Electrochemistry Important Numericals | 2ndPUC Chemistry Exam 2024

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2ndPUC Chemistry Exam 2024: Important Numericals
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2ndpuc Chemistry Exam 2024
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Amines - OneShot
• Amines in One Shot | 2...
Electrochemistry - OneShot
• Electrochemistry in On...
Aldehydes Ketones and Carboxylic acids L01
• Aldehydes Ketones and ...
Aldehydes Ketones and Carboxylic acids L02
• Aldehydes Ketones and ...
Aldehydes Ketones and Carboxylic acids L03
• Aldehydes Ketones and ...
Alcohols Phenols and Ether L01
• Alcohols Phenols and E...
Alcohols Phenols and Ethers L02
• Alcohols Phenols and E...
Alcohols Phenols and Ethers L03
• Alcohols Phenols and E...
Haloalkanes and Haloarenes L01
• Haloalkanes and Haloar...
Haloalkanes and Haloarenes L02
• Haloalkanes and Haloar...
Haloalkanes and Haloarenes L03
• Haloalkanes and Haloar...
Haloalkanes and Haloarenes | Important and Fixed Questions
• 2nd PUC Chemistry Exam...
How to Score 45+ ? KCET 2024 Chemistry
• How to Score 45+ ? KCE...
Section wise Important Questions | 2nd PUC Chemistry Exam 2024 | Section Wise Analysis | Target 95+
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#chemistry2024numericals#simplifieminds_chemistry

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True❤

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From Mangalore❤, like 👇

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Which college

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Namma kudla

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Todays attendance 👇

[@sharan4276]

Antilog trick
You think that you got the value of antilog.i.e 5.0084 ..
1. First take out your calculator then type there what ever u got the value like 5.0084
2. Then divide with (3558 ) (only use this number) and u will get the value i.e 0.00140 then add with the number of (1)
Then u should do upto 13 times (multiplication ×= ×= ×= ×= ×= ×= ×= ×= ×= ×= ×= ×= ×= ×= upto 13 times...then u will get the value of antilog 😊..

[@Tejaspushpa]

Wow😂

[@SLDB7]

Hi Mam
Please upload chapterwise important questions in the app (pyq's)
Electrochemistry and aldehydes ,ketones and carboxylic acid

[@ashithsujay785]

yes bro yu are right that will help us the most even i am commenting on every vids but still they are not uploading PYQS PDF in the app

[@ashwiniholagundi7067]

🎉👌🏻💯

[@sankalpgaonkar7274]

39:59 Ma'am unit for molar conductivity is Scm²mol^-1

[@user-gl3cb4rv2z]

Sm2mol-1

[@vedanttonennavar5762]

Tq so much mam..
. Only for before one day of exam partners...🤞👇 And scoring like topper... But not as topper.....

[@RakshitaPalankar]

26:05 mam ∆G° value negative baribarda
In question the formula has negative is that just indicate that it has lost electron or we should also Indicate the sign in last value
But u haven't 26:05
Love from GADAG

[@RakshitaPalankar]

Mam plz reply to this comment it will cleared ❤

[@Captain_797]

Same doubt
-∆G° value means it's a spontaneous reaction as well right

[@volter_flash]

I think so it is not required to indicate in negative terms
26:42 even in the solution she didn't use a negative sign
Therefore there is no necessity

[@prakashkalaburgi1741]

GADAG🫶🏻🫶🏻

[@Mountain_god_]

We should take negative sign

[@jabeentaj9057]

Mam in answer We should put minus while calculating Gibbs energy

[@Yashusk123]

Mam Tq mam❤ after boards exam kcet gu videos madi mam plzz 🙏
Who and all agree with this like the msg

[@SanjeevBhajantri-iy9qp]

Who love numerical❤

[@monks_rampage]

Not me

[@user-se9zt1lc7k]

It's me ❤

[@ashiqashif8593]

Hate numericals

[@user-xx3ql5lq2q]

❤

[@etechknowledge3904]

Me

[@rekhareddy1361]

Thank you Ma'am... Really understand the numericals ... Would be thankful if we get log table reading 😊🙏🏽

[@athishshekarbc3501]

39:59 mam si unit is s m^2/ mol

[@user-vd1ln5vn2x]

Thank you for teaching mam
Super 🥰❤❤❤

[@user-iw1xr4qj7i]

Thank you mam❤

[@likith.h768]

This videos is really help for us mam thank you

[@anushasharma6611]

Understood well ma'am! Thank you ♥️🙏

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Thank you mam your teaching is beautiful

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Thank you mam thumba easy agi helkodtira❤❤❤❤

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Mam super explanation ❤❤

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Yes mam.. all problems understood 🥰❤️..TQ.

[@queenofmy7kings2030]

Thank you mam ...❤️ Lots of gratitude and love ❤️

[@anjalivaidya2012]

Molar conductivity
Scm²/mol

[@user-pj5en6jz3y]

Thank you so much ma'am ❤ i understood

[@Kavi_tha.23]

-405245.4J
-405.245kJ

[@akshaybhat6067]

Kj/mol

[@user-ok3zp7ws4f]

What's the value of n

[@user-bb2vx5ik2b]

Thank you so much mam💓

[@tiny_heart_nandu]

Mam please solve this question.
Electrolysis of aqueous sodium chloride solution was carried out by passing 5A current for 3 hours. Calculate the volume of hydrogen liberated at STP, at the cathode.[1F=96500C /mol, molar volume of hydrogen at STP=22400Cm³]

[@user-ne4kf8nq3p]

Thank you ma'am❤

[@AdnanAdnan-hu3sj]

Before i do only solution and ck now i am perfect in Electrochemistry problems, thank you so much mam

[@vaishnavivgoshal4652]

can anyone tell me why mam missed negative sign in gibbs energy problems?

