Integral from 0 to 1 of arctanx/(1+x)

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  • Опубликовано: 7 сен 2024

Комментарии • 4

  • @holyshit922
    @holyshit922 Месяц назад

    Integration by parts with
    u = arctan(x) , dv = 1/(x+1)dx
    Substitution u = (1-x)/(1+x)

  • @newmantwine1224
    @newmantwine1224 Месяц назад

    I think you can make these videos shorter and better if you combine some of the obvious steps. But good video otherwise.

  • @alexkaralekas4060
    @alexkaralekas4060 18 дней назад

    Or just do x=(1-t)/(1+t) just like cipher did and solve it in 3 minutes

    • @mathemagicalpi
      @mathemagicalpi  18 дней назад

      Sure, but there's always multiple ways to approach things and not just one.