191 3 года назад +8

    The best thing about uniform continuity is that it's for free for every continuous function defined on a compact space. So, as a little fun fact, f(x) = x^2 is uniformly continuous on every intervall [a,b] (and every other bounded and closed set for that matter)

    • @user-kl8dh7nt2e
      @user-kl8dh7nt2e 3 года назад +1

      So is every polynomial, I think.

    • @dylank6191
      @dylank6191 3 года назад +1

      @@user-kl8dh7nt2e Yep, since every polynomial is continuous.

  • @arturcostasteiner9735
    @arturcostasteiner9735 3 года назад +5

    I think it's interesting to notice that every Lipschitz function is uniformly continuous but the converse is not true.

    • @tofu8676
      @tofu8676 3 года назад

      yes i usually associate LC with UC so it would be very interesting to see such a function!

  • @arturcostasteiner9735
    @arturcostasteiner9735 3 года назад +10

    On the complex domain, there's an amazing conclusion, which doesn't seem to be very known:
    If f is entire and uniformly continuous on C, then f is an affine mapping: for every z, f(z) = az + b, a and b complex constants.

  • @hypershadic5093
    @hypershadic5093 3 года назад +2

    Thank you so much for reviewing this subject of analysis, I was really struggling with these definitions!

  • @wtt274
    @wtt274 Год назад

    Sir has given a perfect explanation on uniform continuity in his great video .Thank you sir !

  • @ranahalide9422
    @ranahalide9422 Год назад

    Thanks sir from india ❤️

  • @asamenechbayissa553
    @asamenechbayissa553 3 года назад +1

    I am getting interested in analysis from those videos

  • @tomoki-v6o
    @tomoki-v6o 3 года назад

    for my engineering problems i use the perpondicular to the bisector angle between left and right tangents and i trait it as a derivative

  • @tomasasnes4081
    @tomasasnes4081 2 года назад

    I actually understood this!!! Awsome video

  • @bijnas0074
    @bijnas0074 3 года назад

    Love from Nepal sir .🇳🇵

  • @Scrollwithvicky333
    @Scrollwithvicky333 Год назад

    Love from 🇮🇳 india❤

  • @andrewmichel2525
    @andrewmichel2525 3 года назад

    I will take real analysis in the near future and am a bit worried about it but these videos make me feel like the class wont completely blindside me

  • @ABC-jq7ve
    @ABC-jq7ve Год назад

    I love your videos!!

  • @maximelamoureux9836
    @maximelamoureux9836 3 года назад

    Your video are really helpfull. Can you make a video on several example to prove that a function isn't UC ?

    • @drpeyam
      @drpeyam  3 года назад +1

      Check out the playlist 😉

  • @DynamicMateTV
    @DynamicMateTV 3 года назад

    Could you please make video explaining uniform continuity visually/diagrmatically?

    • @drpeyam
      @drpeyam  3 года назад

      Already done, check the description

  • @user-jc9kj7wt6j
    @user-jc9kj7wt6j 2 года назад

    Awesome!

  • @him21016
    @him21016 3 года назад

    You say you’ll cover in an upcoming video how functions on compact sets are uniformly continuous but I first learnt about both those terms from a video you made ages ago! We already have this from you. Just a thought, but the definition of finite covers and compact sets was hard to understand - why is (1,6] not compact and [1,6] compact?

    • @drpeyam
      @drpeyam  3 года назад +1

      For (1,6] the family (1+1/n,7) is an open cover that has no finite subcover

    • @him21016
      @him21016 3 года назад

      @@drpeyam Is the difference sir that the limit as n goes to infinity of 1+1/n can touch all the points on the open interval (1, but it could never be exactly one, so you can't call it a cover for [1 closed?

  • @alfredocuomo4284
    @alfredocuomo4284 3 года назад

    Great....

  • @theunknownscientist3249
    @theunknownscientist3249 3 года назад

    Every continuous function on a compact interval is uniformly continous on that interval?! That seems soooo awesome, I can't believe it. Hmm, maybe I'll try a proof? Kinda hard tho.

    • @drpeyam
      @drpeyam  3 года назад

      There’s a proof in my playlist :)

    • @Apollorion
      @Apollorion 3 года назад

      .. say h(x, epsilon) is the value of delta for which |x-y|

    • @drpeyam
      @drpeyam  3 года назад

      I thought it would be like that too, but it’s a bit more complicated than that, unfortunately

  • @ethancheung1676
    @ethancheung1676 3 года назад

    i always wonder why we dont use the scapework as the proof. because usually in these kind of epsilon-delta proof, everything is bidirectional.
    if it is purely about the format of the proof (prefer top to bottom), i think we can do the scapework from bottom to top, voila!

    • @drpeyam
      @drpeyam  3 года назад +1

      It may look like it’s bidirectional, but sometimes it isn’t, as in Example 3

  • @yoav613
    @yoav613 3 года назад

    So x^2 is unif cont in any finite interval unless delta=e/inf counts😆

    • @drpeyam
      @drpeyam  3 года назад

      Yep :)

    • @drpeyam
      @drpeyam  3 года назад

      But interestingly it is not uniformly continuous on R

    • @yoav613
      @yoav613 3 года назад

      @@drpeyam yes i agree. From your example it is easy to see why this is not uc in R because we can not choose delta= e/inf but it is intresting that we can always expand our interval more and more but still x^2 is not uc in R

  • @pierreabbat6157
    @pierreabbat6157 3 года назад

    How about f(x)=cube root of x on all R?

    • @drpeyam
      @drpeyam  3 года назад

      I think it is, since the derivative is bounded. Check out the derivative video on the playlist

    • @pierreabbat6157
      @pierreabbat6157 3 года назад

      @@drpeyam No it isn't; the derivative goes to ∞ at 0. But it's still uniformly continuous.

    • @drpeyam
      @drpeyam  3 года назад +1

      It’s uniformly continuous on [-2,2] since it’s compact, and also UC on [-oo,-1]u[1,oo) since the derivative is bounded there, and then you just patch things up

  • @andikaajisaputra8093
    @andikaajisaputra8093 3 года назад

    Still support u

  • @cricketshorts3402
    @cricketshorts3402 3 года назад

    2nd

  • @loucifabdessalam1522
    @loucifabdessalam1522 3 года назад

    فوليس

  • @stevenmellemans7215
    @stevenmellemans7215 3 года назад +1

    I don’t find this very clear, if my daughter or son would give this as an answer, they would loose a lot of marks on that question. Not by me but but their teacher :-) They should use stricter notation. For instance I didn’t see any .

  • @colleen9493
    @colleen9493 3 года назад +1

    Use the Chen Lu!
    Just kidding I have no idea what this is