[@anushashetty4492]

Sir we are missing your lectures video and motivation video. Now happy to see usha mam lecture video❤

[@kushalgodwa.r3262]

Mam TQ so much for your teaching it was very helpful for me love you so much ma'am 💞💞💞💞♥️♥️♥️♥️❤️❤️

[@disharaikar]

Understood very well mam

[@danishsummusummu1017]

Mam u definitely teach good but sir teaching hits our minds at another level

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Mam biomolecules maadalva ? RP sir log bagge video Maadi sir please

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Thank uh so much mam 🥹🫶

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It was good mam thank you so much mam💙💙💙

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Tq mam for ur support

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Thank you so much mam 💕❤❤❤

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Tq soo much ma'am ❤❤

[@madeshm65]

THANK YOU MA'AM

[@Ritu_001]

Who are waiting for next chapter numericals 👇

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Thank you so much mam😊

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Thank you for ur videos mam

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Thank youu soo much mam ❤❤❤

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Thank you so much mam😍😍😘

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It was good 👍

[@ihsalichu6786]

Mam do chemical kinetics problem of activation energy . That we want to find rate constant instead of activation energy . Log k2 / k1 . K1 is given and we want to find k2 . Mam please

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Thank you soo soo much mam ❤❤❤❤❤❤

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Thank u so much mam❤❤❤❤❤❤❤❤❤❤❤❤

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Nice class mam ❤

[@yashikababu4207]

THANK YOU SO MUCH FOR YOUR EFFORTS MA'AM REALLY UNDERSTOOD VERY WELL❤️❤️❤️❤️
Home work question answer is 405.2kJ

[@user-ln1hb4tc8i]

Tqsm mam😊
we ❤Numericals

[@divya1497]

Mam please... Video on finding log and Antilog...!!

[@SHIYO272]

Mostly ma'am at 39:44 the unit is Scm^2mol^-1
Edit after watching video: ಇದು ಯಾವ angle ನಿಂದ HOTS question??? Easiest chapter ಇದು

[@jokerking3232]

Yeah bro ur right

[@vaniproperties]

Homework question answer is -405kJ❤️

[@MrBts1807]

Home work question answer -406.24kj

[@user-et4gb6lg8e]

Thankyou so much mam i hope ill do it let ne thankyou once again after chem exam

[@shantagangolli5408]

Tq so much mam ♥️♥️♥️♥️

[@Priyanka_Raj792]

Mam hw answer is 405KJ

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Thank you so much mama ❤❤❤

[@samarthhegde7922]

❤❤Thank you mam❤❤

[@PreethiPreethi-zb1dj]

Tq ma'am it wass soo osm explanation plss give us MCQ and other chapters numericals as soon ass ❤😊

[@deepashetty8666]

It was good mam❤

[@chethannnaik]

Thank you, thank you, thank you, thank you, thank you, thank you, thank you, thank you, thank you somuch ma'am❤️🙌🏼🙌🏼

[@aishanirk1692]

15:39 answer is 15.07

[@PreePreethi]

Tqsm mam❤

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Thank you mam

[@kotieshsn4312]

Thank you mam nange numaricals very difficult antha anista ittu but now i am full happy. Because we can solve 2 numaricals ❤️❤️❤️❤️❤️❤️tq mam.. Love u mam💝

[@irp620]

tq soo much mam😍❤

[@ArunKumar-ou7hw]

log value calculated simple 13 time √n,-1×3558 ex.log 2value.
13time√2-1×3558=0.301
Without using santific calculator

[@Crystalite-gt2om]

Awesome dude thank you so much

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[@sharadjorapur6218]

29:05 , ans =405.3kJ

[@adarshkiresur1427]

Divide cathode /anode /anode =apply√13 times -1=×3558 we find log

[@ShivarajUdagatti]

Thank you mam love you ❤

[@CharulathaDN]

Thank u mam wt the numerials u hav thought us they hv asked the exact question

[@rajashrikulkarni9695]

Mam, how we got to know that nickel tranfer 2 electrons?

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Tqsm mam🙏🏼

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Love you mam Thank you ❤

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#best chemistry mam

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Tnk uh smh mam❤....

[@pranavbhattravelshorts1022]

Mam Please Provide All Chapter MCQ In One Shot ....

[@sLatha-dp]

Mam pls do videos on how to calculate log and antilog values if can rp sir must b done dis video

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Mam superb exaplan

[@user-qk2uu8io8k]

Mam HW ans is _405.245 kJ

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Tqsm❤❤❤❤....

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Love u so much mam 💞

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Tq,mam❤

[@hanamantbiranagaddi974]

Log value id 3.60

[@lakshmicr9738]

Tq mam♥

[@sumukh04]

Mam how to find antilog in during exam

[@samarthnaik9936]

good evening mam, ans is -405kJ

[@manojkumarv4863]

Negative sign should not be considerd right so only 405.2454KJ

[@Vi_zard69]

When I searched in net negative sign is usually considered....idk which to be followed rn

[@samarthnaik9936]

@@manojkumarv4863 isn't gibbs energy exothermic? all spontaneous reactions have negative gibbs energy... iDK bruh i guess mam must clarify this issue

[@manojkumarv4863]

@@samarthnaik9936 Hmm then we will write both answers in exam let them take which one they need 😅

[@adarshpachhapure8988]

Tq Mam ❤💛