thank you! have a science exam in a few days lol, i completely forgot about ohms law so here i turn! slight suggestion though is just mention when you rounded something off because i try to solve it first then compare our answers. i thought i was wrong lol anyways, thanks!
voltage= current(amps) x resistance(ohms) so if I need a 6 ohm 12v led to work and I have a 20 volt input at 4 amps so input would be 20 v/4 A= 5 ohms led I used the amperage of the input to find out the resistance to run it 20v /6ohms = 3.333 amps needed? so I need to decrease the amperage to run the 12v 6 ohm led, because if I rework it 12v/6ohm requires 2 amps to run, so If I take the 20v / 2 amps = 10 ohms needed? Might be completely wrong
I need help with this question The seal of a patch clamp pipette is very important. The resistance of the seal determine how much leak current you will have. This leak current becomes noise when you want to record the current of single ion channels with the pipette. Assume you have an ion channel that allows a current of 2 pA to flow through the current. What is the minimum seal of the patch to half a signal-to-noise ratio of 2. Assume that the pipette is 5 mV depolarized with respect to the outside batch. the answer is 10 GigaOhms but I need to know how that was solved
What would happen if a wire having no resistance at all (0 Ω) were connected directly across the terminals of a 6-volt battery? How much current would result, according to Ohm’s Law?
i took electronics in school years ago and dont ouite remember but i have a battery charger that puts out 24 volts and i want to drop the voltage down to 6 volts, so i decided to use ohms lawso that would mean v/i =r v=24v/1000ma=the resisance
I teach in physics in a high school. My background is in chemistry. These Ohm's law problems are genuinely helpful.
Great that you found them helpful. Send me your email address and I can send you the assignment sheets I have as .pdf files.
Thank you s much! I'm in 8th grade and I'm having a hard time understanding my modules, an this helped me a lot!😊
Are you from mdps
This gave me a genuine better understanding of ohms basics. Thank you very much!!
Glad it was helpful!
Thank you! I have my science lab exam today, and it's on Ohm's law. Helped me out a lot :)
Great, hope the lab exam goes well.
I was trying to get an explanation on ohm's law and how to use it your guidance has made me understand it much better
Glad to hear that. Thanks for your comment.
I’m 23 now learning this, big help bro Thankyou !
Glad to hear it!
You are better teacher then my teacher
👍 easy to understand
Thanks for the vote of confidence. I love being a teacher.
thanks a lot! i havent listened to the discussion of my teacher abd this helped understood
Glad that it helped out.
Thank you for making this instructional video!
You bet, happy to do so. Thanks for watching!
Very educative and helpful
Thanks, glad you think so!
Thank you so much, you helping me with my physic class and MCAT prep
Happy to help! You're very welcome.
thank you! have a science exam in a few days lol, i completely forgot about ohms law so here i turn! slight suggestion though is just mention when you rounded something off because i try to solve it first then compare our answers. i thought i was wrong lol
anyways, thanks!
You're welcome and thanks for the tips!
Thanks for the great explaining of the ohms law.
You're welcome, glad it was helpful.
thank you very muuchh this made answering modules easierrr!!
That's great. Glad it helped!
Thanks your questions were helpful to me🙏
I have my exam today
Glad it was helpful and I hope your exam went well!
Thank you for the tips💚 EFFECTIVE
You're welcome, glad it was helpful
voltage= current(amps) x resistance(ohms)
so if I need a 6 ohm 12v led to work and I have a 20 volt input at 4 amps
so input would be 20 v/4 A= 5 ohms
led I used the amperage of the input to find out the resistance to run it 20v /6ohms = 3.333 amps needed? so I need to decrease the amperage to run the 12v 6 ohm led, because if I rework it 12v/6ohm requires 2 amps to run, so If I take the 20v / 2 amps = 10 ohms needed? Might be completely wrong
Very helpful Thanks mate
Glad it helped!
Thank you,
I am seeking knowledge about ohms law in reference to audio amplifier and speakers.
I do not have videos for that.
Thank you so much 😊 Your a Life saver
You're so welcome!
Nice to learn from you dude.
Glad to hear it!
Thank you for sharing your idea
My pleasure!
@@stepbystepscience its a big help for my studies💜 specially this online class
Well explained thank you, this will help me greatly
Glad to hear it!
Very helpful !!
Glad to hear it, thanks!
Thank you for this video, it has been a huge help to me to understand solving ohm’s law problems!
Glad it was helpful! Thanks for the comment.
How do I start from the beginning of this series on electricity?
Here is the link to the playlist.
ruclips.net/p/PLcJ1NYursFxiRnjN28UEf_18zaVO9ub2B
Thanks for this video
You're most welcome
Thank u man u have wisdom
Thanks and best wishes to you
Thank you!
