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3. Binary Division method (Restoring and Non-restoring Division Algorithm)

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  • Опубликовано: 24 фев 2018
  • Binary Division method (Restoring and Non-restoring Division Algorithm) | Binary division | restoring division algorithm | non restoring division algorithm | #coa | #Restoring

Комментарии • 173

  • @marvichadap8338
    @marvichadap8338 2 года назад +22

    Thank you so much mister, my teacher taught this and i didnt understand anything. Its because of people like you that makes things easier and as a fellow indian, i would like to wish you success and hope the world recognises your talent someday.

  • @srushti1258
    @srushti1258 4 года назад +75

    Honestly you are the ones who should be honoured in ytff. We get to learn what we really need to!!
    Thanks a lot!🙏🏻

  • @sakshirajput8828
    @sakshirajput8828 4 года назад +188

    Wht abt non restoring method.. If it was nt to be taught in this video then why the name is included..??

  • @rafaelangelopiad8919
    @rafaelangelopiad8919 3 года назад +50

    bro no words can express how helpful this is, thank you bro

    • @simonriley8696
      @simonriley8696 3 года назад +7

      You just described it with words.

    • @rafaelangelopiad8919
      @rafaelangelopiad8919 3 года назад +3

      @@simonriley8696 HAHAHAHAHAHAHAHAHAHAHAHA OH YEAH

    • @adarsh2004
      @adarsh2004 8 месяцев назад

      hahahahahahahahahhahahahahahahahahahahahahahahahah oh yeah@@rafaelangelopiad8919

  • @HGCS_ASHWINIMD
    @HGCS_ASHWINIMD 3 года назад +4

    Excellent teaching sir....it's very easy to understand everyone... Becz of... u teaching the way is very simplest..it's too much good sir..tqsm

  • @pranavchauhan3549
    @pranavchauhan3549 3 года назад +3

    Very much needed bro...i cannot found this method anywhere on internet...🤘

  • @aditichatterjee3353
    @aditichatterjee3353 3 года назад +6

    Thanks a lot bhaiyya!!!... I wasn't able to solve these questions earlier, this tutorial has clarified all my doubts on the topic, thank you😊

  • @MasterMindmars
    @MasterMindmars 4 года назад +9

    P E R F E C T
    Amazing method to divide with a simple algorithm and resulting directly the quotient and the rest.
    Thank you

  • @manishswami7512
    @manishswami7512 3 года назад +7

    For anyone wondering it is 10 / 3 instead of 9 / 3

  • @nikhilgiripunje2663
    @nikhilgiripunje2663 Год назад +3

    First i was a little bit confused but after watching his video I'm now more confused

  • @saravanann9709
    @saravanann9709 Год назад +1

    Thank you very much sir ... tomorrow i have exam...i understood clearly thanks a lot 🎉

  • @itsoknottobeok9381
    @itsoknottobeok9381 Год назад +2

    If video is about restoring algorithm then remove (Restoring and non restoring algorithm) the title!

  • @_PremKharat
    @_PremKharat 2 года назад +5

    I was searching for such simple explanation and finally came across the video
    Thank you sir🤩🤩🤩

  • @vikhyaths1369
    @vikhyaths1369 6 лет назад +6

    Thank you so much for clearing the concept✌️

  • @harshaneelam
    @harshaneelam Год назад +1

    Good Explanation For Morning Exam

  • @arshadshaikh5482
    @arshadshaikh5482 Год назад +3

    Very nice explanation sir ,next time please cover whole page☺️

  • @bssumanth5427
    @bssumanth5427 3 года назад +2

    Thank you so much sir ur teaching way really awesome concept cleared

  • @rutujabalak9310
    @rutujabalak9310 6 лет назад +5

    I like it and I also understand it .Thank you

  • @nishtha9666
    @nishtha9666 2 года назад +4

    Very well explained 👍👍Please divide 67÷14 using division algorithm....

  • @samsunighar8134
    @samsunighar8134 3 года назад +1

    Hats off bro. Superb and good explanation

  • @Watchfuse
    @Watchfuse 3 месяца назад

    great explanation , keep it up.

  • @unmeshmandal3071
    @unmeshmandal3071 2 года назад +2

    If the numbers are represented in signed 2's complement method then how 1010 becomes decimal 10.

  • @maziarghorbani
    @maziarghorbani 5 лет назад +3

    Thank you for the great explanation.

