For the ones curious: omega^2 . Re . cos^2(theta) Is: 0,0337 m/s^2 for Theta = 0° And 0,0238 m/s^2 for Thera = 45° g = 9,8066 m/s^2 is the average value!
i am sorry to ask here but in the newton shell theorm vedio i wasnt able to solve the integral and no machine i know was able either can the channel owner give me any insight about it
Use a u substitution of r - Rcos(theta). Don't forget to update boundaries. This will recast the integral in a more common form: udu/(R^2 - r^2 + 2ru) ^(3/2) If you want to suffer, now do the integral manually with integration by parts, or again reference a table/integral calculator. If you have further questions, let me know, but I'm guessing this will be enough for you.
For the ones curious:
omega^2 . Re . cos^2(theta)
Is:
0,0337 m/s^2 for Theta = 0°
And 0,0238 m/s^2 for Thera = 45°
g = 9,8066 m/s^2 is the average value!
Did you have the value of g at the poles? How did you get it?
i am sorry to ask here but in the newton shell theorm vedio i wasnt able to solve the integral and no machine i know was able either
can the channel owner give me any insight about it
Use a u substitution of r - Rcos(theta). Don't forget to update boundaries. This will recast the integral in a more common form: udu/(R^2 - r^2 + 2ru) ^(3/2) If you want to suffer, now do the integral manually with integration by parts, or again reference a table/integral calculator. If you have further questions, let me know, but I'm guessing this will be enough for you.