Regeneration in Rankine cycle
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- Опубликовано: 13 сен 2024
- Regeneration in Rankine cycle
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By the condenser of rankine cycle, heat is lot to the surrpunding. Regeneration is the concept by which the heat lost by condenser to the surrounding is reduced and convert the saved heat into useful work. By this leture you can clearly understand regeneration principle in Rankine cycle with how to measure the steam bled and caefficiency by the help of regeneration.
Dr. Amit Mandal
Great.. The best explanation ever on this topic. Finally after 3 years understood regeneration.
Very very thankful
Best explain
Simply Superb! Thank you Mr. amit, it was very helpful!
tq so much sir very good explanation
Excellent explanation Sir, first time getting someone to explain the ranking cycle like you
superb explanation in a very lucid manner. concept became crystal clear now. thank you.
your way of explanation is superb!! plz upload more contents of thermal power plants.
Super se bhi uper
Excellent explanation, I will share this video with classmates.
very nice explanation by Amit Mandal.....Thanks a lot...!!
For the first time in my life, I understand
better than other videos. keep it up bro
awesome lecture.........thank you very much
Awsm video sir u are really Awsm and you explain everything in a brilliant way
Wonderful videos made by u sir.. really impressed
Superb sir...thank u very much excellent teaching sir it helped me alot to understand the concept👌👌
Very nice explained sir. Thanks
Awesome explaination sir
Awesome explanation sir....thanks a lot..
very helpful video
thanking from IIEST Shibpur
Well done sir well explained
Damn awesome vids, hope to see more of Thermodynamics concepts covered in your vids. #GoodGoing #KeepGoing
best............thanks...
tq sir for a wonderful teaching
really u r amazing sir,thanks fr info.....i got cleared many doubts by ur lecture ,plzz up mre videos of thermal.
Amazing video...
nicely explained....Thankyou.
Thank you Amit
It's zing zing amazing
Superb sir
nice explanation sir..
Hats🎩 off you 🙏🙏
Sir.. you made the topic complicated to understand..
thax sir
m(h2-h6)=(1-m)(h6-h5).......bcz as u said m mass of (h2-h6) will be shared to (1-m) mass at point 6
Its correct , The heat given by m mass between points 2 and 6 is absorbed by mass (1-m) between points 6 and 5 .
thumbs up
Wow .....
👏👌👌
But due to bleed off in turbine would we get lesss work output from turbine?
regeneration results in less work with high efficiency....
Give me one explanation, in the bleeding cycle how come the expansion process is a straight line (isentropic)
In T-S diagram,how entropy is decrease in pump (3 to 4)
+PRASANTA PAL it is interesting to know that the pump work cannot be isentropic even ideally. It is because , in case temperature of liquid water increases then it is essentially with increment of entropy.Only for the case of gases it can be possible that temperature increment happening with unaltered entropy i.e. reversible adiabatic compression.however in many literature sources it is written that ideally pump work is isentropic. In my lecture the pump shown in TS diagram is indicative. My main focus is to give an idea to learn regeneration...
@@Dr.AmitMandal Watch out my friend, ideal pumps are isentropic by definition while in real application some work is lost since some irreversibility arieses, work lost is then dissipated into the fluid which produces some temperature increase
@@wiskifrac then the end of entropy in the pump must be with higher entropy
@@Dr.AmitMandal In fact entropy increases, the curve 3-4 in your draw should be slightly inclined towards right not left
Lucid explanation.
Sir we bleed that steam from turbine it reduces the turbine work or not.
Yes
@@Dr.AmitMandal sir
Ultimately we are reducing the turbine work and that reduced work (because of bleeding) increase the heat of feed water.
I mean in order to increase the efficiency the heat supplied is reduced but here we are decreasing the work also . Then how efficiency is increased due to regeneration?
Understand it with this analogy, suppose a motor produces 10kw shaft power by consuming 12kw electrical energy, it's efficiency would be 10/12 = 83% . Now some modification is done over the motor and it produces 8kw shaft power by consuming 9kw of electrical power , it's efficiency will be 88%.
233℃ temp er water means...It's at vapour condition.....How can handle by pump...?
Its liquid, watch my lecture on TS diagram of water....
why total steam is not condensed at 80 bar..?
in mass balance equation! in multiple feed water heater! energy balance equation for finding mi would be!
m1(h2-h9)=(1-m1)(h8-h7) where value of h8 would be taken approxiamate to h9=hf at pressure at pt2!
second i would like to ask if q1 work load is decreased then we are also facing a decrease in wt because of bleeding mi and m2 mass flow rates and also an increase in wp work input to turbine ! does this difference (wt-wp) would compansate in equal proportion as a decrease of q1(HEAT INPUT SAVING)?
+A Gafar its correct i.e m1(h2-h9)= (1-m1)(h9-h8),
Actually the latent heat at low pressure is very big amount than the specific heat of water.
hmmmm! ok dear
damn
the equation you have given , fr finding mass flow rate of one time regeneration is wrong.......but explanation is superb, many of my doubts were cleared
I have checked , can you explain in which regards its wrong ?
but you have written there 1(h2-h6)=(1-m)(h6-h5)
Ok Will rectify..
video intro
is too much horrible
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