You bet!
amazing man, keep it up
Thanks, will do!
Great video
Thanks, glad you liked it!
Thank you sir for these amazing questions that u gave us for practice.
And I have enjoyed these questions when I solving them 🥰🥰👍👍 ;)
It's my pleasure and thanks for the comment.
@@stepbystepscience ✌👍👍
Just found your channel. I’m trying to build a 24V with 7S 18650 batteries.
That lip smack in the beginning 😂😂😂😂
Thanks
I wanted to know about the problems which have to be solved with the formula of “ R = p .l/a
Thx for the the help
You bet, and thanks for watching!
Video is but standard of questions should increase for next time
Increase like how?
@@stepbystepscience increasing level of questions
Thank you so much!i like it 👌😊
You're welcome 😊, glad you like it!
Thank you sooooo much 💖
You’re welcome, thanks for watching
Fantastic - Thank you!
You are very welcome!
I like the way you explain thank you!
Helpful 💖
Glad it was helpful!
Thanks man
You bet!
i finally learned something about ohms law cuz i dint listen in class cuz i just slept and a day later i got 15/15 😊👍
👍 Great.
Lets hope you find a good video on English as well
@@alzeNL lol ye
thank you so much I was about to fail ninth grade
You're welcome, you can do this!
I need help with this question The seal of a patch clamp pipette is very important. The resistance of the seal determine how much leak current you will have. This leak current becomes noise when you want to record the current of single ion channels with the pipette. Assume you have an ion channel that allows a current of 2 pA to flow through the current. What is the minimum seal of the patch to half a signal-to-noise ratio of 2. Assume that the pipette is 5 mV depolarized with respect to the outside batch.
the answer is 10 GigaOhms but I need to know how that was solved
I am in grade 7 and you realy helped me bra thanks😀😁🙂😮🤓
Happy to help!
You are amazinggggg❤️thank you so much
Thanks to you for the nice comment.
I didn’t understand example 5 can you help me please? Why did you put 10-3 V?
Because the current is given in mA (milliamperes) and milli is 10 raised to the power of -3.
Thank you , it was helpful :)
Glad it helped! Thanks for the comment.
Thnxxxx bro
Love dis video tanx a lot
Who come in this video because they can't understand the ohms law
good job reaching 100k
Thanks! 😃
What would happen if a wire having no resistance at all (0 Ω) were connected directly across the terminals of a 6-volt battery? How much current would result, according to Ohm’s Law?
There would be an infinite current and the wire would eventually melt
Helloooo I need this so muchhhhh 😭
Hope it helps. Thanks for watching!
Thank you sir 👍👍👍
tnx for this video I have a knowledge like wise...
Great and thanks for the comment.
You are amazing
Very nice of you to say so.
Thanks for tips
You are very welcome!
Thanks for this! I subscribe keep it uppp!
Will do. Thanks for watching!
Thank you.....
You are very welcome!
Thank I learned from the video💬
Very nice
Thanks
I don't really gethow you get volts
Sir 2 nd answer of question is R=18.4 ohm
Does this really need to be round offed?btw ThanKs.
Thanks
How abt this formula? i=v÷r
That is correct, ohms law solved for current.
POV:your answering your school works and u don’t know how so you go here
Thnq ♥️
Genios
thanks
i took electronics in school years ago and dont ouite remember but i have a battery charger that puts out 24 volts and i want to drop the voltage down to 6 volts, so i decided to use ohms lawso that would mean v/i =r v=24v/1000ma=the resisance
THIS YES
Thanks!
Niceeeeeeeee
Thank you!!
Hi from PHY-252 :D
Shantanu Hello from Berlin, Germany, where is PHY-252?
@@stepbystepscience I am in College in Boston, US. My professor us asked to see this video! The name of my class is PHY-252
Great, tell your professor I said hello and thank you.
3rd week 101 class here so sorry if dumb question. But 1st one is .35/750 comes out to 262.5..do we automatically round up to 263?
I you want to round to three significant figure then yes.
I'm a grade 12 student and I still suck in this🤦♀️
Keep trying, and I hope the videos help!
Sir 1st question answer is 262.5 Or any other
i though current was magic
subscribe BTW.
Fantastic!
Hi buddy what's dood man
Please give heart ❤
Repent and forsake sins Jesus is coming accept Jesus now
OK, thanks for the reminder.
nice joke in remembering the formula😂
Thanks!
Your language is not understanding please improve it😵😵😵
👎👎👎👎
Maybe you should learn to speak English before criticizing others.
Thank you s much! I'm in 8th grade and I'm having a hard time understanding my modules, an this helped me a lot!😊
That's great to hear. Glad it was helpful!
I'm grade 7
@@koro3259 same, that you so much for helping me understand