Deflection of Trusses Virtual Work Method

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  • Опубликовано: 24 янв 2025

Комментарии • 34

  • @reza1001us
    @reza1001us 7 месяцев назад +2

    It was a good and complete example. Thank you.

  • @qashafi2754
    @qashafi2754 3 года назад +2

    Nice presentation. Explained and solved in a very simple way. Thank you very much

    • @nadimshbeeb417
      @nadimshbeeb417  3 года назад +1

      You're welcome. And thanks for the feedback

  • @tayoojumiri8820
    @tayoojumiri8820 2 месяца назад

    I understand very much better now, Thank you❤

  • @jaimechavez9466
    @jaimechavez9466 2 года назад +1

    where does the 4.5 come from? i am assuming he is using pythagoram theorm which will be square root of 2.25^2 + 3.5^2 which equals to 4.16 rather than 4.5, right?

  • @francesloveend.galang4463
    @francesloveend.galang4463 3 года назад +1

    Where does 1.36 came from? Timestamp (10:12)

    • @nadimshbeeb417
      @nadimshbeeb417  3 года назад +1

      It should be 1.2 not 1.36

    • @francesloveend.galang4463
      @francesloveend.galang4463 3 года назад

      @@nadimshbeeb417 thank you sir! May I ask sir, what if I also have a given settlement. I want to find vertical displacement due to settlement and fabrication error. What formula should I use sir? 😊

    • @nadimshbeeb417
      @nadimshbeeb417  3 года назад

      In that case you would multiply the reaction due to the virtual system with the actual settlement value at that reaction (support) and add or subtract depending on direction to the required displacement and equate to zero since there is no internal work

    • @francesloveend.galang4463
      @francesloveend.galang4463 3 года назад

      @@nadimshbeeb417
      Sir can you check?
      Problem is: AB and and BD are fabricated 3/4 in too long and support D settles 0.25 in.
      Reaction of Support D in virtual system: 1/2 kips
      Settlement at D: 0.25 in
      Fv of AB = (-5/8) kips
      Fv of BD = (-5/8) kips
      Fabrication error = 3/4 in
      Solution for vertical displacement due to settlement and fabrication error:
      (1/2 kips)(0.25 in) + (-5/8 kips)(3/4 in)(2 members) = - 0.8125 in.
      I wonder if I got it right. Thank you so much sir! ❤️

    • @nadimshbeeb417
      @nadimshbeeb417  3 года назад

      As an equation it looks good but I have no sense for the direction.

  • @Corrected254
    @Corrected254 17 дней назад

    I thought we only work with the imaginary unit load at the joint in question

  • @Senamile_Mphandle
    @Senamile_Mphandle Год назад

    Is A a pin or roller?

  • @Mohamed-ef5zw
    @Mohamed-ef5zw 2 года назад

    How can I check if this deflection is acceptable or not?

    • @nadimshbeeb417
      @nadimshbeeb417  2 года назад

      It depends on the design codes.

    • @Mohamed-ef5zw
      @Mohamed-ef5zw 2 года назад

      @@nadimshbeeb417 what is the deflection limit for truss in Euro Code?

    • @nadimshbeeb417
      @nadimshbeeb417  2 года назад

      www.newsteelconstruction.com/wp/eurocode-design-factors-and-limits/

  • @danz02TB
    @danz02TB Год назад

    how did you get -0.59KN

    • @nadimshbeeb417
      @nadimshbeeb417  Год назад

      =-0.5/sin(57.26)

    • @ntonyjaime_
      @ntonyjaime_ Год назад

      ​@@nadimshbeeb417hi,where did the values for n come from

  • @kwakuboateng2068
    @kwakuboateng2068 2 года назад +1

    I don't understand how he got the 57.26°

    • @Zii3zoz
      @Zii3zoz 2 года назад +1

      I pretty sure instead of 2.5 its 2.25 so it will be tan -¹= 3.5/2.25 = 57.26

    • @jaimechavez9466
      @jaimechavez9466 2 года назад

      @@Zii3zoz where does the 4.5 come from? i am assuming he is using pythagoram theorm which will be square root of 2.25^2 + 3.5^2 which equals to 4.16 rather than 4.5, right?

    • @nadimshbeeb417
      @nadimshbeeb417  2 года назад +1

      You're right it is 2.25 not 2.5

    • @nadimshbeeb417
      @nadimshbeeb417  2 года назад

      Members AE, EB and CD are 4.5 (2.25+2.25). The rest are 4.16 (rounded to 4.2)

    • @ricardoarturolaraperaza9988
      @ricardoarturolaraperaza9988 2 года назад

      @@Zii3zoz EXACTLY

  • @ntonyjaime_
    @ntonyjaime_ Год назад

    How did you get n

    • @nadimshbeeb417
      @nadimshbeeb417  Год назад +1

      Slide 6

    • @ntonyjaime_
      @ntonyjaime_ Год назад

      ​@@nadimshbeeb417oh so like n,are the forces found in the virtual system? And I have one more question, assuming the forces pointing down are horizontal instead how would you represent that in the virtual system

    • @nadimshbeeb417
      @nadimshbeeb417  Год назад

      Yes, they are the virtual system. Regarding your second question, the virtual system is the system where you want your displacement. If you've noticed, I used the same virtual system to answer all questions. If you change the original loading and still want to find the vertical displacement at E, you can use the same virtual system.