GIVEN THE FOLLOWING DISCRETE PROBABILITY DISTRIBUTION FIND OUT THE EXPECTED VALUE AND VARIANCE OF X?

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SOLUTION EXPLANATION:
TO CALUCULATE MEAN(OR)EXPECTED VALUE:
mean=expected value=E(x)
=summation x=0 to n (x)(p(x))
NEXT WE SUBSTITUTE VALUES AND SIMPLY IT THEN E(x)=2
TO CALUCULATE VARIANCE(x):
variance(x)=expection of x square - expection of x whole square.
var(x)=E(x)^2 - (E(x))^2
= summation x=0 to n (x^2)(p(x))
NEXT WE SUBSTITUTE VALUES AND SIMPLY IT
VAR(x)=1.2
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