  • @OldSloGuy
    @OldSloGuy Год назад +2

    This algorithm is actually a special case. NOTE the sign bit of the divisor being zero in this example. The generalized division algorithm does not require this but generates TWO carry bits. Processors do not handle a second carry bit, but it can be emulated by implementing a flip-flop in software. Yes, that requires the use of a goto operation which is spaghetti code. When it comes to division, goto is not harmful. A benefit of this is an extra bit of precision which allows correct rounding when the unsigned quotient is restored to a signed integer. While that is simple in assembly language, it results in complicated logic in many high level languages. Unsigned scaled integer division is usually ignored for this reason. The reader should understand what is being avoided in this video and why the extra zero in the divisor is so important. Omit that and the algorithm will work most of the time, and depending on the inputs, may occur so infrequently as to avoid detection during testing. The generalized version is never used in life safety software because it is so poorly understood by most programmers. Just because you understand it doesn't mean someone in the future won't clean up the code because they don't comprehend the reason it exists.

  • @kishoreshetty7338
    @kishoreshetty7338 2 года назад +4

    Thank you sir ,please provide a clearer image of the flow chart in the description it really helps us a lot!

  • @rx5194
    @rx5194 Год назад +1

    But at last step counter value is 1 then there will another step know as it is not zero

  • @157_anweshasahoo7
    @157_anweshasahoo7 2 года назад +1

    Thank you so much sir for make this video

  • @prakashbharati6707
    @prakashbharati6707 5 лет назад +2

    thanks it helps me to understand in better way

  • @adarsh2004
    @adarsh2004 8 месяцев назад

    very nice

  • @vishnusandeep4548
    @vishnusandeep4548 Год назад +1

    Did'nt restore in 3rd cycle??

  • @rakshitsingh9690
    @rakshitsingh9690 2 года назад +1

    Thank you so much for this video

  • @harshsha0562
    @harshsha0562 10 месяцев назад +1

    Sir Hindi m hi Vdo bnaya kare thodi problem hoti hai samajne m😢😢

  • @afrozr9191
    @afrozr9191 2 года назад +1

    In last step 00001 remainder in my reader ?

  • @manofsteel6173
    @manofsteel6173 Год назад +1

    Helpfull❤️

  • @---MDEEKSHA
    @---MDEEKSHA 3 года назад +3

    Explained very well

  • @muskansao1317
    @muskansao1317 3 года назад +1

    Got my doubts clear ty sir

  • @THE_WAY_FORWARD
    @THE_WAY_FORWARD 3 месяца назад

    Sir I have a question, when setiing Qo to 0, then after that why not doing A= A+M

  • @icemans1matedude339
    @icemans1matedude339 8 месяцев назад

    Im assuming that A always has one more digits place than Q to account for sign bit and 2’s complement

  • @Menkamohbekar
    @Menkamohbekar Месяц назад

    Why we add agr hume subtract krna tha t??

  • @TheBhadhu
    @TheBhadhu 6 лет назад +1

    Thank you so much . Great video btw :)

  • @deveeshn1192
    @deveeshn1192 11 месяцев назад

    thank u for saving my life sir😘😘

  • @sowmyakarra9413
    @sowmyakarra9413 2 года назад +1

    Thank you so much sir😊

  • @Arjun-px3gx
    @Arjun-px3gx 4 года назад +2

    Thanks for this informative video...I have only one suggestion:the flow chart is not visible while you were explaining the procedure of getting answer....other than that it is good.. thank you very much🤝👍

  • @shivarammuthukumaraswamy7164
    @shivarammuthukumaraswamy7164 5 лет назад +3

    thank you so much sir...

  • @trinhcuong9188
    @trinhcuong9188 5 лет назад +6

    I do not understand why does A have 5 bits whereas Q has only 4 bits. Could you explain it for me? Thank you so much!

  • @samanvithachidella2485
    @samanvithachidella2485 5 лет назад +3

    Why u didnt restored in 3rd cycle and last cycle..???

    • @srushti1258
      @srushti1258 4 года назад

      Samanvitha Chidella Restoring A was not needed because we got a positive number(starting with zero).

    • @samanvithachidella2485
      @samanvithachidella2485 4 года назад +1

      Yes... I later understood.... But i have forget to delete that comment

  • @societystalker47yearsago65
    @societystalker47yearsago65 2 года назад +1

    Thank you sir

  • @logarathinam1782
    @logarathinam1782 6 лет назад +3

    Is this possible only for the unsigned values?? Is there any method for signed??

