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What would be the work done by friction?
You would have to go back with the mu value we found, and Wf=-(mu)*n*s=-(mu)*mgcos(theta)*(1.2/sin(theta))
What would be the work done by friction?
You would have to go back with the mu value we found, and Wf=-(mu)*n*s=-(mu)*mgcos(theta)*(1.2/sin(theta))