Im 13 and interested in making model rockets and need these equations to be able to know how high to deploy the parachute. You are the only person i have found to explain mate this well.
Mark, Absolutely. The exact rocket equation is much more complicated. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
Excellent point. You are correct that at least initially the fthrust must be greater than fdrag + mg in order to have a positive acceleration. Once it gets up to high speed and fdrag increases to the point where they are equal, it moves at constant (presumably high) speed. Cheers, Dr. A
Wonderful lecturer that makes physics fun and understandable !!!
Im 13 and interested in making model rockets and need these equations to be able to know how high to deploy the parachute. You are the only person i have found to explain mate this well.
Nice lecture ))) Really like it )
Bohdan,
Thank you.
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
Would you have to consider the change in "gravity" (or mass) as the rocket burns it's fuel?
Mark,
Absolutely. The exact rocket equation is much more complicated.
Thanks for the comment, and keep up with the physics!
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
if the fthrust is equal to fdrag and mg then why would there be a constant speed? wouldn't it just not move?
Excellent point. You are correct that at least initially the fthrust must be greater than fdrag + mg in order to have a positive acceleration. Once it gets up to high speed and fdrag increases to the point where they are equal, it moves at constant (presumably high) speed.
Cheers,
Dr. A
sir isn't it like , the upward thrust is a function of time ?! isn't its magnitude changing with time .?!
thank you
Why is thrust up and not down
i guess, what he calls Fthrust is the reaction to thrust force which has the same magnitude with Fthrust