    • @patryk_49
      @patryk_49 5 лет назад +1

      If sings of the input values are not the same you negate the output value. Thats all.

    • @m0st4fabideer14
      @m0st4fabideer14 3 года назад

      You save the signs of the operands before the operation to determine the sign of the quotient, and then set their most significant bits to 0 (so that it doesn't affect the actual division), after the division is finished, you set the sign of the quotient (XOR the MSbs of the operands), the sign of the remainder is the always the same as the sign of the dividend.

  • @elvindsa6283
    @elvindsa6283 2 года назад +1

    Perfect ❤️❣️

  • @sakshirajput8828
    @sakshirajput8828 4 года назад +1

    Btw it cleared concept regarding restoring method

  • @techworld2052
    @techworld2052 2 года назад

    Bro place your camera little bit up , we wre not able to see the lower part of block diagram clearly ..

  • @harling9835
    @harling9835 4 года назад

    How to convert the remainder to the fornat bbb.bbb where b is binary numbers?

  • @shushrutgahane6551
    @shushrutgahane6551 Год назад +1

    Thanku so much

  • @shubhamaynandi6068
    @shubhamaynandi6068 6 месяцев назад

    sir aapka video toh bas black lover students hi dekhte honge 😷

  • @arpitbhaliya2972
    @arpitbhaliya2972 29 дней назад

    Thanks sir ❤

  • @tadepu-raghavendra
    @tadepu-raghavendra 3 года назад +1

    In 3rd cycle why not restore pls explain

  • @DarkWebCode
    @DarkWebCode 5 лет назад +1

    Thank you so much bro

  • @muslimwaqar
    @muslimwaqar 4 года назад

    thanks bro good explanation

  • @maddyabdullah6340
    @maddyabdullah6340 4 года назад

    is it possible complete division in this question... -15 divide by +5 ??? please if u could solve it.. i did and in last i did set it but i had to restore because it was 0 remainder please help?

  • @sailajapalukuru7493
    @sailajapalukuru7493 2 года назад +1

    I like you sir

  • @devagabond6926
    @devagabond6926 3 года назад +2

    complimenttt...

  • @vinayjadhav3502
    @vinayjadhav3502 2 года назад

    how to solve this if the dividend is negative?

  • @vinayak186f3
    @vinayak186f3 3 года назад +1

    Exam offline hota to pakka ye aata 5 marks me ab to mcq de rhe hai 😓

  • @govindprajapati5524
    @govindprajapati5524 5 лет назад +2

    thanks so much bhaiiiii

  • @swopnilmaharjan8630
    @swopnilmaharjan8630 10 месяцев назад

    shouldn't the bit size of A = Q?

  • @ujjwalsinha1237
    @ujjwalsinha1237 5 лет назад +1

    How are you doing the count operation? I mean to say by referring which thing you did the count operation?

    • @ujjwalsinha1237
      @ujjwalsinha1237 5 лет назад +2

      Is this operation based on the number of bits present in the dividend?? I think that's why you are counting 4 cycles for complete this process.🤔

    • @MrBabaaldar
      @MrBabaaldar  5 лет назад

      @@ujjwalsinha1237 Yes You are right.

    • @starkendeavours7072
      @starkendeavours7072 2 года назад +1

      @@ujjwalsinha1237 What if Dividend is a -ve integer? Will it Count 5 Cycles then?

    • @techvishnuyt
      @techvishnuyt Год назад +3

      @@starkendeavours7072 if the dividend is a negative integer, we need to convert it to its two's complement representation and perform the algorithm as usual. The number of cycles required will be the same as for a positive dividend, but sign extension will be required at the end to obtain the correct sign for the quotient.

  • @AbhishekKumar-my8sp
    @AbhishekKumar-my8sp 6 месяцев назад

    Thanks a lot!🙏🏻

  • @rudrasama297
    @rudrasama297 3 года назад +1

    But reminder should be 00000 why we are getting 00001 ? According to Decimal system 3 is totally dividing 9 leaving reminder as 0.

  • @fujoshiarmygrl8377
    @fujoshiarmygrl8377 2 года назад +1

    Thank u 💓

  • @kamyagupta4030
    @kamyagupta4030 Год назад

    Thank you so much 🙏

  • @chanu2400
    @chanu2400 5 месяцев назад

    Thank you sir!

  • @3dy97
    @3dy97 6 лет назад +1

    Thank you!

  • @itspurelypassionate
    @itspurelypassionate 3 года назад +1

    Thanks!

  • @cutecreatures167
    @cutecreatures167 5 лет назад

    Super teaching

  • @user-hy8wj3xq4u
    @user-hy8wj3xq4u 9 месяцев назад

    Thanks Sir 🙏🏻

  • @BTS-in6xc
    @BTS-in6xc 11 месяцев назад

    Sir please Hindi ma video bano
    I know your English is very good

  • @omarma2617
    @omarma2617 5 лет назад

    Thank you very much

  • @raj12030
    @raj12030 Год назад +1

    If there is A-B why he does A+B? Someone explain

    • @xteez6051
      @xteez6051 3 месяца назад

      Because he found the 2s complement which is basically -B so A+(-B)

  • @kaustubh1871
    @kaustubh1871 3 года назад

    after we shift and subtract.... if we get a carry do we discard or keep it??

    • @itv5610
      @itv5610 2 года назад +1

      discard

  • @shivsuthar9759
    @shivsuthar9759 2 года назад +1

    Respect++

  • @shubhamhelloworld321
    @shubhamhelloworld321 3 года назад +1

    Sir puri screenc toh dikhao nhin toh mt padhao

  • @lunavathsainaik4443
    @lunavathsainaik4443 Год назад

    Sir I have a dought at 4th cycle ,why should we stopped at 4th cycle !

  • @kunalsrivastav2913
    @kunalsrivastav2913 3 года назад

    can somebody tell me how to identify if a given binary bit is +ve or -ve? i know what is sign bit, still how can i differentiate between any randomly given binary number and know?

    • @aditichatterjee3353
      @aditichatterjee3353 3 года назад

      If the first bit of the said binary number is 1 it is a negative number, and if it's 0 then it's a positive number.

  • @shashankshankar4021
    @shashankshankar4021 6 лет назад +1

    Thank you ;)

  • @betavenomlite6379
    @betavenomlite6379 2 года назад +1

    Tq sir

  • @LUCIFER-uv3dt
    @LUCIFER-uv3dt 11 месяцев назад

    Hats off

  • @yugendharsai
    @yugendharsai 5 лет назад

    Nice

  • @abhishekpoudel1902
    @abhishekpoudel1902 5 месяцев назад

    Please solve -7/3

  • @suhaspp8885
    @suhaspp8885 2 года назад

    Can u do binary division for 273/15

  • @sandeepswami7156
    @sandeepswami7156 6 месяцев назад

    Bhai subtraction bol ke addition kyu Kiya

  • @awarenessentertainment5252
    @awarenessentertainment5252 Год назад

    Good 👍😂👍😂👍😂👍😂👍😂👍😊😊👍

  • @NCCSSandhyaN
    @NCCSSandhyaN 2 года назад

    Sir can u help me for another example . Dividend=1010, divisor=0100 . Plzz

  • @sayantandas7054
    @sayantandas7054 5 лет назад +1

    Y u haven't restore on 3rd cycle

  • @mytrollscollection9375
    @mytrollscollection9375 Год назад

    sorry bro i did not understand your direct steps and i had saw your 1 and 2 videos also

  • @user-ey2ye1sh6s
    @user-ey2ye1sh6s Год назад

    R.I.P Audio

  • @user-qf8fb1yx6t
    @user-qf8fb1yx6t 6 лет назад

    Thanku sir

  • @laudarikailash9244
    @laudarikailash9244 6 лет назад

    How to perform restoring and non restoring division for the following
    11/4
    17/8

    • @MrBabaaldar
      @MrBabaaldar  6 лет назад +2

      Dividend =11 =1011= Q
      Divisor= 4=00100 =B

    • @laudarikailash9244
      @laudarikailash9244 6 лет назад

      If u don't mine can u solve an send me no need to send algorithm only process

    • @MrBabaaldar
      @MrBabaaldar  6 лет назад +4

      I m out of station...I will solve it as early as possible and send u.

  • @shrutisamal
    @shrutisamal 6 лет назад +2

    how to divide 9/9?

  • @natureisbeautiful4486
    @natureisbeautiful4486 3 года назад +1

    tnx

  • @vishalmishra1937
    @vishalmishra1937 6 лет назад +2

    non restoring hai hi nhi

    • @MrBabaaldar
      @MrBabaaldar  6 лет назад

      ruclips.net/video/zVestoCRRbM/видео.html